eps 300

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Exponential investment-investment with clear rules and clear positions

clear rules and clear positions, or a combination of open options. Stock selection methods and weights are clearly determined. Exponential investment is full. It determines the three essential aspects of a portfolio, including the configuration of major asset categories, stock configurations, that is, positions, stock types, and individual stock weights. Or in the future, there will actually be similar foreign products that control stock positions based on a certain indicator.Investment with cl

MySQL 5.7 JSON support

MySQL 5.7 JSON support Recently, a business needs to store Json and perform some simple business logic processing. I have found that it is difficult to use mysql 5.6 for json data analysis. It is very difficult to simply store data. I have no way to ask.I first thought of mongodb, and second thought of mysql 5.7. Then, check it out. Oh, it's GA. As we all know, mongodb's engine layer stability has been a short board, while innodb has been very stable after 10 years of verification. So I was wond

Be alert for attacks with CVE-2015-2545 Vulnerabilities

Be alert for attacks with CVE-2015-2545 VulnerabilitiesPreface Recently, APT Warning Platform captured an attack sample, after analysis, the sample seems to use CVE-2015-2545 for attacks, and has a high level of attacks.Analysis This sample is constructed by a User-After-Free vulnerability in the Encapsulated PostScript (EPS) filter module (EPSIMP32.FLT in 32bit. The causes and utilization of vulnerabilities are as follows:When processing the copy op

Codeforces Round #303 (Div. 2)

Codeforces Round #303 (Div. 2) A. Simple question /*************************************** * *********************************> File Name: a. cpp> Author: ALex> Mail: zchao1995@gmail.com> Created Time: wednesday ******************************** **************************************** /# include # Include # Include # Include # Include # Include # Include # Include # Include

UVA 11123-counting trapizoid (tolerance + geometry)

,DoubleL =0) { This->k = k; This->c = C; This->l = l; }friend BOOL operatorConstline A,Constline b) {returnA.K structState {DoubleC, L; State (DoubleCDoubleL) { This->c = C; This->l = l; }};intNDoubleX[n], y[n]; vector Set; vectorGinline DoubleDistant (DoubleXiDoubleYi) {returnXi * xi + yi * yi;}inline DoubleCal (intAintb) {if(X[a] = = X[b])returnX[a];returnY[a]-X[a] * ((Y[a]-y[b])/(X[a]-x[b]));}inline intCintA) {if(A 1)return 0;returnA * (A-1) /2;}inline BOOLCmpC (Conststate A,Conststate b) {if

First day of internship in Suzhou, first day of internship in Suzhou

location, went to the environment, and ran a sample in, draw a line or something. 0x03 The WY senior spoke about coding standards and collaborative development. For some developers, I feel that this is important at 01:10. WY started to learn programming in the second day. Think about yourself. I have never touched on programming languages in the second day. ① Alignment related ② Indent ③ The curly braces behind if are written in another line. ④ Variable alignment ⑤ Blank lines: Role of separati

A Round Peg in a Ground hole-poj 1584 (judging convex polygons & judging points within polygons & judging circles within polygons)

DoubleOO = 1e10+7;structpoint{Doublex, y; Point (Doublex=0,Doubley=0): X (x), Y (y) {} pointoperator- (ConstPoint tmp)Const{ returnPoint (x-tmp.x, ytmp.y); } Double operator^(ConstPoint tmp)Const{ returnx*tmp.y-y*tmp.x; } Double operator*(ConstPoint tmp)Const{ returnx*tmp.x + y*tmp.y; }};DoubleDist (Point A, point B) {///the distance between two points returnsqrt (A-B) * (Ab));}intSign (Doublet) { if(T > EPS)return 1;

Image, graphic, picture file format

spaces contain much more color than RGB and CMYK colors for displays and printing devices. PhotoCD images are mostly of very high quality. 13 DXF (. dxf) The Drawing Interchange Format (Drawing eX change Format) is a graphic file format in AutoCAD that stores graphics in ASCII form and is accurate in terms of the size of the graphics Can be edited by large software calls such as CorelDRAW and 3DS. 14 Ufo It is a dedicated image format for the wel

POJ-2728 desert King Optimal Proportional Spanning Tree 01 score planning/parameter search

Given n three-dimensional plane points, each point has a height. The edges must be constructed between each two points. The edges are determined by the Euclidean distance of the X and Y coordinates, the cost of edge is determined by the Z value. How much is the minimum cost ratio in a reasonable spanning tree? Solution: each edge corresponds to a height difference. If the height difference of each edge is set to hi and the distance is Li, a set of edge sets must be found. As always, let's assu

"Digital image processing principle and practice (MATLAB version)" A book Code PART8

