find nth prime number c

Today in the group has the Netizen question: Ask for a 1000th prime number starting with Python 0? In fact, the algorithm itself is not difficult to find the prime number from the definition of prime numbers.

Problem Description: Find the prime number within a rangeIdea: to label each numberFirst, to iterate through all the numbers in that range, a cycleThen, traverse 2 to n-1. See if they can be divisible.Code:#-*-coding:utf-8-*-Importstring#find the prime

Find the prime number between 1~n Difficulty level: A; run time limit: 1000ms; operating space limit: 256000KB; code length limit: 2000000B Question Description The number of primes is greater than 1 and cannot be divisible by other integers except 1 and itself. Requires a

Package Com.test_java; Import Java.util.Arrays; public class Prime {* * * * * * * * To find the prime number within n/int n; int i,j; Prime (int inputn) {this. N = inputn; //Normal Trial Division private void Comprime1_1 () {System.out.println ("less than" + N + "

This article mainly introduces the JavaScript implementation to find prime number code sharing, this article directly gives the implementation code, the need for friends can refer to the following Well, there's no background note, no advanced skills, sheer boredom, trying to find all the primes in 10000. So here we g

Optimization points:Even numbers must not be primes, because they can all be divisible by 2.The boundary of J can be taken as the root, because if a number can be divisible, the square root of it can be judged whether it is a prime value.Import Datetimestart = Datetime.datetime.now () #0.512,993 sec Print (2, end= ") for I in range (3, 100000, 2): for J in range (3, int (i * * 0.5) + 1, 2): # for J in range

1 Packagealgorithm;2 //Reprint Please specify3 Public classFilterprime {4 Public Static voidFilterprime (intN) {5 Boolean[] Isprimes =New Boolean[N+1];6 for(inti=2;i){7isprimes[i]=true;8 }9isprimes[2]=true;Ten for(intj=2;j){ One if(isprimes[j]==true){ A for(intm=2;j*m){ -isprimes[j*m]=false; - } the } - } - for(intk=2;k){ - if(isprimes[k]==true){ +System.out.println (k +

Tag: Make it terminate with a labeled break statement Publicclassc3_18{publicstaticvoidmain (String[] args) { Intn=0,m,j,i;p1:for (i=3;iRun results650) this.width=650; "src=" http://img.blog.csdn.net/20150723163145420 "alt=" here write a picture describing "title=" "/>This article is from the "Sanghaidan blog column" blog, please be sure to keep this source http://10602803.blog.51cto.com/10592803/1683069To find the

1181 prime numbers in prime numbers (prime number Sieve method)Title Source: SguBase time limit: 1 seconds space limit: 131072 KB score: 0 Difficulty: Basic problemIf a prime number is a prime