In recent years, unsupervised learning has become the focus of research, with little left to be picked with supervised learning of low branches of fruit. The models of VAE (variational auto-encoder, variable-encoder) [1,2] and GAN (generative adversarial Networks) are becoming more and more concerned.
The author has also been studying the knowledge of VAE (from the perspective of depth learning). First of a
Q: How do i customize a harmonic path in CorelDRAW?
A: First to reconcile a object to B-Object line harmonic effect, and then draw a path, click the property bar in the path properties-New Path button, then go to the path curve, the path will be interactive gradient. (This method is universal for graphics, text, and combination patterns).
The blending tool can be used in CorelDRAW to draw light and shade
Although the various advantages of the Frequency Conversion Power supply can be widely used in various industries, the frequency conversion will generate a kind of Power Harmonic that has some harm to the machine equipment during operation. What kind of harm will this harmonic wave cause to peripheral electrical equipment? The technicians at Yangsheng zhonggang have sorted out some electric
One of the Spigot algorithms is used to calculate the sum of harmonic series and spigot series.Zookeeper
I first noticed Spigot-Algorithm in [1]. This Algorithm was released quite early. For details, see [2]. [1] Several amazing programs are provided. Only a small amount of code can be used to calculate constants such as e, pi, and log (2. The program with four lines of code to calculate the circumference rate was called by netizens as a program writt
I was first in [1] to notice the Spigot-algorithm, this algorithm was released quite early, see [2]. [1] Given a few amazing programs, you can calculate constants such as E,pi,log (2) with very little code. One of the 4 lines of code to calculate the PI program is known as the aliens written by the program, but I have not the courage to analyze and learn it, recently decided to learn this spigot-algorithm, first read the literature "3", understand its basic ideas, then plan to try to write va
Harmonic numberTime Limit:3000MSMemory Limit:32768KB64bit IO Format:%LLD %llusubmit Status Practice Lightoj 1234DescriptionIn mathematics, the nth harmonic number is the sum of the reciprocals of the first n natural numbers:In this problem, you is given n, you have to find Hn.InputInput starts with an integer T (≤10000), denoting the number of test cases.Each case is starts with a line containing an integer
Question: Application of Polynomial methods in Harmonic AnalysisSpeaker: Zhang RuixiangTime: January 1, July 30, 2014Location: Room 1309, building 1, science
Recently, in terms of the problems and limitations of kakeya in harmonic analysis, the so-called "polynomial method" has developed very important and produced a series of important results. We will describe these results and try to explain the role and
http://lightoj.com/volume_showproblem.php?problem=1234Harmonic numberTime Limit:3000MSMemory Limit:32768KB64bit IO Format:%LLD %llusubmit Status Practice Lightoj 1234DescriptionIn mathematics, the nth harmonic number is the sum of the reciprocals of the first n natural numbers:In this problem, you is given n, you have to find Hn.InputInput starts with an integer T (≤10000), denoting the number of test cases.Each case is starts with a line containing a
1245-harmonic Number (II)
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Time Limit:3 second (s)
Memory limit:32 MB
I was trying to solve problem ' 1234-harmonic number ', I wrote the following codeLong long H (int n) {Long long res = 0;for (int i = 1; I res = res + n/i;return res;}Yes, my error is that I was using the the integer divisionsonly. Howeve
Title Link: BZOJ-2048Problem analysisWhen there is only one book, the weight of the book falls on the edge of the table, and the length of the desktop is 1/2.When there are two books, the center of gravity of the first book falls on the edge of the second book, the center of the two books on the edge of the table, the center of the two books is at the bottom of the book at the right end of 1/4. So stretch out 1/2 + 1/4.Three books, you can stretch more than 3 of the book's center of Gravity 1/6.
