exponential smoothing calculation

Original address:Http://blog.csdn.net/qustmeng/article/details/52186378?locationNum=4fps=1Import java.util.LinkedList;Import java.util.List;public class Demo {/*** Two times exponential smoothing method for predicting values* @param list Base data collection* @param year of the next few installments* @param modulus Smoothing coefficient* @return Predictive value*

My friends and I shared the simple exponential smoothing method, simple exponential smoothing can only predict those at a constant level and no seasonal changes in the time series, today and you share the non-constant level of growth or reduce the trend, The time series prediction algorithm without seasonal additive mo

We have a complete understanding of the time series sequence and decompose the time series, and today we share the simplest of the common predictive algorithms with the small partners: simple exponential smoothing. Simple exponential smoothing applies to the available additive model descriptions, and is at a constant l

Today goes on to the most complex time series in exponential smoothing: a predictive algorithm that has a time series of increasing or decreasing trends and having seasonal fluctuations is holt-winters and shared with everyone. This sequence can be decomposed into the horizontal trend part, the seasonal fluctuation part, therefore these two factors should have the corresponding parameter to control in the a

20th and 30 rows is used to calculate the exponential function. This method uses the formula ex + y = exey to divide the X parameter into integer part N and decimal part X-N for calculation. The integer N is decomposed into some sums in the numbers 1, 2, 4, 8, 16, 32, and 64, which are calculated using the previously calculated constants. Row 25th is used to prevent e66.5421 from being broken down

("Emar={0}", result. EmaR);}Contains calculation results for EMA indicatorpublic class Emaresult{Public listpublic int Startindexoffset {get; set;}Public double EmaR {get; set;}}//------------------------------------------------------------------------------------------------------------- ------------------Calculates exponential moving Average (EMA) indicatorpublic static Emaresult EMA (ienumerable{var ret

Welcome to __xiong 's blog: http://blog.csdn.net/acmore_xiong?viewmode=list calculation time limit:2000/1000 MS ( java/others) memory limit:32768/32768 K (java/others) Total submission (s): 1912 accepted Submission (s): 413 Link: Click me problem descriptionassume that F (0) = 1 and 0^0=1. F (n) = (n%10) ^f (N/10) for all n bigger than zero. Calculate f (N)%m. (2≤n, m≤10^9, x^y means the y th power of x). inputthe first lin