PromptBIND () error = 10048
Cause: other programs use port 2425 of the Flying Pigeon
For example, feiqiu uses port 2425.
Solution: run the netstat command to check which process occupies the port.
Format: netstat-ano | find "2425"
Result: UDP 0.0.0.0: 2425 *: * 1716
The final 1716 is the process ID that occupies the 2425 process. Let's see what it is. You can end the process directly and then open the Flyi
Mysql connection error (10048) solution bitsCN.com
The solution Can't connect to MySQL server on 'localhost' (10048), which is generally seen in the use of mysql windows 2003 server. The cause of the error:
Applications need to be quickly released and create new connections, but the connections in TIME_WAIT exceed the
PromptBIND () error = 10048
Cause:OthersProgramOccupied port 2425 of the Flying Pigeon
Solution:Run the netstat command to check which process occupies the port.
Format:Netstat-Ano | find "2425"
Result: UDP 0.0.0.0: 2425 *:*1716
The final 1716 is the process ID that occupies the 2425 process. Let's see what it is. You can end the process directly and then open the Flying Pigeon.
For the netstat comm
This is generally because the port number of SQL Server is caused by other applications, you can use the DOS command or Network tools to view the current port usage, to see which program occupies the SQL Server default port 1433, the program can be restarted by the end of the If you are too bothered, you can change the default port for SQL Server directly, and then start the SQL Server service, changing methods such asFigure 1:Figure 2:Figure 3:Original: http://blog.csdn.net/mynewdays/article/de
Topic Introduction: A undirected forward weight graph is used to find the shortest path length between any two nodes. To solve this problem directly, replace the DP sub of Floyd with G [I] [J] = min (G [I] [J], max (G [I] [K], G [k] [J]), and bidirectional assignment code for undirected graphs
#include
Ultraviolet A 10048 audiophobia ultraviolet A-10048
Label:Resolve can ' t connect to MySQL server on ' localhost ' (10048) You are using the Windows operating system, and this error is related to a registry key value of TcpTimedWaitDelay.Reducing tcptimedwaitdelay time in Windows resolves such problems, which by default is 240 (this is also the case if not set)This setting needs to be set to the registry in the following locationHkey_local_machine/system/cu
After a reverse proxy is set on the Apache server, the backend server cannot be connected for a period of time. After several seconds, the backend server can be automatically restored, after checking, it is found that the Apache error log contains the following words: [Error] (OS 10048) only one usage of each socket address (Protocol/network address/port) is norm
Two ways to solve this problem:the first: by looking for the software that takes up the port and shutting downReason: Other programs occupy 2425 ports of the Flying pigeonWorkaround: Use the netstat command to see which process is consuming the
Can't connect to MySQL server on 'localhost' (10048), which is generally seen on windows 2003 server using mysql.Cause of the error:Applications need to be quickly released and create new connections. However, because the connections in TIME_WAIT exceed the default value, the throughput is low.Solution:Two windows registry keys closely related to this error: TcpTimedWaitDelay and MaxUserPort.TcpTimedWaitDel
Resolves can ' t connect to MySQL server ' localhost ' (10048), commonly seen in Windows 2003 servers using MySQL.
Why the error occurred:
Applications need to quickly release and create new connections, but because the connections that exist in time_wait exceed their default values, they result in lower throughput.
Solution:
Registry entries for two windows that are closely related to this
2003Can ' t connect to MySQL server on ' localhost ' (10048)Typically seen in Windows 2003 servers using MySQL.Reason for the occurrence of the error:The first reason:The application needs to quickly release and create new connections, but lower throughput due to the presence of connections in time_wait that exceed the default values.Solution:Two windows registry entries that are closely related to this error
Test instructions: Find the minimum value of the maximum weights for all paths between two points.Idea: Change the form of Floyd;Note: Note the initialization problem and the output form of the UVA flower.The code is as follows:#include #include#include#includestring>#includeusing namespacestd;#defineINF 0x3f3f3fintdp[ the][ the];intMain () {intN,m,q,a,b,w,ca =0; while(cin>>n>>m>>q) {if(n+m+q==0) Break; if(CA! =0) printf ("\ n"); Memset (DP,0x3f,sizeof(DP)); for(inti =0; I ) {cin>>a>>b>>W; DP[
Test instructions: Give a C point, s bar Edge composed of the graph, to find a path to the other point of the maximum weight of the least path, output this valuecan put thisD[i][j]=min (D[i][j],d[i][k]+d[k][j])Change to D[i][j]=min (D[i][j],max (D[i][k],d[k][j]))That is, to find the maximum weight of an edge, and then from these edges to find the smallest1#include 2#include 3#include 4#include 5#include 6#include 7#include 8#include Set>9#include Ten#include One #definemod=1e9+7; A using namesp
Link:
Http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem &problem=989
Topic:
Problem B:audiophobia
Consider yourself lucky! Consider yourself lucky to be still breathing and has fun participating
The following figure shows the minimum noise that must be tolerated by a point (that is, the maximum value of the right of the two adjacent points in the path ).
Chinese Translation
Question Link
Question type: Graph Theory/Floyd
UVA_10048
This topic is to find the path with the smallest maximum value in all reachable paths and output the maximum value. Based on the topic features, it is easier to use the Floyd algorithm to solve the problem.
#include#includeint f[110][110];
Original question: Consider yourself lucky! Consider yourself lucky to be still breathing and have fun participating inThis contest. But we apprehend the many of your descendants may not have the this luxury. For, as youKnow, we is the dwellers of
PhenomenonWhen we encode the implementation to request a page, the requested code resembles the following code:HttpWebRequest req = (HttpWebRequest) webrequest.create (strURL);Req. useragent = "MSIE6.0";Req. Method = "GET";HttpWebResponse res = (HttpWebResponse) req. GetResponse ();StreamReader sr = new StreamReader (res. GetResponseStream (), Strencode);strHTML = Sr. ReadToEnd ();Sr. Close ();However, if the page we are requesting is exactly a page with an exception, or a page that does not exi
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