hearthstone tutorial

problem DescriptionCDFPYSW loves playing a card game called "Hearthstone". Now he had N cards, he wants to split these cards into 4 piles.Let's assume the number of cards in each pile is A1, A2, A3, A4. It must be satisfied that:a1 * K1 = a2 + a3 + a4 A2 * k2 = a1 + A3 + a4 a3 * K3 = A1 + a2 + A4 A1, a2, A3, A4 Must be positive Because cdfpysw are clever, there must be a-to split there card. Can you tell CDFPYSW?InputThe first line was an integer T,

,0,sizeof(DP)); LL p,n,m; scanf ("%i64d%i64d%i64d",p,n,m); LL N=n+m; for(LL i=n;i) scanf ("%i64d",Val[i]); dp[0]=1; for(LL st=0;st1) { if(dp[st]==0)Continue; LL Dam=0, num_a=0, num_b=0; for(LL i=n;i) { if(st (1; } if(dam>=p)Continue; for(LL i=0; i) { if(st (1; } if(num_a+1Continue; for(LL i=0; i) { if(st (1Continue; Dp[st+(1Dp[st]; }} LL ans=0, all=Fac[n]; for(LL st=

of your turn, you draw a-card from the top of the the card deck. You can use any of the cards in your hands until to run out of it. Your task is to calculate the probability so you can win in this turn, i.e., can deal at least P damage to Your enemy.Inputthe first line is the number of test cases T (tThen come three positive integers P (pOutputfor each test case, output the probability as a reduced fraction (i.e., the greatest common divisor of the numerator and denominator is 1). If the answer

Fifth session of the provincial race: HearthstoneCombinatorial mathematics.n Races, M tables (n>=m). Each race is a table, and each table is used at least once.The idea behind the question has been how to fill the M table with n positions.is actually the Tao Stirling number model, the direct set formula M!*{n m}#include #includestring.h>#defineL 1000000007intMain () {intn,m; Long Longa[101]; while(SCANF ("%d%d", n,m)! =EOF) {a[0]=0; for(intI=1; i) A[i]=1; for(intI=3; i) for(intj=i

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