good birthday gift for girlfriend

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Give a gift to your girlfriend for romance

stories behind him could not be remembered. I only remember that I thought, "Dizzy, This is the civilized world of the United States !". Now, let's take a look at our motherland... Haha, let's get down to the truth... Do I need a reason to give gifts to my girlfriend? (Relationship between gifts and occasions) In general, giving gifts should pay attention to occasions (birthday, anniversary, appointment, V

How do Programmers Make girlfriends happy and customize an app (birthday gift) for their girlfriends)

Tags: Android style blog HTTP ar SP file Div on This is a complete Android app written by me, but in fact it is not very complete. There are still many other features that have not been added, but yesterday was my girlfriend's birthday, so I gave it to him. This is the first app I used to study Android for half a month. "music player "! It took two days to complete the production process, from conception to completion. Many of them were not perfect,

CODEVS1815 BSOJ2971 Birthday gift DP or randomization _DP

2971--"mock test" birthday present Description a pair of twin siblings on the same day birthday, this day, their friends sent them a gift, each gift is 2 books, one to his brother, one to his sister, but did not say which is for the sister, which is to the brother,   Each book has its own value, in order to avoid confl

How do programmers get friends happy and customize an app (birthday gift) for their girlfriends)

This is a complete Android Application I wrote, but it is not complete yet. There are still many other functions that have not been added, but yesterday was my girlfriend's birthday, so I gave it to him. This is the first app I used to study Android for half a month. "music player "!It took two days to complete the production process, from conception to completion. There were still many imperfections, the UI was ugly, and the layout was messy! The mai

The first birthday gift for your life-JAVA games!

Abstract: I amGuangdong Institute of petrochemical technologyOneFreshman, BecauseMobile DevelopmentI am very interested, so I learned the basics of Java in my free time during the summer vacation.Today is me.20 years oldOfBirthdayIt's not easy to think about it. After 20 years, I didn't give myself any gifts. So today I spent a little time writing a Java game as my birthday gift!When I went to college, I li

HDU 5171 GTY & #39; s birthday gift matrix fast power, hdu5171

HDU 5171 GTY's birthday gift matrix fast power, hdu5171Click Open LinkGTY's birthday giftTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission (s): 225 Accepted Submission (s): 78Problem DescriptionFFZ's birthday is coming. GTY wants to give a

Birthday gift (to be modified)

Turbo C 2.0 is an excellent C language programming tool in the DOS era, but the majority of users are currently using Windows operating systems. If you want to call a graphic animation program written in C language in windows. there may be many errors that cannot be displayed in graphic animation. This is because the image processing function of C cannot be accurately located on the Windows interface. Therefore, when using the initgraph () function in Turbo C for graph initialization, you must c

[Best Coder] #29 B GTY & #39; s birthday gift (Fast Power | remember to bear it when mod !),

[Best Coder] #29 B GTY's birthday gift !), You can view the related sessions.Idea: the question of the push formula can be quickly solved by using the rapid power-plus formula, or the speed can be accelerated by using the binary splitting method.Note that, in the future, a mod should be added after mod for operations, or a uniform mod should be added.By the way, let's review the binary splitting method !!T

Bzoj2288 birthday gift (line segment tree)

Of course I want to select the largest child segment and the greatest child segment. But if I want to select m, it is not necessarily the best. Therefore, we provide an option to repent. After selecting a paragraph, I will multiply them by-1 and then select the best one (similar to the idea of network flow) This can be maintained by using the line segment tree, recording that a range contains the maximum and minimum values of the left and right endpoints (because it must be multiplied by-1) and

Bzoj 1293 scoi2009 birthday gift heap

Tags: bzoj bzoj1293 heap Given N points on a number axis, each point has a color. k colors are used in total to find a shortest interval, including all k colors. After a while, 0.0 first thought about the second answer, and later found that the data range was too large to write 0.0. Later, I went to the question to find out that Nima was really clever. Maintain a heap and add the first beads of each color to the heap. Then, remove the leftmost beads, add the next beads of this color, and update

[Heap] bzoj1293 [scoi2009] birthday gift

The method of taking the poj3320 ruler is basically the same as that of the question, but the range of the question is 2 ^ 31.Sort the position of each bead.Maintain a pointer for each type of beads to indicate which beads of this type are used.Therefore, the ruler acquisition method is optimized by the heap. Each time the smallest value is taken from the heap, the head pointer of the ruler acquisition method is moved backward.Then a position (pointer ++) is taken from the back of each bead (whi

Luogu P2564 [SCOI2009] Birthday Gift (queue + simulation)

Transmission DoorThinking of solving problemsIt is better to think, with a queue, and then put all the points together in order, in turn queued. Each time you check the type of the team head element is the current queue element type, yes, the words have been \ (pop\), each update answer can be.Code#include Luogu P2564 [SCOI2009] Birthday Gift (queue + simulation)

[bzoj1293] [SCOI2009] Birthday Gift

]; the build (i); -now[i]:=J; in End; them:=K; the fori:=1 toN Do About begin thelc[i]:=heap[1].c; theln[i]:=heap[1].x; theSwap (heap[1],heap[m]); + Dec (m); -Update1); thenow[lc[i]]:=Next[now[lc[i]];Bayi ifNow[lc[i]]0 Then the begin the Inc (M); -heap[m].x:=Q[now[lc[i]]; - build (m); the End; the End; theh:=1; theFillchar (sum,sizeof (sum),0); -t:=1; theans:=Maxlongint; thesum[lc[1]]:=1; the fori:=2 toN Do94 begin the Inc (Sum[lc[i]); the ifsum[lc[i]]=1 ThenInc

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