Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13 .....His rule is that the first item is 0, the second item is 1, and the third item starts with the sum of the first two.> Recursive implementationSee this rule, the first thought of course is recursive algorithm to achieve, so wrote the following paragraph: Public classRecursionforfibonaccisequence { Public Static voidMain (string[] args) {System.out.println (recursion (10)); } Public Static DoubleRec
/** * Title: * There are a pair of rabbits, from the 3rd month after birth, each month has a pair of rabbits, the rabbit long to the third month after the birth of a pair of rabbits each month. * If the rabbit is not dead, ask after month months, how many rabbits total? */public class Fibonacci {//month static Integer month = 3;//NOTE: month > 0public static void Main (string[] args) {Integer pair = f (month); System.out.println ("A: after" + month +
is equal to the first two months the sum of the large rabbit logarithm. If the N-month large rabbit logarithm is expressed in un, there isUN = un-1 + un-2, n >2 each month the number of large rabbits in the series is: 1,1,2,3,5,8,13,21,34,55,89,144, /c5> this sequence is called the Fibonacci sequence. Recursive method:Using the formula F[n]=f[n-1]+f[n-2], recursive calculation in turn, the recursive end condition is f[1]=1,f[2]=1.code
First, a solution using addition is written in the header file whichfibonaccinumber.h . There is no verification that the input number is less than 0.#ifndef whichfibonaccinumber_h_#define whichfibonaccinumber_h_typedef unsigned long long uint64;//abbreviated unsigned long long , because it is 64 bits, writing UInt64 (meaning: Unsigned int 64 bit)//max = = 18446744073709551615, try to ensure that no overflow. Another: the "General formula" solution needs to open square. UInt64 whichfibonaccinumb
The python iterator implements the Fibonacci evaluate and the python Fibonacci evaluate
The Fibonacci sequence, also known as the Golden series, is also known as the rabbit Series: F (0) = 0, F (1) = 1, F (n) = F (n-1) + F (n-2) (n ≥ 2, n *). For example, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,144,233,377,610,987,159, 28657,463 ........ this series starts from 3rd
One: Recursive implementation
Using the formula F[n]=f[n-1]+f[n-2], recursive calculation in turn, the recursive end condition is f[1]=1,f[2]=1.
Two: Array implementation
Spatial complexity and time complexity are all 0 (n), which is more efficient and faster than recursion.
Three:vectorTime complexity is 0 (n), time complexity is 0 (1), is not aware of vector efficiency is not high, of course, Vector has its own properties will occupy resources.
Four:queueOf course the queue is more suitable th
Approximate test instructions: Enter two nonnegative integers, a, B, and positive integer n. Calculates f (a^b)%n. Among them F[0]=f[1]=1, F[i+2]=f[i+1]+f[i]. That is to calculate the large Fibonacci number and then take the modulus.First saw the big Fibonacci number, think of the matrix fast power, output wait a few seconds before output, will definitely time out. Because all calculations are to be modulo,
Fibonaccitime limit: 1000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)
Total submission (s): 3569 accepted submission (s): 1627
Problem description is coming in 2007. After one year of practice in 2006, zouyu, a mathematical prodigy, finally ranked 0 to 100000000 In the Fibonacci series.
(F [0] = 0, F [1] = 1; F [I] = f [I-1] + F [I-2] (I> = 2 )) all the values are backed up.
Next, codestar decided to test him, so every time he a
The beauty of programming: 2.9 Fibonacci series, 2.9 Fibonacci
The Fibonacci series is a classic example of recursion when we are learning the C language. Of course, there will also be an example of the tower of legends.
This problem is defined as follows:
0 (x
F (x) = 1 (x = 1)
F (x-1) + f (x-2) (x> 1)
After seeing this recursive formula, we can easily write th
10236-the Fibonacci Primes
Time limit:3.000 seconds
Http://uva.onlinejudge.org/index.php?option=com_onlinejudgeItemid=8category=24page=show_problem problem=1177
Note that the description of this topic is different from the description of Fibonacci prime on Wikipedia.
The above-highlighted text shows that Fibonacci Prime can be screened with a similar number
One: Recursive implementationUsing the formula F[n]=f[n-1]+f[n-2], recursion is computed sequentially, and the recursive end condition is f[1]=1,f[2]=1.
Two: Array implementationThe space complexity and time complexity are all 0 (n), and the efficiency is generally faster than that of recursion.
three:vectorThe time complexity is 0 (n), the time complexity is 0 (1), the vector is not known to be highly efficient, of course the vector has its own attributes will occupy resources.
Four:queueOf
One: Recursive implementationusing the formula F[n]=f[n-1]+f[n-2], recursion is computed sequentially, and the recursive end condition is f[1]=1,f[2]=1.
Two: Array implementationthe space complexity and time complexity are all 0 (n), and the efficiency is generally faster than that of recursion.
Three:vectorthe time complexity is 0 (n), the time complexity is 0 (1), the vector is not known to be highly efficient, of course the vector has its own attributes will occupy resources.
Four:queueof
Luogp1962 Fibonacci series, P1962 Fibonacci SeriesBackground
As we all know, the Fibonacci series is a series that meets the following characteristics:
• F (1) = 1
• F (2) = 1
• F (n) = f (n-1) + f (n-2) (n ≥ 2 and n is an integer)Description
Find the value of f (n) mod 1000000007.Input/Output Format
Input Format:
· Row 1st: an integer n
Output Format:
Row 3:
First: Using a For loopThe use of the For loop, does not involve functions, but this method for my small white is a good understanding of the function of a more abstract ...1 >>> fibs = [0,1]2 for in range (8):3 Fibs.append (Fibs[-2] + fibs[-1])45 >>> fibs6 [0, 1, 1, 2 , 3, 5, 8, 13, 21, 34]Or, enter a dynamic length:1fibs = [0,1]2num = input ('howmany Fibonacci numbers does you want? ' )3 for in range (Num-2):4 fibs.append (Fibs[-2] + Fi
Topic Transfer: UVA-10229Idea: The simple matrix quickly powers the Fibonacci sequence, then notice that the intermediate result can explode int, because 2^19 has more than 500,000AC Code:#include Uva-10229-modular Fibonacci (Matrix fast Power + Fibonacci)
The sum of the First n digits of Fibonacci and the n digits of Fibonacci
Public class Fei_bo_na_qi {Public static void main (String [] args) {// main method, program entryInt I = 10; // declare an int type variable I, and assign a value of 10Int a = 0; // declare an int data type variableFor (int j = I; j> = 1; -- j) {// for Loop: j = I = 10, j> = 1A + = m1 (j); // call the m1 method and assign the value of
Question Link
Give N and M, and find F (n) % m. f (x) is the Fibonacci sequence.
Idea: Because N is big, it is very likely that it will use the formula to calculate it, so we can use the Matrix to quickly solve the power. | (1, 1), (1, 0) | * | f (n-1), F (n-2) | = | f (N), F (n-1) |, so f (N) equivalent to | F (1), F (0) | multiplied by N-1 | (1, 1), (1, 0) |.
Code:
#include
Uva10299-modular Fibonacci
Projection type:
Based on the shape of the shadow plane, it can be divided into: azimuth projection (plane projection), cone projection, and garden column projection.Classified by deformation properties into: Equality projection, equality
A simple Fibonacci sequence, with the following code:# Filename: fibonaci.py# author by: stephendef fib(n): #定义一个函数叫 fib() if n [Python learning] Fibonacci sequence Fibonacci Sequence
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