find nth prime number c

1. Title:In the infinite sequence of integers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... To find the nth number in aAttention:n is a positive number and is within 32 of the Shaping range ( n Example 1:Input:3 output:3Example 2:input:one output: 0 Description: the 11th digit in sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, .

flag [10]. 2, 3,4, 5,6, 7,8,9,10 Step 5 Access 6. Flag [6] is marked so 6 is not added to the prime number table. The number obtained by multiplying all the numbers in the 6 and prime number tables must not be a prime

My algorithm ideas and implementation methods are in the code and comments, this way does make the algorithm complexity of a grade, very good ah.#include /** * Use an array to find the first n prime numbers * To determine whether a number m is a prime, which can be determined by the divisible nature of the obtained

Prime number and composite number Excerpt from Wikipedia: Prime number, also known as Prime , refers to the number of natural numbers greater than 1, except for 1 and the integer itse

Number Sequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 35823 Accepted: 10340 DescriptionA single Positive An integer I is given. Write a program to find the digit located in the position I in the sequence of number groups s1s2 ... Sk. Each group Sk consists of a sequence of positi

Invitational Contest RecommendWangye[Cpp] view plaincopy/*Question:Give you a, B, c, d, k; find such a Team x, y, so that gcd (x, y) = k, and x in [1, B], yε [1, d]: ask how many pairs meet the requirements (x, y ).------------------------------------------------------------------------------Idea: gcd (x, y) = k indicates that x and y can be divisible by k, but what can be divisible by k may not be gcd = k, and must satisfy the mutual quality. the pr

method to find all prime numbers within n. the time complexity is too high to be tolerated. Therefore, another algorithm is introduced here, the prime number embedding method can save a lot of time. The direct effect is that I instantly AC the question about prime

);//Print out the prime number within 100 *//*Method Three: Using the screening method to find prime numbersFirst step: First of all, we identified 1 as a prime number, 0 is identified as a non-

Let's take a look at the most classic Eratsteni sieve method. Time Complexity of O (n loglog N) int ANS[MAXN]; void Prime (int n) { int cnt=0; memset (prime,1,sizeof (Prime)); prime[0]=prime[1]=0; for (int i=2;i Obviously, when a n