esp 3250

) object User-Defined Function 2 → │ ┃ 24 (?) ...... The object variable of the │ interface was too large and too small to exceed the upper limit.] ━━ ━┓ │ ① 0 (4) the pointer of the interface was → ② 0 (4) * pvtable was → ③? (?) ...... │ ┗ ━ ┛ ┃ ┗ ━━ [[[[[│ ┣ ━━ ━ [Interface 2] ━━ ━ ┫ ┏ [[ [interface 2] ━━ ┓ │ ┃ ...... Too many? (?) ...... ┃ ╰ ── ╯ ① = Varptr (object variable) Address ② = objptr (object variable) '// This pointer address ③: it can only be obtained indirectly through copymemory:

of the function in the function, pointing to the stack bottom (frame bottom) of a function ). % ESP --- is the stack register, which is equivalent to the base register of the entire program, always pointing to the top of the stack. Push --- import stack operation. MoV --- move Sub --- Subtraction In the first sentence, push % EBP means % EBP is put into the stack. At this time, % EBP stores the starting address of the frame of the previous function,

is not currently in the running state.; Sub ESP, 4*4MoV [esp + 12], EBX; save registersMoV [esp + 8], ESI;MoV [esp + 4], EDI;MoV [esp + 0], EBP;MoV EBX, PCR [pcselfpcr]; Set address of PCRMoV EDI, ECx; set old thread addressMoV ESI, EDX; set next thread addressMovzx ECx, by

It is widely used in NAT and IPSec technologies. But in essence, there is a conflict between the two. 1. From the IPsec perspective, IPSec needs to ensure data security, so it encrypts and verifies data. 2. From the perspective of NAT, IP addresses are bound to be modified to complete address translation. IPSec provides the security of end-to-end IP communication, but there is limited support for IPSec in the NAT environment. Ah must not be able to perform Nat, this is contrary to the concept of

In-depth analysis of the C ++ function call Process Liu Bing QQ: 44452114 E-mail: liubing2000@foxmail.com 0. Introduction 　　The function call process is actually an interrupted process. How does C ++ implement a function call? How does a parameter stack, function jump, protection site, and response site be implemented? This article provides an in-depth analysis and explanation of the function call process, and demonstrates it in the VC 6.0 environment. If the analysis is not in place or there ar

int goo(int a, int b){return a + b;}void foo(){int a[] = {1, 2, 3};int result = goo(a[1], a[2]);printf("result: %d", result);} Compile in vs2010 Foo function assembly: 00EB3890 push ebp 00EB3891 mov ebp,esp 00EB3893 sub esp,0E4h 00EB3899 push ebx 00EB389A push esi 00EB389B push edi 00EB389C lea edi,[ebp-0E4h] 00EB38A2 mov ecx,39h

;}CCall::~CCall(){}int CCall::Call(int arg1, short arg2, char arg3, void *arg4){int var1;short var2;char var3;int *p;var1 = arg1;var2 = arg2;var3 = arg3;p = (int *)arg4;*p = m_Var1;return 0;}There are also portals and global functions: // Main. cpp... # include Next we will look at the call process in DEBUG. Note that if it is VS. NET, a DWORD will be added before and after each variable during VC compilation to detect Buffer Overflow. First, call the void function without return values. Th

Original article address: Http://net.pku.edu.cn /~ Course/cs201/2004/ASSEMBLY/Workshop In Win32 compilation, we often deal with APIs. In addition, we often use self-compiled subprograms with parameters similar to APIs, this article describes the concept and Analysis of parameter transfer during the subroutine call process. In a program, the parameter is passed through the stack. That is to say, the caller pushes the parameter to be passed to the subroutine (or called) into the stack, the subrou

*/Task[pid].next= task[pid];/*the next process in the initial process 0 is process 0*/Then three processes were copied, note Task[i].state =-1; / * Initial state of the process, not enforceable */ Task[i].next = task[i-1].next; Task[i-1].next = task[i]; /* */These two lines of code set the way the process is switched, such as process 0 switching to process 1, and process 1 switching to process 2. /*START process 0 by task[0]*/PID=0; My_current_task= Task[pid]; ASMvolatile( "M

Debug versionESP stack top pointerEBP holds stack pointer Empty program: Int main () { 00411360 push ebp, press into EBP 00411361 mov ebp,esp; EBP = ESP, keep esp, wait for function call to resume, ESP is definitely used in a function call. 00411363 Sub esp,0c0h;