= reshape (dark,imsize,1);Imvec = reshape (imagergb,imsize,3);[Jdarkvec, indices] = sort (Jdarkvec);Indices = indices (imsize-numpx+1:end);Atmsum = zeros (1,3);For ind = 1:NUMPXAtmsum = atmsum + Imvec (Indices (IND),:);Endatmospheric = atmsum/numpx;% to solve the transmittance, and choose to retain a certain degree of haze through the Omega parameter to avoid damaging the realismOmega = 0.95;im = zeros (Size (IMAGERGB));For ind = 1:3Im (:,:, Ind) = Imagergb (:,:, Ind)./atmospheric (Ind);EndDark

"POJ3155" Hard Life score plan + min cut

Link:#include int main(){ puts("转载请注明出处[辗转山河弋流歌 by 空灰冰魂]谢谢"); puts("网址:blog.csdn.net/vmurder/article/details/46437961");}ExercisesTitle. Calculate the fractional value first, and then see who else is connected to the source point.Minimum cut map: The original image each point corresponds to a point, the original picture each edge corresponds to a point. Each edge corresponds to a point to each end point, and note that you want one-way edge.This problem card accuracy:So some of the details

Abstract and Virtual in C #

(for details)Interface UsageInterface Usage (instance 1)Using System;Namespace Dage. Interface{// Printer interfacePublic interface IPrint{String returnPrintName ();}}//--------------------------------------------Using System;Using Dage. Interface;Namespace Dage. Print{// HP printerPublic class HP: IPrint{Public string returnPrintName (){Return "this is an HP printer ";}}}//--------------------------------------------Using System;Namespace Dage. Print{// Ep

[JSOI2007] Alloy

the transformation for the Floyd to find the smallest ringall points are to be awarded (possibly Output 1), and all points on the segment (i.e. output 2)1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 structNode8 {9 Doublex, y;Ten}a[501],b[501]; One Doubleeps=1e-8; A intdis[501][501],n,m,inf,ans; -Nodeoperator-(Node U,node v) - { the return(Node) {u.x-v.x,u.y-v.y}; - } - Double operator*(Node U,node v) - { + returnu.x*v.y-v.x*u.y; - } + BOOLSPJ () A{inti,j; at

SQL Worm firewall currently unable to halt virus

Asia's most popular internet rate, the internet rate in the world's first South Korea, in worm_sqlp1434. A fast passenger virus outbreak on the day, the three major telecommunications companies in escrow server received attacks, the network was completely paralyzed, the first working day after the outbreak of the virus, the South Korean High-tech index opened, fell to the lowest point in history. What's more troubling for IT staff is that spending a lot of money on firewalls and other fully func

C Language Programming sixth time job

(a) Correct the wrong questionSequence summation: Enter a positive real number EPS, calculate the sequence portion and 1-1/4 + 1/7-1/10 + ..., the absolute value of the last item is less than the EPS (keep 6 decimal places).Input/Output Sample:Input eps:1e-4s = 0.835699  source program (with the wrong program)#includeError message:Error reason: There is no semico

Neural Network (optimization algorithm)

latter two categories are regarded as the 2nd category), then the data according to the characteristics: petal length and width do classification. Run the following code: #感知器训练结果: a W Iris1 D E P max Eps i repeat{ v Y e Eps[i+1] if (eps[i+1] Print ("Finish:"); Print (w); Break } w i if (I>max) { Print ("Max time Loop"); Print (

Approximate seeking pi

5-10 approximate pi (15 points) The subject requires programming, according to the following formula to find the approximate value of π\piπ, until the last item is less than the given precision EPs. Π2=1+1!3+2!3x5+3!3x5x7+⋯+i!3x5x⋯x (2xi+1) +⋯\frac{\pi}{2}=1+\frac{1!} {3}+\frac{2!} {3\times 5} + \frac{3!} {3\times 5\times 7}+ \cdots +\frac{i!} {3\times 5\times \cdots \times (2\times i+1)}+ \cdots 2π=1+ 3 1! + 3x5 2! + 3x5x7 3! +⋯+ 3x5x⋯x (2xi+1) I! +⋯

Java Course Design (Student Information management system)

, 150, 50);Administrator_label.setbounds (280, 50, 100, 50); 280, 60, 100, 30User_field.setbounds (180, 100, 300, 50);Password_field.setbounds (180, 200, 300, 50);Login_btn.setbounds (200, 300, 100, 50);Exit_btn.setbounds (350, 300, 100, 50);Add to PanelThis.add (Username_label);This.add (Password_label);This.add (User

PKU 1319 pipe fitters

Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> /* Pay attention to situations where the value is less than 1 and the value is skewed */ # include iostream > # include cmath > # define EPS 1e-6 using namespace STD; DoubleSin60=SQRT (3.0)/2; Int Cal_skew ( Double A, Double B){ Int X, XX, Y; Int Skew; If ( - 1 -

Interface Definition and usage

The Interface Definition starts with an uppercase letter I. The method only defines its name. in C #, the method is a public method by default. The public modification method is not allowed; otherwise, a compilation error occurs. The interface can be inherited from other interfaces, if multiple interfaces are inherited, the parent interface list is separated by commas. Interfaces can be implemented through classes. When the base list of classes contains both the base classes and interfaces, the

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