fundamentals of information systems security second edition
fundamentals of information systems security second edition
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20145306 "Fundamentals of Information Security system Design" 14th Week study summary textbook Learning content Summary physical and virtual addressingPhysical addressing: The main memory of a computer system is organized into an array of cells consisting of m contiguous byte sizes. Each byte has a unique physical address of Pa. The address of the first byte is 0
2018-2019-1 20165316 "Information Security system Design Fundamentals" the second week to summarize the learning contents of the teaching materials
Small end, low address to low, high address to high; You can determine the size and end type of a machine by forcibly extracting a byte of storage from either the cast or union.
A logical operation has on
Floating-point arithmeticIEEE floating point representation: v= ( -1) s x M x 2E (sign S, Mantissa M, order E)Round to even (default): Rounds a number up or down, and the least significant number of results is even. Can be used in binary decimals.Rounds to 0: rounds the integer down, and the negative number rounds up.Round down: Both positive and negative numbers are rounded down.Round up: Both positive and negative numbers are rounded up.Code hosting other (sentiment, thinking, etc., opti
specified as a double word, the size of the block is the integer multiple of the double word, not the rounding to Yes.Explicit idle linked list
Difference(1)分配时间 隐式的,分配时间是块总数的线性时间 但是显式的,是空闲块数量的线性时间。(2)链表形式 隐式——隐式空闲链表 显式——双向链表,有前驱和后继,比头部脚部好使
Sorting policy:?后进先出?按照地址顺序维护Detached List of idle links
Separating storage is a popular way to reduce allocation time. The general idea is to divide all possible block sizes into equivalent class/size classes
The allocator maintains an a
exception.
The typical errors are:scanf("%d",val);
(2) Read uninitialized memory
Although the bass memory location is always initialized to 0 by the loader, it is not the case for heap storage.
A common mistake is to assume that the heap memory is initialized to 0.
(3) Allow stack buffer overflow
If a program writes to the target buffer in the stack without checking the size of the input string, the program will have a buffer overflow error.
(4) Assume t
)That is, the number is rounded up or down, and the lowest valid number of the result is even.Can be used in binary decimals.2. Rounding to 0That is, rounding down integers and negative numbers rounded up.3. Rounding DownBoth positive and negative numbers are rounded down.4. Rounding upBoth positive and negative numbers are rounded up.Iv. floating-point arithmetic 1. floating-point addition
Floating-point addition is exchangeable
Floating point addition not binding
The floating-
summary of the wrong quiz
Wrong question 1 and reason, understand the situation
Wrong question 2 and reason, understand the situation
...
Other (sentiment, thinking, etc., optional)XxxXxxLearning progress Bar
lines of code (new/cumulative)
Blog Volume (Add/accumulate)
Learning Time (new/cumulative)
Important Growth
Goal
5000 rows
30 Articles
400 hours
First week
200/200
2/
20145321 "The basis of information security system Design" 7th Week study summary textbook study content summary sixth chapterA memory system is a hierarchical structure of storage devices with different capacities, costs, and access times.6.1 Storage TechnologyThree common storage technologies: ram/rom/disk(1) Random access memory RAM
There are two categories: Static RAM (SRAM) and dynamic RAM (DR
that there are already compiled. yo files that can be viewed with vimThe code in Figure 4-7 of the No. 239 page of the textbook, called Asum.yo in the system, prints its contents on the screen:It can be seen that the results are consistent with the 240 pages of the textbook.Textbook page No. 251 of Figure 4-17, I first used to build a 417.ys enter after entering:Then compile with make 417.yo and use Vim to enter 417.yo after compiling.Reference, I saw Shang she summed up than I have more organi
Tags: alt padding command ble language jump Edit RDA SystemStack traceFirst edit a program Compile with GCC, then debug with GDB and find GDB has not been downloaded Re-run gdb after download Set Breakpoint: B + line number or "main" Run: R Frame: The printed information: the stack's layer number, the current function name, the function parameter value, the file and line number where the function is located, and the statement to which the functio
