The algorithm of factorial is more than two aspects: first, high precision computation and the second is related to number theory.
First, the high precision calculation factorial
This is actually the least technical content of the problem, but
LeetCode 172 Factorial Trailing Zeroes (zero after Factorial )(*)Translation
Given an integer n, return n! The number of zeros. Note: Your solution should be within the log time complexity.
Original
Given an integer n, return the number of
LeetCode 172: Factorial Trailing Zeroes
Given an integer n, return the number of trailing zeroes in n !.
// Question Description: given an integer n, return n! (Factorial of n) the number of suffixes 0. // Method 1: first obtain the factorial of n
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Title:Given an integer n, return the number of trailing zeroes in N!.Note: Your solution should is in logarithmic time complexity.Ideas:We're going to calculate N! The number of rear guides 0.Let's take a look at the rules, consider n!. Prime-number
Two factorial Problems
Two questions about factorial
This article introduces two problems related to the factorial operation. Remember, the factorial result cannot be calculated because it will overflow. Do not convert it to a string because it is
Given an integer n, return the number of trailing zeroes in n!.Note: Your solution should is in logarithmic time complexity.Credits:Special thanks to @ts for adding this problem and creating all test cases.See for a long while did not read the
Zoj2022 factorial
The first question of self a in the IDC room ~
Find the number of consecutive zeros on the tail of the given factorial;
Train of Thought: high requirements on efficiency, so there is no need to doubt that it is a reference to
Problem description: given an integer N, the factorial n of n! How many zeros are there at the end? Example: n = 10, n! = 3628800, n! There are two zeros at the end
Analysis of the problem: Calculate the factorial of N and then check whether there
Question one: Given an integer n, how many 0 are there at the end of the factorial of n? For example n = ten, n! = 362800,n! There are two 0 at the end.Question two: Ask N! The position of the lowest bit 1 in the binary representation.Solution one
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