fundamentals of information systems security second edition

week's exam error summary 1.The following jump commands are related to ZF ()A. jmpB. JeC. jsD. JaE. JBF. JbeAnalytical:2.Assuming that the function of the C-expression T=a+b is completed with the add instruction, the correct statement about the condition Code Register is ()A. If t==0, then zf=1B. If tC. If tD. if (aE. if (aF. LEAQ directive does not affect the condition code registerG. CMP directives do not affect the condition code registerAnalysis: Textbook p135ZF: 0 logo. The result of the r

I. Learning Objectives Understanding the role of ISA abstraction Master Isa, and be able to learn other architecture extrapolate Understanding the pipeline and how it is implemented Second, the Learning content y86-64 directive MOVQ directive IRMOVQ rrmovq mrmovq RMMOVQ Four integer manipulation instructions Addq,subq,andq,xorq only the Register data 7 Jump Instructions Cmovle cmovl cmove cmovne cmovge CMOVG The call command returns the address to the stack, and then j

1.Y86-64 Instruction Set architecture①Y86-64 directive MOVQ directive IRMOVQ rrmovq mrmovq RMMOVQ Four integer manipulation instructions Addq,subq,andq,xorq only the Register data 7 Jump Instructions Cmovle cmovl cmove cmovne cmovge CMOVG The call command returns the address to the stack, and then jumps to the destination address, and the RET instruction returns from such calls Pushq and POPQ instructions are implemented into the stack and out of the stack Execution of Halt

specific framework is divided into four categories: 1. For OPL (integer and logical Operations), RRMOVL (register-register transfer) and IRMOVL (immediate count-register transfer)2. For RMMOVL and MRMOVL3. For PUSHL and POPL4. For jump, call and RET The summary is that the clock is used to control the updating of the state elements, and the values are propagated by the combinatorial logic. ExperimentAfter you run the make commandTo view the contents of the directory, you can see o

20145311 "Information Security system Design Fundamentals" The 14th Week study summary textbook Learning content Summary1. Physical AddressingThe main memory of a computer system is organized into an array of cells consisting of m contiguous byte sizes. Each byte has a unique physical address of Pa. The address of the first byte is 0, the next byte has an address

2018-2019-1 20165329 "Information Security system Design Fundamentals" 4th Week Study SummarySummary of learning contents of textbook Y86-64 directive: The y86-64 instruction is a subset of the x86-84 instruction set. It includes only 8-byte integer operations. There are 4 integer operations directives: ADDQ, SUBQ, ANDQ, and Xorq. There are 7 jump commands: j

2018-2019-1 20165210 "Information Security system Design Fundamentals" 4th Week study summary Textbook Learning content Summary ISA Concept: The byte-level encoding of a processor-supported instruction and instruction is called its instruction set architecture Isa.While the processor performance and complexity of each manufacturer is increasing, the

2018-2019 20165227 "Information Security system Design Fundamentals" The third week to learn to summarize learning objectives Understanding the concept of reverse Master X86 compilation base, able to read (reverse) Assembly code Understanding ISA (Instruction set architecture) Understand the concept of function call stack frames and can debug

2018-2019-1 20165333 "Information Security system Design Fundamentals" Third Week study summarySummary of learning contents of textbookThe machine-level representation of the program:Two important abstractions of computer systemsISA (Instruction set architecture): Instruction set architecture, machine-level program format and behavior. Defines the format of the p

2018-2019-1 20165336 "Information Security system Design Fundamentals" Fourth week study summary 1. The knowledge points learned in the textbook The states that are visible to programmers (assembler programmers, compilers, and so on) in y86-64 include program registers, condition codes, program states, program counters (PCS), memory Y86-64 15 Program regist

architectureHow is the sequence of processor architectures implemented?fifth. Optimizing Program PerformanceHow does the compiler generate efficient code, and what short board does he have?Sixth chapter Memory hierarchyHow to determine if a memory unit is in steady stateSeventh Chapter LinksWhen and how can a link be done?eighth. Abnormal control FlowHow does exception control flow work at every level of the computer?nineth Chapter Virtual MemoryWhat are the three important features that virtua

