find common divisor

Baidu Encyclopedia on the introduction of the greatest common divisor (limit two number) There are two main: The method of the division and the more subtractive method.Euclidean methodThe Division method, Baidu Encyclopedia on the example:The

A, two number of greatest common divisorDef common_divisor (A, B):For I in range (1, min (A, B) + 1): If a% i = = 0 and b% i ==0:m = i print ("The common divisor is%d "%m)At first, the above code is never understood, why it is just 6, because

1. the Euclidean methodThe greatest common divisor is a method of finding two natural numbers, also called Euclidean algorithm.For example, ask for GCD (319,377):∵377÷319=1 (Yu 58)∴GCD (377,319) =GCD (319,58);∵319÷58=5 (Yu 29),∴GCD (319,58) =GCD (58

1, two number coprime: if the two number of the public factor is only 1, then it can be said that the two numbers coprime. Euclidean algorithm for greatest common divisor:First, greatest common divisor, suppose we ask for a and b 's greatest common

First give the source code, explained below. #include void Main (){int a,b,c,d; //define four variablesscanf ("%d,%d", &a,&b);D=a*b; //Find out the product of two positive integerswhile (b!=0){C=a%b; //focus is here, a lot of people do not

Topic Background ApproximateIf a number a can be divisible by a number B, a is called a multiple of B, and B is called a 约数 .Greatest common divisorGreatest common divisor is a two-digit number that everyone can meet and the largest number.Euclidean

The practice of seeking greatest common divisor, least common multiple and decomposition factorization of exotic flowers (C language) 1 /*2 The most wonderful seeking greatest common divisor and least common multiple3 Create by Laog4 Time July 27,

The classical algorithm for greatest common divisor and least common multiple is described as follows:If greatest common divisor and least common multiple are required for a, a, two number, A is a, B is the larger number, B is the smaller number,

Title: Enter two positive integers number1 and number2, seeking their greatest common divisor and least common multiple.Algorithm: The larger number and the smaller number take the remainder, the smaller number except the remnant, until the

Enter two positive integers m and N to find their greatest common divisor and least common multiple.Solution: Program:#include int main (){int NUM1, num2, t,p;printf ("Please enter two positive integers:");scanf ("%d,%d", &num1, &num2);//7,8p = num1*