glc bx u

This is a created article in which the information may have evolved or changed. Project Address Github.com/xuri/glc Brief introduction GLC (Glog Cleaner) is the Go language written glog log cleanup class library, Glog is developed by Google, an application-level log framework, providing log grading, file segmentation and other functions, but does not provide log cleanup function, with

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1.[BX] and memory unit[BX] refers to the segment address in the DS, offset address in BX in the memory unit2.loopUsed to describe loops3. We define the descriptive symbol "()"Register: (ax/al) represents the contents of the Ax/al registerSegment Register: ((DS) *16+ (BX)) indicates that the segment address is DS conten

5.1 [BX] and [0] Similar [0] Indicates the offset address length, the segment address is default in BS, However [0] in debug is not the same as in ASM, [0] in ASM after ML will become the value of 0 To solve MOV ax,[1] after AXM compiled into MOV ax,1; can be written mov ax,ds:[1] Four kinds: mov Al,[0];mov al,ds:[0];mov Al,[bx];mov DS:[BX] Loop: Related to Loo

MOV Ax,[0] put an internal deposit element to register AX, memory unit length 2 bytes, offset address 0, segment address DSMOV Al,[0] put an internal deposit element to register AL, memory unit length 1 bytes, offset address 0, segment address DSSo: To describe a memory unit, you need 1.ds and offset address 2. Memory Unit length[BX] also represents a memory unit, offset address in the register BX justWe us

This chapter mainly describes what is [BX] and loop (loop) instruction how to use, loop and [BX] how to combine, what the paragraph prefix is what ghosts, and how to use the paragraph prefix. 1, [BX] concept [BX] and [0] similar, [0] indicates that the memory unit offset address is 0. To fully describe a memory unit, y

To find the root of the equation ax^2+bx+c=0, consider respectively: 1, there are two unequal real roots 2, there are two equal real roots # include "C language" to find the root of the equation ax^2+bx+c=0, respectively, consider: 1, there are two unequal real roots 2, there are two equal real roots

Jump instruction is used to implement the program flow jump, in the ARM program there are two ways to achieve the program flow jump: (1) use special jump instructions. (2) write the jump address value directly to the program counter PC. By writing the jump address value to the program counter PC, you can achieve any jump in the 4GB address space, and use it together before jumping MOV LR, PC

[BX]Because in the compiler mov ax,[0] instruction will be considered by the compiler to be MOV ax,0 so introduced the concept of [BX]mov [bx],ax means to assign the value of the (DS) *16+ (BX) memory location to Microsoft Dynamics AXUse the same as before Ds[address]Small Tips1 ;How to use [

Getting started with crazy summer vacation Study Notes (4) -- [BX] and loop commands Reference: Chapter 5th of Assembly Language 1. [BX] MoV Al, [1] In debug, data in BS: 1 is assigned to Al, but data in BS: 1 is not assigned to Al in MASM, instead, [1] is considered to be 1 assigned to Al. If you want to implement mov Al, [1] In debug, you need [BX] In MAS

// Obtain the root of the quadratic equation ax2 + bx + c = 0. The values of coefficients A (a = 0), B, and C are input by the keyboard. # Include # Include Using namespace STD; // Root Float get_x (float a, float B, float C) { Float x1, x2, X; If (B * B-4 * a * C { Cout } Else if (0 = B * B-4 * a * C) { X = (-B)/2/; Cout } Else { X = SQRT (B * B-4 * a * C ); X1 = (-B + x)/2/; X2 = (-B-x)/2/; Cout } Return 0; } Void main () { Flo

A middle school student asked me how to find the root of the quadratic equation of one yuan over the past few days. I was so stupid that I didn't know where to start. At that time, I remember that I could never remember the formula, during the examination, it took a lot of time to calculate the formula. The formula calculated from the results is often less than the plus or minus sign. Calculate the formula again this time, As a result, the student said that this formula was very familiar and fou

[BX] and [0] somewhat similar, [0] represents a memory unit, its offset address is 0, the same [BX] also represents a memory unit, its offset address in BX.Loop, the English word "loop" has a circular meaning, obviously this instruction is related to the loop.We agree that the symbol idata represents a constant, one thing to note here is that it is not possible to send a idata data directly into the segment

[BX] indicates a memory unit, and its offset address is in BXMoV Al, [BX]The description symbol () to indicate the content in a register or memory unit.The agreed idata symbol represents a constant.Loop labelWhen the CPU executes the loop command, there are two steps: 1. (CX) = (CX)-1; 2. judge the value in CX. If it is not zero, it is transferred to the label to continue execution, otherwise, execute the f

The solution of ax^2+bx+c=0 equation is obtained by C language.#include #include #define M 0.000001int main (){float a,b,c,x,x2,n,q,p;scanf ("%f%f%f", a,b,c);N=b*b-4*a*c;if ((a{x= (-c)/b;printf ("%f", X);}else if ((n{x= (-B)/(2*A);printf ("%f", X);}else if (n>0){X= ((-B) +sqrt (n))/(2*A);X2= ((-B)-sqrt (n))/(2*A);printf ("%f\n%f", x,x2);}Else{q= (-B)/(2*A);P=sqrt (-N)/(2*a);printf ("%f+%fi\n", q,p);printf ("%f-%fi\n", q,p);}}Solving the ax^2+

Find the root of Equation ax^2+bx+c=0 # include "C language" to find the root of equation ax^2+bx+c=0

This article comes from: http://baike.baidu.com/view/6159.htm8086 has 14 16-bit registers, which can be divided into (1) General registers, (2) instruction pointer, (3) mark register and (4) segment register. There are 8 General registers, which can be divided into two groups. One is the data register (4), the other is the pointer register and the address register (4 ). as the name suggests, general-purpose registers are those that you can use as needed. modifying their values usually does not h

PurposeGLC coastline network security information site In Windows 2000, the user password is a system Double-click "Telnet" to open its Properties window, as shown below. Then, change the "Startup Type" to "automatic" so that the telnet server can run automatically after Windows 2000 is started. Then, click the "Start" button to make it "started, click OK to save and exit. GLC coastline network security information site 2. Modify NTLM to verify the

Sidi is a register with similar functions between 8086cpu and BX. Sidi cannot be divided into two 8-bit registers. The following three sets of commands implement the same functions: (1) mov BX, 0 MoV ax, [BX] (2) mov Si, 0 MoV ax, [Si] (3) mov Di, 0 MoV ax, [di] The following three sets of commands also implement the same function: (1) mov

[deltay],1; Change this and watch what mov [deltaz],1; Happens. It ' s fun! mov [xoff],256 mov [yoff],256; Used for calculating Vga-pos mov [zoff],300; Distance from Viewer Mainloop: Call Mainprogram; Yep ... do it all ...;-) In al,60h; Scan keyboard CMP al,1; Test on ESCAPE Jne Mainloop; Continue If not keypressed ; = = = Quit to DOS = = MOV ax,0003h; Back to TextMode int 10h Lea Dx,[credits] MOV ah,9 int 21h MOV ax,4c00h; return control to DOS int 21h; Call DOS Interrupt ; = = = Sub-routines