Reference :http://blog.csdn.net/hudashi/article/details/7820338http://shitou7630.blog.163.com/blog/static/32699536201342110155436/Http://www.cnblogs.com/52yixin/archive/2011/06/29/2093634.htmlhttp://blog.csdn.net/mniwc/article/details/7993361Http://www.cnblogs.com/coderzh/archive/2008/12/01/1345053.htmlHttp://blog.sina.com.cn/s/blog_6f6769b50100uhzz.htmlHttps://msdn.microsoft.com/zh-cn/library/ms235286.aspx(Owed by: Spring Night rain Http://blog.csdn.net/chunyexiyu reprint please indicate the so

vtbldiamond (); If (pvtblreal1! = NULL) { Pvtblreal1-> F1 (); Vtblrealb * ptempvtbb = dynamic_cast Ptempvtbb-> F1 (); Delete pvtblreal1; } Vtblrealb * pvtbrealb = new vtbldiamond (); If (pvtbrealb! = NULL) { Ivtbl * pvtbl = dynamic_cast Pvtbl-> F1 (); Delete pvtbrealb; } Return 0; } The execution result is as follows: Let's perform disassembly and debugging to see how the compiler helps us implement it? Let's look at the initialization of an

// Big map. Text: 6f3a2060 sub_6f3a2060 proc near; Code xref: sub_6f38d120 + 67 P. Text: 6f3a2060; sub_6f39bca0 + 67 P.... Text: 6f3a2060. Text: 6f3a2060 var_8 = dword ptr-8. Text: 6f3a2060 var_4 = dword ptr-4. Text: 6f3a2060 arg_0 = dword ptr 4. Text: 6f3a2060 arg_4 = dword ptr 8. Text: 6f3a2060 arg_8 = dword ptr 0ch. Text: 6f3a2060 arg_c = dword ptr 10 h. Text: 6f3a2060. Text: 6f3a2060 sub ESP, 8. Text: 6f3a2063 mov eax, [

---restore content starts---Content one: Experimental report related instructions.Real name Chering HelpOriginal works reproduced please indicate the sourceLessons learned: Linux kernel Analysis MOOC courseLinks:http://mooc.study.163.com/course/USTC-1000029000Virtual Lab ExperimentContent two: Analysis of stack changes during the working process of assembler codeThe analysis is divided into two parts: (The label of the stack address is not aligned, please understand)The first part is the stack t

Explains stack changes for MAIN.C assembler codeThe experiment looks like this:The following analysis begins with the main function (three variable values from top to bottom are 4,7,4):Suppose you start with an empty stack, the initial position is 0,EBP=ESP, and the following is marked with a line number18:esp point to position (1), the value of position (1) is the address of the ESP19: Make EBP point to th

Transfer from http://blog.csdn.net/dongtingzhizi/article/details/6680050In-depth analysis of C + + function call processBrotherWeibo:-bing son of the dongting0. Introduction　　The process of a function call is actually a process of interruption, so how does a function call be implemented in C + +? How to implement parameters in the stack, function jump, protection site, reply to the scene? In this paper, the procedure of function call is analyzed and explained in detail, and it is demonstrated in

the contents of RAM inside pull. You can go to "see the snow" to learn a simple assembler command. 004f3b9c/$ PUSH EBX 004f3b9d |. 83C4 F8 ADD esp,-8 004f3ba0 |. 8BDA MOV Ebx,edx; Data Destination address after decryption 004f3ba2 |. 8bd4 MOV Edx,esp; Data Delivery Destination Address 004f3ba4 |. B9 04000000 MOV ecx,4; The number of passes is 4 004f3ba9 |. E8 12eef8ff call client.004829c0; Pass the 4 valu

the number of records replaced 0X2E, that is, ".", the completion of the processing. The function that handles the incoming domain name in Symdns.sys is at the Symdns.sys base address +0xa76, which allocates enough space in the stack (in fact, the last Shellcode execution is not performed on the stack, but in the non-paged pool). The incoming domain name has a maximum length limit and cannot exceed 0x40 bytes, so i shellcode length is 0x3f (63) bytes per paragraph. After overwriting 532 bytes,

;int *p;var1 = Arg1;var2 = Arg2;var3 = Arg3;p = (int *) arg4;*p = M_var1;return 0;}There are also portals and global functions:Main.cpp #include The following is a look at the call procedure under Debug, note that if VS.NET,VC is compiled, a DWORD is added before and after each variable to detect a buffer overflowThe first is to call the void function with no return value, which is __cdecl called by default:: fnvoid (1, 2, 3); 0040135D push 30040135F push 200401361 push

instruction ' jnz. L003nohalt ' X86cpuid-elf.s:97:error:bad instruction ' PUSHFL ' X86cpuid-elf.s:98:error:bad instruction ' popl%eax ' X86cpuid-elf.s:99:error:bad instruction ' BTL $9,%eax ' X86cpuid-elf.s:100:error:bad instruction ' Jnc. L003nohalt ' X86cpuid-elf.s:102:error:bad instruction ' PUSHL%edx ' X86cpuid-elf.s:103:error:bad instruction ' PUSHL%eax ' X86cpuid-elf.s:104:error:bad instruction ' hlt ' X86cpuid-elf.s:106:error:bad instruction ' Subl (%