I have a 60 GB Kingston solid state drive, tested the difference between 4 K partition alignment and found that the performance is very different, not to mention, first, the software optimization and testing software below, download URL:There is no running score with 4 K partition alignment firstNote that 31 k-BAD means that 4 k does not mean alignment.650) this. width = 650; "src =" http://www.bkjia.com/uploads/allimg/131227/19141355V-0.png "border =
Matte Painting refers to the landscape, scene, or distant environment that is required to create a film by means of Painting, but is too expensive or difficult to create in the field. Matte Painting can be translated as "" or "" in Chinese, but it cannot express the meaning of the original word exactly.
Matte Painting is the originator of special film effects. It first appeared in the era of black and white silent movies, and its development history is almost as old as that of movies (around 191
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Link to this article: "Creative appreciation" 60
Android --- 60 --- simple use of the Notification bar, androidnotification
Notification is a Notification displayed in the mobile phone status bar.
Create a Notification object using the Notification. Builder class.
Common Notification. Builder methods:
SetDefaults (): Set the notification LED light, music, vibration, etc.
SetAutoCancle (): sets the notification to be deleted automatically in the status bar after clicking the notification.
SetContentT
more than 24 points. This lays the foundation for the advantage of using TTF to dynamically generate a model. We want to be big, big, and small.
You can feel it by yourself. In Windows Phone 7, there is almost no readability in the
When 480*320 resolution is used, the display on the screen cannot be aligned to pixels, And the edge anti-aliasing is meaningless. In addition, this resolution is intended for graphic performance. The dot matrix font library should be used at this time. We will su
){for(int i=2;i
57. Print the loop matrix (Netease)
Void print (int n) {If (n
58. expression evaluation (Netease)
A string consists of '+', '-', and '0'-'9', and '+' and '-' are only binary operators.
Bool calculate (const char * exp, Int result );
bool calculate(const char* exp, int result){if(exp==NULL)return false;char opera;int temp;result = *exp++-'0';while(*exp!='\0'){opera = *exp++;temp = *exp++-'0';if(opera=='+')result+=temp;elseresult-=temp;}return true;}
59. display of another loo
Dedecms imposes a limit on the title length of the article. The maximum length is 60 bytes, which is obviously not enough. The following are the modifications:1. Go to the dedecms background, and change the system-basic system parameters-other options-maximum length of document title-here to 200 or greater (in fact, 200 should be enough ).2. Run: System -- SQL command line tool -- input statement: alter table dede_archives modify title varchar (200)
Start the storyCondition: if the task level is greater than or equal to 60, the task is automatically obtained after the previous main task is completed.Plot processVictory over the door guard (battle) → Yin Wenjiao → victory over the prawns (battle) → The woodcut → find only the demon to the mountain god → victory over the crab (battle) → return the Dingyan beads to the turtles, → The Dragon King of the East China Sea → The Soul of Chen Guangrui → Yi
when you hate, suffer, or feel bad. Otherwise, you will regret it.
I have regretted it many times and it is hard to recover some things. Everyone must remember this sentence! ImpulsiveIt's the devil!
57. Never be curious about the possibility of a bad ending. Otherwise, it may take your life.
Dead cats! This sentence is from instructor Hu's hand.Pen, I feel like the atmosphere is getting rid of it ...... It's scary, but it does help us with our life principles.
58. Do not punish yourself with o
set to false unsuccessful"Tryself.driver.find_element_by_id ("Input1"). Send_keys (U "Shanghai-leisurely")self.driver.find_element_by_id ("Input2"). Send_keys ("xxx")# login ID is wrong, positioning will throw exceptionself.driver.find_element_by_id ("Signin"). Click ()# Determine if the Login Success page has an account: "Shanghai-leisurely"Time.sleep (3)Locator = ("id", "lnk_current_user")result = Ec.text_to_be_present_in_element (locator,u "Shanghai-Yo") (self.driver)Self.assertfalse (Result
Agera
Responsive programming on Android
One. Log frame
name
Description
Logger
Simple, beautiful, powerful Android logging tool
Hugo
Logging of the triggering method for annotations on debug builds
Timber
A small, extensible logging tool
12. Test framework
name
Description
Mockito
Mocking unit test frame
Title Description:Given a sorted array and a target value, the index is returned if the target value is found in the array. If not, return to the location where it will be inserted sequentially.You can assume that there are no repeating elements in the array.Have you ever encountered this problem in a real interview? YesSample Example[1,3,5,6], 5→2[1,3,5,6], 2→1[1,3,5,6], 7→4[1,3,5,6], 0→0challengesO (log (n)) timelabelArray sorting Array binary methodTopic Analysis:Given a sorted array and a ta
="App" >H1v-if=' Age >= ' >age: {{age}}H1>H1V-else>name: {{Name}}H1>H1>---------------------Split Line---------------------H1>H1v-show="Name.indexof (' keep ') >= 0" >name: {{name}}H1>H1V-else>sex: {{Sex}}H1>div> body> script src=" js/vue.js "> script> script> var vm = new Vue ({el: #app ', data: {Age: 28, Name: ' Keepfool ', Sex: ' Male '}}) script> HTML> v-elseWhether the element is rendered in HTML depends on the previous use v-if or v-show instruction.True in this code v-if , the
Dictionary format "' Curpath = Os.path.dirname (Os.path.realpath (__file__)) Yamlpath = Os.path.join (Curpath," Taobao.yaml ") prin T ("Config address:%s"% yamlpath) F = open (Yamlpath, "R", encoding= "Utf-8") A = F.read () f.close () # Turn Yaml file to dictionary d = y Aml.load (a) for I inD:if devicesname in i["desc"]: print (i) # start service devicesname = i[' desired_caps ' [' u Did '] Print (devicesname) start_appium (port=i[' Port '), Udid=devicesname) return (i[' desire D_caps '], i['
Answer reference: 23322951Title Link: https://leetcode-cn.com/problems/permutation-sequence/description/Title Description:Code See below:classSolution { Public: stringGetpermutation (intNintk) {vectorint> num (n,0); intPerm_sum =1; for(size_t i =0; I i) {Num[i]= i +1; Perm_sum*= (i +1); } stringret; //since the array is from 0 to n-1, the cardinality is from 0 to K-1--K; for(size_t i =0; I i) {perm_sum= Perm_sum/(N-i); intSelected = k/perm_sum; Ret.push_back (num[selected]+'0'); //re
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