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ESP law shelling OD script

For beginners, I read the OllyScript syntax and wrote a simple ESP law shelling script. The Explanation of "ESP law" is not explained here. You can search for relevant information by yourself. // UPX and Aspack Tests passed. After the script is run, you may need to fix IAT later.

ESP8266 ESP-01 Debugging method

1, using AMS1117 to build a 3.3V output circuit2, ESP8266 ESP-01 wiringAs long as you connect the UTXD, GND, CH_PD, VCC, urxd these five pins can be used directly.Note that the CH_PD is to be connected to high level.3, using the TCP232 serial function test3.1 Open serial assistant, baud rate set to 1152003.2 When the power is restarted, the Blue lantern flashes a few times, then the serial assistant also has the information output. After the output is

Recently do a ESP-8266 module study ~ Come on!

Module just to ~2016-01-26After three is the mobile phone app, the front is two ESP8266 hardware module, of course, we should not be determined to buy two, their own solder a USB to TTL serial port on the line, with the bottom of the base we can conveniently put ESP8266 at the firmware to the chip inside, At the same time the module is also connected to the TXD and RXD to facilitate the communication of the microcontroller-board 6 LEDs, respectively, with the application of the button correspond

Comparison Between Fast ESP and autonomy l server-Microsoft Enterprise Search

Comparison Between Fast ESP and autonomy idol server-Microsoft Enterprise Search-fast-csdn blogHttp://blog.csdn.net/lliihhtt/article/details/5511510The most visible oneArticle,The comparison is advantageous, and the comparison between deliberately short and weakened competitors. Since fast began to support Microsoft OS, does not support Linux, UNIX, is doomed to death.The U.S. fast has been laid off, and the bell of the fast has begun to ring. I don

(installed) about WINRE/ESP/LRS_ESP/MSR/PBR these partitions

WINRE 1GB use: Windows 8 system Recovery model. This partition is a Windows 8 PE system that is saved when the Windows 8 system principal itself is damaged and does not start properly when the system is repaired.ESP 260MB uses: EFI extended partition, UEFI BIOS boot system used, storage bios/efi NAND chip stored in that part of the EFI extension feature.lrs_esp 500MB use: Lenovo One-click Restore Windows PE system boot partition, Lenovo one-click Restore software is also installed in this sectio

Esp-pos printing pictures and QR codes

Bytearrayoutputstream buffer = new Bytearrayoutputstream (); data[0] = 0x1D; data[1] = 0x76; data[2] = 0x30; data[3] = 0x00; data[4] = (byte) w; XL data[5] = (byte) (w >> 8); XH data[6] = (byte) h; data[7] = (byte) (H >> 8); int k =

DLL call error-The value of ESP was not properly saved stored ss a f

Jeffrey Magder | replyI was having the same problem, but I just FIXED it. I was getting the same error from the following code: HMODULE hPowerFunctions = LoadLibrary ("Powrprof. dll ");Typedef bool (* tSetSuspendStateSig) (BOOL, BOOL, BOOL

--- Prototype implementation of overflow implanted Trojan Horse (backdoor) Author: flashsky (original)

esp Code provision and positioningOverflow Code uses retaddr to grasp the initiative, but because shellcode is dynamically allocated in the memory stack, it cannot obtain its address accurately, so we need to take advantage of the JMP ESPSome applications may have such statements. Some applications may not have such statements, and the addresses are not the same.It also changes. Therefore, a fixed jmp esp

How does the compiler implement a virtual function table in C ++ using the Assembly Language and implicitly pass the this pointer? (1)

The so-called object-oriented and inheritance, polymorphism, and so on are only implemented at the language level, and machines do not even know this when executing programs. The purpose of this blog is to discuss how the compiler implements C ++ virtual functions. First, we will discuss the simplest situation: The Code is as follows: vtable. cpp: #include Gcc-s vtable. cpp generates vtable. s The annotations are very detailed. You only need to know a few simple assembly commands to understand

Disassembly of a simple C program

Long#long + Original works reproduced please specify the source + "Linux kernel analysis" MOOC course http://mooc.study.163.com/course/USTC-1000029000C Program code:1 intGintx)2 {3 returnX +3;4 }5 6 intFintx)7 {8 returng (x);9 }Ten One intMainvoid) A { - returnF8) +1; -}View CodeCompile command:gcc -s-o main.s main.c-m32Compiled assembly code:. file"main.c". Text. Globl g. Type G, @functiong:.LFB0:. Cfi_startproc pushl%ebp. Cfi_def_cfa_offset8. Cfi_offset5, -8movl%

