hearthstone stream

problem DescriptionCDFPYSW loves playing a card game called "Hearthstone". Now he had N cards, he wants to split these cards into 4 piles.Let's assume the number of cards in each pile is A1, A2, A3, A4. It must be satisfied that:a1 * K1 = a2 + a3 + a4 A2 * k2 = a1 + A3 + a4 a3 * K3 = A1 + a2 + A4 A1, a2, A3, A4 Must be positive Because cdfpysw are clever, there must be a-to split there card. Can you tell CDFPYSW?InputThe first line was an integer T,

,0,sizeof(DP)); LL p,n,m; scanf ("%i64d%i64d%i64d",p,n,m); LL N=n+m; for(LL i=n;i) scanf ("%i64d",Val[i]); dp[0]=1; for(LL st=0;st1) { if(dp[st]==0)Continue; LL Dam=0, num_a=0, num_b=0; for(LL i=n;i) { if(st (1; } if(dam>=p)Continue; for(LL i=0; i) { if(st (1; } if(num_a+1Continue; for(LL i=0; i) { if(st (1Continue; Dp[st+(1Dp[st]; }} LL ans=0, all=Fac[n]; for(LL st=

of your turn, you draw a-card from the top of the the card deck. You can use any of the cards in your hands until to run out of it. Your task is to calculate the probability so you can win in this turn, i.e., can deal at least P damage to Your enemy.Inputthe first line is the number of test cases T (tThen come three positive integers P (pOutputfor each test case, output the probability as a reduced fraction (i.e., the greatest common divisor of the numerator and denominator is 1). If the answer

Fifth session of the provincial race: HearthstoneCombinatorial mathematics.n Races, M tables (n>=m). Each race is a table, and each table is used at least once.The idea behind the question has been how to fill the M table with n positions.is actually the Tao Stirling number model, the direct set formula M!*{n m}#include #includestring.h>#defineL 1000000007intMain () {intn,m; Long Longa[101]; while(SCANF ("%d%d", n,m)! =EOF) {a[0]=0; for(intI=1; i) A[i]=1; for(intI=3; i) for(intj=i

I. Io and stream Data input and output (I/O for input/output)The input and output of standard input devices and standard output devices are referred to as standard I/OThe input and output of files stored on an external disk are referred to as files I/O.The input and output of the specified string bucket in the memory are referred to as string I/O. The process of data input and output can be visually viewed as a stream.The operation for retrieving dat

java.io uses design patterns such as adapter pattern decoration mode to solve the socket and input-output problems of character streams. A byte stream can only be processed at a time, in order to more easily manipulate the data, it adds a socket flow. Problem Introduction: Why is the buffer stream more efficient than ordinary file-byte throttling? An operation without buffering, which writes a byte ever

1: Login Register IO version case (master)Ask, write it over again.Cn.itcast.pojo UserCn.itcast.dao UserdaoCn.itcast.dao.impl UserDaoImp1 (realize I don't care)Cn.itcast.game GuessnumberCn.itcast.test Usertest2: Data manipulation flow (flow of manipulating basic type data) (understanding)(1) Basic types of data can be manipulated(2) Stream object nameDataInputStreamDataOutputStream3: Memory operation flow (understanding)(1) Sometimes we do not need to

The content of this article: What is a stream BYTE stream Character Stream Starting Date: 2018-07-24 what is a stream Flow is an abstract concept, is an abstraction of input, the input stream can be regarded as an input channel, the outpu

Elementary stream In the MPEG-2, bit streams that contain encoded images, sounds, or data are called the basic stream ES (elementary stream ), it only contains one type of data (audio, video, or subtitle). What we call "audio", "video", or "bit stream" is elementary stream,

The IP datagram has a header and data two parts, the first part of the header is a fixed length of 20 bytes, is all the IP datagram must have. The header includes: total length, logo, MF, DF, offset. The digital signal actually transmits the data stream, the general data flow includes the following three kinds: ES streams: Also called basic streams, which contain continuous streams of video, audio, or data. PES st