girls having fun with boys

First of all, the height of a girl may not be able to pay attention to the height of a girl at first glance. She may not have noticed your appearance at all, but the height left her with an impression, this is the height line of the lover in her dream. Then there is a hair style. When a girl looks at a boy's hair style, she doesn't know how handsome the boy's hair is, but she looks at the boy's hair neatly and cleanly. If she looks very clean, she scores a lot again. Third, it is also unreason

program should write to standard output a line containing the result.Sample Input70: (3) 4 5 61: (2) 4 62: (0) 3: (0) 4: (2) 0 15: (1) 06: (2) 0 130: (2) 1 21: (1) 02: (1) 0Sample Output52Maximum Independent set = Total number of points-maximum matchesBecause the number is enlarged by twice times, the maximum number of matches should be divided by 2.#include #includestring.h>#include#include#include#defineN 510#defineINF 0x3f3f3f3fusing namespacestd;intG[n][n], vis[n], used[n];intN;BOOLFind (in

) {Vis[e[a][i]]=1; if(match[e[a][i]]==-1||DFS (Match[e[a][i])) {Match[e[a][i]]=A; return 1; } } } return 0;}intMain () { while(SCANF ("%d", n)! =EOF) {memset (match,-1,sizeof(match)); for(intI=0; i) e[i].clear (); M=N; for(intI=0; i) { intx, y; scanf ("%d: (%d)",x,y); for(intj=0; j) { intC=read (); E[x].push_back (c); } } intans=0; for(intI=0; i) {memset (Vis,0,sizeof(VIS)); if(Dfs (i) = =1) ans++; } printf ("%

{ +scanf"%d: (%d)", q, m); - for(inti =1; I ) the { *scanf"%d", GG); $MAP[Q][GG] =1;Panax Notoginseng } - } the intsum =0; + for(inti =0; I ) A { thememset (Vis,0,sizeof(Vis)); + if(Dfs (i)) -sum++; $ } $printf"%d\n", n-sum/2); - } - return 0; the}1#include 2#include 3#include 4 using namespacestd;5 intmap[1010][1010], dis[1010], vis[1010];6 intN;7 BOOLDfs (inta)8 {9 for(inti =0; I )Te

(The following stories are purely fictitious. If there is a similar story about your infringement .) The boy and the girl met for the third time. This is the second day of the meeting. The girl said she was going shopping with her mother to buy clothes. The boy was caught off guard because when he went with the girl yesterday, they said they were going to visit the girl's alma mater today and didn't say they were going to buy clothes. Without it, accompanied.

There is such a couple. the girl is very beautiful and considerate. Sometimes she has some bad ideas to play with boys. boys are very smart and sensible, the most important thing. A strong sense of humor. you can always find a way to make girls laugh when they get together. girls like

If you don't want to accept this guyYou 'd better reject him in a better way. First, let's say:1. As a friend"We can still be ordinary friends"This is true for girls. Naturally, it is subjective to reduce the pain points of boys.But in this case, being a friend is actually a failure for boys to emphasize being a lover.His wishes cannot be fulfilled, and he must constantly emphasize his failure.He will be mo

Click Open Link Bipartite Graph Matching, hopcroft-Karp #include Girls and boys

Simple question.#include #include#include#include#include#include#include#includeusing namespacestd;Const intmaxn=100000;structx{stringname; stringsex; stringID; intC;} S[MAXN];intN;intMain () {scanf ("%d",N); for(intI=1; i) Cin>>s[i].name>>s[i].sex>>s[i].id>>s[i].c; intid1=-1, id2=-1; intmax=-1, min=99999; for(intI=1; i) if(s[i].sex[0]=='F's[i].c>max) max=s[i].c,id1=i; for(intI=1; i) if(s[i].sex[0]=='M's[i].ci; if(id1==-1) printf ("absent\n"); Elsecout" "Endl; if(id2==-1) print

that there may be romance between the two opposite sex in the school, it is time to find a group of people who have no romance between them and seek the maximum value of this number. Obviously the problem of the maximum independent set, but because do not know the gender of each person, so the two point set of the binary graph is everyone n, so that the maximum match is the true maximum match twice times, the answer is N-Max match/2#include #include #include #include #include #include #include

I believe that a lot of people who just do mom and dad in the child bag diapers, there will be a misunderstanding, is that the boy and girl bag law is the same, hehe, actually, there will be some differences between men and women.Female baby urination compared to, urine usually back flow, you can choose in the rear of the hips more cushion some diapers, or the corresponding position of the diaper folded into a double. You can also buy a pad, mat under the baby's sheets, so that even if "flood",

classJob.setpartitionerclass (Genderpartitioner.class); //the number of reduce is set to 3Job.setnumreducetasks (3); //Input PathFileinputformat.addinputpath (Job,NewPath (args[0])); //Output PathFileoutputformat.setoutputpath (Job,NewPath (args[1])); //Submit a Task returnJob.waitforcompletion (true)? 0:1; } Public Static voidMain (string[] args)throwsException {string[] args0= { "Hdfs://ljc:9000/buaa/gender/gender.txt", "Hdfs://ljc:9000/buaa/gender

This is asked to tell the difference between the lowest grade of all the male students and the highest grade of All the female students.Input Specification:Each input file contains the one test case. Each case contains a positive an integer n, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID is strings of no more than characters with no space, gender is either F (female) or M (male), and grade are an in

#include HDU 1068 Girls and Boys (two-part graph matching)

} the } + } - $ return false; $ } - - intHungary () the { - intcn1=0;Wuyi for(intI=0; i) { theCLR (F,0); - if(Find (i)) ans++; Wu } - returnans; About } $ - intMain () - { - intu,v; A + while(~SCANF ("%d",N)) { the init (); - for(intI=0; i) { $scanf"%d: (%d)",u,m); the while(m--){ thescanf"%d",v); theg[u][v]=1; the } - } inprintf"%d\n", N-hungary ()/2); the } the About