[Dynamic stack memory allocation] inside alloca

_ alloca_probe_8. The Code is as follows: .xlist include cruntime.inc.listextern _chkstk:near; size of a page of memory CODESEGpagepublic _alloca_probe_8_alloca_probe_16 proc ; 16 byte aligned alloca push ecx lea ecx, [esp] + 8 ; TOS before entering this function sub ecx, eax ; New TOS and ecx, (16 - 1) ; Distance from 16 bit align (align down) add

How to obtain the function parameters in DLL

We can know the interface function parameters through disassembly. We recommend that you use w32dsm for analysis, or you can directly use VC for analysis, which is a little more troublesome.The following describes how to use w32dsm:1. First open the DLL to be analyzed, and then find the function to be analyzed through the menu function-> export, double-click it.It can directly locate the function.2. Check the function entry. Generally, the function uses the following code as the entry point.Push

The difference between pointer and reference.

pointers and references We use the following simple code to analyze pointers and references in depth: # Include Using namespace STD; Int main (INT argc, char ** argv) { Int I = 1; Int ref = I; Int x = ref; Cout Ref = 2; Int * P = I; Cout } Use the above CodeG ++ test. cCompile and decompileObjdump-d a. OutTo obtain the assembly code of the main function: 08048714 8048714: 55 push % EBP8048715: 89 E5 mov % ESP, % EBP8048717: 83

Pointers and references in C + +

-draw a vertical asterisk (*) through the pointer declaration, if the const appears to the left of the line, the pointer to the data is a constant, if the const appears on the right, the pointer itself is a constant. and the reference itself and the sky is the constant, that is, can not change the point.4. Implementation of pointers and referencesWe use the following simple code to drill down on pointers and references:#include using namespace Std;int main (int argc, char** argv){int i=1;int ref

Differences between references and pointers in C + +

change the point. 4. Implementation of pointers and references We use the following simple code to drill down on pointers and references: #include using namespace Std; int main (int argc, char** argv) { int i=1; int ref=i; int x=ref; cout ref=2; int* p=i; cout } The code above is compiled with g++ test.c and then disassembled objdump-d a.outto get a section of the assembly code for the main function as follows: 08048714 8048714:55 Push%EBP8048715:89 e5 mov%

Function call stack (good)

National embedded Talent Training Base 1. function callPrevious PageChapter 2 Relationship Between assembly and CNext Page -------------------------------------------------------------------------------- 1. Please comment on function calls We use the following code to study the function call process.Example 19.1: Study the function call ProcessInt bar (int c, int D) { Int e = C + D; Return E; } Int Foo (int A, int B) { Return bar (A, B ); } Int main (void) { Foo (2, 3 ); Return 0; } If the-G

Pointer and reference in C ++

" Ref = 2; Int* P = I; Cout "Ref ="", I =" } Use the above CodeG ++ test. cCompile and decompileObjdump-d a. OutTo obtain the assembly code of the main function: 08048714 8048714: 55 push % EBP 8048715: 89 E5 mov % ESP, % EBP 8048717: 83 E4 F0 and $0xfffffff0, % ESP// Reserved location for the parameters argc and argv of the Main Function 80100001a: 56 push % ESI 801

A summary of the first week of the Linux kernel analysis course

of viewAPI: interface between programmer and computerABI: Program and CPU binary interface, instruction encoding, mainly assembly instructions, need to be familiar with the instructions involved in the register layout, most instructions can access memory.The EIP in X86 automatically adds an instruction after the CPU executes an instruction, the instruction length is different, and can be modified by other instructions such as CALL,RET,JMP and conditional JMP.Ii. the basis of x86 compilationStac

C + + Disassembly instance (1)-Output multiple lines

Program Description: Output multi-line content, the content is as follows:*************************1#include 2 using namespacestd;3 intMain ()4 {5cout " *"Endl;6cout " ***"Endl;7cout " *****"Endl;8cout "*******"Endl;9cout " *****"Endl;Tencout " ***"Endl; Onecout " *"Endl; A -System"Pause"); - return 0; the}Debug Disassembly CodeintMain () {00ff5e00 push ebp //Enter function after the first thing, save the bottom pointer, used to exit the function to restore the bottom of the stack. 00

C Language Learning Note (002)-the difference between references and pointers in C + + (reproduced)

reference itself and the sky is the constant, that is, can not change the point.4. Implementation of pointers and referencesWe use the following simple code to drill down on pointers and references:#include using namespace Std;int main (int argc, char** argv){int i=1;int ref=i;int x=ref;coutref=2;int* p=i;cout}The above code is compiled with g++ test.c , and then disassembled objdump-d a.out, to get the assembly code of the main function as follows: 08048714 8048714:55 P

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