solutionissue: After you open HyperTerminal, The information on the arm machine is never displayed in the HyperTerminal window. solution: Found the reason, is the serial cable connected to the wrong location, should not be connected to 1, after replacing 0 , HyperTerminal will show normal. (2)IP problems and Solutionsproblem: Need to put the lab box, virtual machine the IP of Redhat,WinXP is set to the same network segment. FIX: First look at the lab
expressed in the desired floating-point form.1. Rounding to even numbersRounds a number up or down so that the lowest effective number of the result is even.2. Rounding to 03. Rounding up4. Rounding Down34 you can see the upper bound.Rounding to even gets the closest match.4. Floating-point arithmeticFloating-point addition: exchangeable, non-associative, satisfying monotonicityFloating-point multiplication: exchangeable, non-associative, non-assignable, satisfies the following monotonicityFloa
, and n = 23 bits respectively, resulting in a 32-bit representation;In a double, the S, exp, and Frac fields are 1 bits, k = 11 bits, and n = 52 bits, respectively, and a 64-bit representation is obtained.Problems in Learning:(1) about overflow:Due to the inherent flaw of C/D + + language, neither checking the array boundary nor checking type reliability, and the program developed in C + + language because the target code is very close to the machine core, so it can directly access the memory a
misses/number of references
Hit Ratio = 1-No hit
Hit time
No hit penalty: Because of the extra time required to miss the
2. Specific impact:
Cache Size: Hit ratio +, hit Time +
Block Size: Spatial locality +, hit ratio +, number of cache rows-, time locality-, no hit penalty +
Degree of coupling: E value big, jitter-, Price +, hit Time +, no hit penalty +, control logic + "compromise for not hit penalty low, low degree of coupling, not hit penalty high, use hig
that divides the cache into chunks, transfers blocks between different tiers, determines whether they are hit or miss, and processes themCache memoryGeneral-Purpose Cache Memory Architecture:Each memory address has a M-bit, which forms m=2^m different address cache groups: Array cache lines for S=2^s cache groups: b=2^b bytes of data blocks make up a valid bit: Indicates whether the row contains meaningful information marker bits: Uniquely identifies
non-gate or non-gate
HCL integer Expression
Case Expression Format:
[ select 1: expr 1 select 2: expr 2 . select k: expr k ]
Set Relationship:iexp in{ iexp1,iexp2,...iexpk }
Arithmetic/logic unit (ALU)
Sequential implementation of Y86-64
Organize the processing into stages
Value fetch--> decoding decode--> performing execute--> memory--> writeback write back write back--> update PC update
SEQ
/12
20/200
Learn the contents of system level I/O and understand the intrinsic function
Tenth Week
407/1035
1/13
30/230
Analyze and debug your code, system-level I/O content
11th Week
714/1749
2/15
40/270
Understanding anomalies and their types
12th Week
0/1749
4/19
30/300
Review the contents of the previous weeks
13th Week
797/2728
2/21
20/320
Learn t
handler is called, the new signal screen word created by the system automatically includes the signal being delivered. This ensures that when a given signal is processed, if the signal occurs again, it will be blocked until the end of the processing of the previous signal; The response function is set to be valid and not resetThe implementation of sleep () should be divided into three steps:
Register a signal signal (sigalrm,handler).
Call the alarm () function.
Pause () suspen
status code stat from the result of the instruction execution, based on Icode,imem_error,instr_valid,dmem_error.
update pc stage
generates a new value for the program counter, depending on the type of instruction and whether to select the branch, the new PC may be valc, Valm, or Valp.
Please explain why there is only one if statement in the C language code, and the assembly code contains two conditional branches?A: The first conditional branch is part of th
1. Machine-Level Code(1) Two kinds of abstract
Defines the format and behavior of machine-level programs by ISA
The memory address used by the machine-level program is the virtual address
2. Data format3. Operand designator4. Press in and eject stack data
Follow the principle of first in and out
Push Press in, pop delete
Pushq press four words into the stack popq four words pop-up stack
5. Arithmetic and logical operations
LEAQ Load Valid address
INC plus a
D
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