lines of code (new/cumulative) Blog Volume ( new/cumulative) Learning time (new /cumulative) Goal 5000 rows 30 Articles 400 hours First week 100/100 1/2 10/10 Second week 150/200 2/4 8/18 Third week 200/250 1/5 5/23 Week Five 50/300 1/6 9/32 Week Six 20/320 1/7 8/40 Seventh Week

can not open, Later according to Zhangxiaohan classmate blog written steps to do, finally installed successfully.Learning progress Bar lines of code (new /Cumulative) Blog volume ( new/cumulative) Learning time (new/cumulative) Important growth Goal 3000 rows 30 Articles 300 hours First week 0/0 1/2 25/40 Learn Linux basics and Core commands Second week 0/0 0/2

parent process is the same as the Descriptor table, file table, V-note tables correspondence and child processes. Descriptor FD points to the same file table entry in the parent-child process. So when the child process has finished reading, the parent process reads O, and the output O10.4:Dup2 (A, A, b) refers to the redirection of a to a, and a copy to the B standard input descriptor is 010.5:Dup2 (FD2,FD1) fd2 Copy to Fd1,fd1 is redirected to FD2. So after performing the read again, the outpu

descriptor table entry OLDFD to the Descriptor table entry NEWFD, overwriting the previous contents of the Descriptor Sheet table entry newfd. If the NEWFD is already open, Dup2 will close NEWFD before copying the OLDFD.#include int dup2(int oldfd,int newfd);8 Standard I/OThe standard I/O library models an open file as a stream, which is a pointer to the structure of the file type.#include *stdin; /*标准输入，文件描述符为0*/extern FILE *stdout; /*标准输出，文件描述符为1*/extern FILE *stderr; /*标准错误，文件描述符为2*/A strea

shift x>>k: Move the K-bit right and the value at the left to complement K's most significant bit Logical right Shift x>>>k: Move K-bit right, left complement K 0 Use arithmetic right shift for signed number, logical right shift for unsigned numberInteger representation Information = bit + context unsigned integer: b2u4[0011]=0 2^3+0 2^2+1 2^1+1 2^0=3 Signed integer-complement code: B2t4[1011]=-1 2^3+0 2^2+1 2^1+1 2^0=-5 Uns

) or positive (s=0), and the sign bit with the value 0 is interpreted as a special case.Mantissa: M is a binary decimal order: E is weighted against floating-point numbers and can be negativeFloat:s=1 bit, exp=8 bit, frac=23 bitDouble:s=1 bit, exp=11 bit, frac=52 bit2. Integers and floating-point numbers indicate the relationship of the same number:P74: The relative region corresponds to the low of the integer, just before the highest significant bit equal to one stop, and a floating point repre

FeelingsJust beginning to touch Java, feel both confused and hard, because they have not been in a self-learning way to contact a new programming course, long time to find more difficult. I think, teacher and student relationship is eldest brother and brother! Why do you say that, because the teacher experienced the student age and more understanding of the situation of students, leading students to learn and impart some experience, so that students less detours, and exchange ideas with students

processor design, it is often necessary to compare a signal to a number of possible matching signals to detect if a certain instruction code being processed is part of a class of instruction code.Sequential implementation of Y86-64Organize the processing into stages1. For OPL (integer and logical Operations), RRMOVL (register-register transfer) and IRMOVL (immediate count-register transfer)2. For RMMOVL and Mrmov3. For PUSHL and POPL4. For jump, call and RETTake a fingerDecodingPerformVisitWrit

Summary of the learning contents of the textbook fourth Chapter processor Architecture Y86-64 instruction set architectureThe "programmer" here refers to the person who writes the program with the assembler code, or the compiler that produces the machine code . The state of y86-64 is similar to x86-64.Y86-64 directive X86-64 's MOVQ instruction is divided into 4 different instructions: IRMOVQ,RRMOVQ,MRMOVQ,RMMOVQ, which explicitly indicates the source and destination format, and the source