gray pebbles

There is n piles of pebbles on the table, the i-th pile contains ai p Ebbles. Your task is-to-paint each pebble using one of the K given colors so, for each color c an D any II piles i and J The difference between the number of pebbles of color c color c in pile J are at the most one. In and words, let's say that b i , c is The number of pebbles

Title Link: PebblesTime limit:3000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 1504 Accepted Submission (s): 865Problem Descriptionyou ' re given an unlimited number of pebbles to distribute across a N x N game board (n drawn from [3, ), where each square on the board contains some positive point value between and the inclusive. A 6 x 6 board might look like this:The player distributes

=0; jj) { - if(isOK (Sta[i],sta[j])) Vec[i].push_back (j); Wu } - } About for(intI=1; ii) { $ for(intj=0; jj) { - for(intk=0; K!=vec[j].size (); ++k) D[i][sta[j]]=max (d[i][sta[j]],d[i-1][sta[vec[j][k]]); - for(intk=0; kk) { - if((sta[j]>>k) 1) d[i][sta[j]]+=A[i][k]; A } + } the } - intres=0; $ for(intI=0; ii) { theRes=max (res,d[n-1

Label: style Io AR for SP on amp EF BS There is a matrix of N * n (3 Question: The s array is in a valid state, that is, the number of binary values not adjacent to each other is selected at the same time. sum [I] [J] indicates the sum of the numbers in the J state of row I, in DP, you only need to enumerate the status of the previous row and determine whether it is feasible. Then, you can transfer the optimal solution of each valid state of this row. #include HDU 2167

The focus of block creation is the texture part. You need to use a variety of filters to make a preliminary texture, and then use a deformation tool to make the desired effect. You can simply overlay the final color later. The focus of block creation is the texture part. You need to use a variety of filters to make a preliminary texture, and then use a deformation tool to make the desired effect. You can simply overlay the final color later. The focus of rock creation is the texture part. You ne

This problem once again made no initialization of the problem, but the sample actually only the 2nd group is wrong, the others are right ... And it's impossible to debug ....The problem is still a very simple form of pressure. Or the state of each row is preprocessed first. Then the state shifts from the first line down. In order to not tle, should be in each state and also pre-treatment.The code is as follows:#include HDU 2167 Pebbles (pressure DP)

Turn from http://www.cnblogs.com/tiandsp/archive/2012/01/07/2316006.html thanks to DSP TianClearCLCimg = imread (' 124.jpg '); % Read image from graphics file[m n T] = size (IMG); % Get pattern sizemax = 0;min = 256;Avg = 0;For I =1:1:mfor j = 1:1:nIf IMG (i,j) Min = img (i,j);EndIf IMG (i,j) >maxMax = img (i,j);EndAVG = AVG +double (img (i, j));EndEndAvg = uint8 (avg/(m*n));MNTMaxMinAvgHow to read and write image files in MATLAB and simple processing of imagesThe MATLAB image processing Toolbox

"089-gray Code (Gray code)""leetcode-Interview algorithm classic-java Implementation" "All topics Directory Index"Original QuestionThe gray code is a binary numeral system where the successive values are differ in only one bit.Given a non-negative integer n representing the total number of bits in the code, print the sequence of

In the code of a group of numbers, if any two adjacent code is different from only one binary number, it is said that this code is gray code (gray code), gray code is composed of 0 and 1, the binary code evolved.The Gray code generation method is as follows: 1-bit gray