It is clear that the real and imaginary parts of pure functions are harmonic functions. Naturally, ask a question:If the $u$ is a harmonic function on the area $d$, is there necessarily a function $f\in H (D) $ so that $${\RM re}f=u$$ is established? Generally speaking, this conclusion is wrong. But if the restricted area $d$ is single-connected, then the conclusion is right. The following is a proof of thi
Take the Harmonic Function $ \ log | z | $ on $ B () \ setminus \ {0 \} $, so it cannot be $ B) \ setminus \ {0 \} $ indicates the actual part of a pure function. otherwise
$ F (z) = \ log | z | + IU (z) \ In H (B (0, 1) \ setminus \ {0 \}) $
$ U (z) $ is a real value. then $ e ^ {f (z) }=| z | E ^ {IU (z) }$, so $ \ left | \ frac {e ^ {f (z) }}{ z} \ right | \ equiv1 $
Therefore, $ \ frac {e ^ {f (z) }}{ z} $ is a constant value, so $ \ Theta \ In
Label: Style Color SP on BS ad amp size UISet $ U $ to the Harmonic Function on $ \ BBR ^ N $, and $ \ Bex \ Sen {u }_{ L ^ p} = \ sex {\ int _ {\ BBR ^ n} | U (y) | ^ p \ RD y} ^ {1/p} Proof: by $ \ beex \ Bea \ sev {u (x )} =\ sev {\ frac {1} {\ omega_n R ^ n} \ int _ {B _r (x)} U (y) \ RD y} \ quad \ sex {\ omega_n :\\ BBR ^ n \ mbox {Unit Ball volume, mean Value Theorem }\\\ \ Leq \ frac {1 }{\ omega_n R ^ n }\sex {\ int _ {B _r (x)} | U (y) | ^
Assuming that the original signal sample rate is 4000kHz, a set of 1 harmonics consisting of a 200Hz fundamental, which is simulated by the sine function.Thus get 200hz,400hz,600hz ... 2000Hz, but the magnitude of the 2000Hz here is almost 0, which is explained in detail later.Time domain waveform with a 200Hz amplitude of 1. FFT transformation, the amplitude of the corresponding frequency is still 1, the frequency is still 200Hz, the mirror frequency symmetry, at the frequency (4000-2000) Hz di
As the operation of the frequency upgrade machine needs automatic leveling function, so start to do this work. Hardware selection is incremental encoder, 100 pulses per revolution, and later learned that each timer of the STM32 Channel 1 and Channel 2 built-in Quadrature encoder module, can be used directly. Before the company engineers are using a timer to capture the pulse, and then self-processing, I loo
FFmpeg installing a third-party encoder (encoder) Library
Keywords: ffmpeg, code H264, third party encoder
After installing the FFmpeg, if you use the FFmpeg tool to turn a video file into H264 video encoding, MP3 audio encoding or other ffmpeg itself without the XXX encoding type, you will see the error message, unknown enco
From: Http://www.opus-codec.org/docs/html_api-1.1.0/group__opus__encoder.html#gaefeb7dc1d6e3b59dea5ea674c86e9c18
Detailed description This page describes the use procedures and features for encoding. Since Opus is a state codec, it is necessary to create an encoder before encoding. You can do this: int error;Opusencoder *enc;ENC = opus_encoder_create (Fs, channels, application, error); From there, the enc can be used to encode the audio stream. Th
http://lightoj.com/volume_showproblem.php?problem=1245The sum of a number n divided by 1 to nAnalysis: Violence is certainly not possible, we can first ask for the number of 1~SQRT (n), and then the n divided by the number of 1~SQRT (n) andThe complexity of the 2*SQRT (n) is the only thing that counts.Finally, we have to rule out extra,#include #includestring.h>#include#include#include#includestring.h>#include#include#include#include#include#includeusing namespaceStd;typedefLong Long intLL;#defi
Main topic:Give a number n, find out 1/1+1/2+1/3+....+1/(n-1) +1/n; 1Problem Solving Ideas:Because the value range of n is too large, marking the words will be super memory, so simply calculate the size of the memory, you can hit a save n=40,80,120 The table,So, for the worst case of N, which is looping 39 times,Code:1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 8 #defineMAXN 25000059 #defineN 100000005Ten DoubleA[MAXN]; One A intMain () - { - intT, N, M, I, j, L
Coding | script using Script encoder
The script encoder encodes only the script code, and the other contents of the file are not moved and are displayed in plain text. To use the Scripting Encoder, develop and debug the text in the usual way, and then use the utility to encode the final script. The script encoder uses
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