help with decimals

Town Field Poem:The Pure Heart sentiment wisdom language, does not have the world name and the benefit. Learn water under the hundred rivers, give up arrogant slow meaning.Learn to have a small return to feed root, willing to cast a conscience blog. Sincere in this writing experience, willing to see the text to inspire.——————————————————————————————————————————Code1 DOCTYPE HTML>2 HTML>3 Head>4 Metahttp-equiv= "Content-type"content= "text/html; charset=utf-8"/>5 title>title>6 Scriptt

In the actual coding, you will encounter many high-precision cases, for example, in the calculation of money need to retain high-precision decimals, so that the calculation will not be too much error:In the following code, we verify that when the number of two float types is added, the resulting result is error with our expected result, and in order to reduce and prevent this error, we need to use the BigInteger class and the BigDecimal class to calcu

Label:Always keep decimals, calculation in the program is too cumbersome, but also to convert the operation. It is convenient to operate directly in the database.The data type is defined as Decimal/numeric type, the decimal place needs to be arbitrarily set, divisor and dividend must have a type in decimal/numeric,The following example:SELECT 24.0000/38.0000--0SELECT CAST (24/38 as NUMERIC (18,4))--0SELECT CAST (24/38.0000 as NUMERIC (18,4))--0.6316 T

-adot + b.length-Bdot)) { if(I! = a.length +b.length) {Re[i]='.'; } } Else{Re[i]+=R[JJJ]; JJJ++; } } returnre; } Public Static Char[] Quadunit (stringAintb) {intR =0; intJW =0; Char[] C =A.tochararray (); ListChar> items =NewlistChar>(); ListChar> Ritems =NewlistChar>(); for(inti = C.count ()-1; I >=0; i--) { if(A[i] = ='.') {R='.'; Items. ADD

public class Numutils {/*** Reserved two decimal places** @param D* @return*/public static String Get2wei (double D) {Java.text.DecimalFormat df = new Java.text.DecimalFormat ("#.##");Return Df.format (d);}/*** Reserved two decimal places** @param D* @return*/public static String Get2wei (Float d) {if (d = = null)return "0";Java.text.DecimalFormat df = new Java.text.DecimalFormat ("#.##");Return Df.format (d);}/*** Reserved 0 decimal places** @param D* @return*/public static String Get0wei (doub

1 import Java.text.DecimalFormat;2 import Java.text.NumberFormat;3 4 import org.junit.Test;5 6 Public classTestCase {7 /**8 * Replace decimal with percent output9 * The double type is reserved two bits after the decimal point, converted toTen */ One @Test A Public voidTest () { - // ================================================================================ - Doublef =0.5585; the //BigDecimal B = new BigDecimal (f); - //Double f1 = B.setscale (2,bigdeci

Topic:Given a positive integer n, ask for a decimal representation of 1/n, such as:1/2=0.51/3=0. (3)1/6=0.1 (6)1/7=0. (142857)Where parentheses represent the loop portion of the decimal.Ideas:Consider the process of the division operation:When the remainder is duplicated with the previous operation, then the loop has already begun, so a hash table can be used to record the position of the remainder.Dividend divisor remainder quotient1 7 1 01*10 7 3 13*10 7 2 42*10 7 6 26*10 7 4 84*10 7 5 55*10 7

//Way One:Doublef = 3.1516; BigDecimal b=NewBigDecimal (f);DoubleF1 = B.setscale (2, bigdecimal.round_half_up). Doublevalue (); //Way Two:NewJava.text.DecimalFormat ("#.00"). Format (3.1415926);//#.00 represents two decimal places #.0000 four decimal places and so on ...//Way Three:DoubleD = 3.1415926; String result= String.Format ("%.2f", d);//%.2f%. Indicates that any number of digits before the decimal point of 2 indicates that the result of the two-bit decimal format is F for floating-point.

PHP converts decimals to integers. The floatfloor (floatvalue) rounding method returns the next integer not greater than the value and rounds the fractional part of the value. The return type of floor () is still float because of the float value. Float floor (float value) Rounding Returns the next integer not greater than value and rounds the decimal part of value. The return type of floor () is still float, because the float value range is usually l

In the database is the numeric (38,6) type, shown to the DataGridView interface is always followed by 6 0 (for example: 20000.000000), want to just display integers, a burst of easy to find, but no detailed documentation comments, and some in the format string with the # symbol (such as: ##.##), do not know what to do. can do so. DataGridView dgvdiscipline= this as DataGridView; dgvdiscipline.columns["anticipatingincome"]. defaultcellstyle.format="0";An integer is displayed on the inte

; $ Else thee.handled =false; the } the } the } - } in the /// the ///masking other strings of a digital textbox About /// the /// textbox to block the Public Virtual voidShieldnumbertextboxotherkeys (TextBox tbox) the { +Tbox. ImeMode =imemode.disable; -Tbox. KeyDown + =Tboxnumbers_keydown; theTbox. KeyPress + =tboxnumbers_keypress;Bayi } the the #

In integer division, Division (/) always returns a floating-point number, and if you want only the result of an integer, discard the possible fractional portion, you can use the operator // :>>> 17 / 3 # Integer division returns floating-point type5.666666666666667>>>>>>17 //3 # Integer division Returns the result of rounding down 5>>> 17 % 3 #% operator returns the remainder of division 2>>> 5 * 3 + 2 17 above excerpt from: Http://www.runoob.com/python3/python3-number.htmlConversion of int

1 Public classTest4 {2 Public Static voidMain (string[] args) {3BigInteger num1=NewBigInteger ("123456789123456789123456789");4BigInteger num2=NewBigInteger ("2345678901234567890");5System.out.println ("Plus:" +(Num1.add (num2)));6System.out.println ("Minus:" +(Num1.subtract (num2)));7System.out.println ("Multiply:" +(Num1.multiply (num2)));8System.out.println ("except:" +(Num1.divide (num2)));9System.out.println ("modulo:" +(Num1.remainder (num2)));TenBiginteger[] Num3=(Num1.divideandremainde

Time limit: 1 s space limit: 128000 KB title level: SilverTitle Description Description Give you a real number, no more than 50 digits after the decimal point, please keep to the decimal point after n bit (rounding!!!) )Enter a description input Description First line, a real number, no more than 50 digits after the decimal pointSecond row, reserved to n decimal placesoutputs description output Description A real number, a fractional number that has been retainedsample input to sample5.1982732

In Java:Import java.math.bigdecimal;import Java.text.decimalformat;import java.text.numberformat;public class format { Double F = 111231.5585; public void M1 () { BigDecimal bg = new BigDecimal (f); Double f1 = Bg.setscale (2, bigdecimal.round_half_up). doublevalue (); System.out.println (f1); } /** * DecimalFormat conversion is easiest * /public void m2 () { decimalformat df = new DecimalFormat ("#.00"); System.out.println (df.format (f)

Two ways to pay attention to the logical details!//Title Description////There is a real number between 0 and 1, and the type is double, which returns its binary representation. Returns "Error" if the number cannot be represented exactly in a 32-bit binary representation. //given a double num, which represents a real number from 0 to 1, return a string representing the binary representation of the numbers or "Error". //Test Examples://0.625//return: 0.101//two methods, forward and reverse#include

calculate the repeating decimal cycle section Enter integers A and B (0 For example, a=5,b=43, decimal notation is 0. (116279069767441860465), and the loop byte length is 21 You can use arrays to store numbers and simulate vertical division to solve them.The AC code is attached:1#include 2#include 3 using namespacestd;4 5 Const intmax=3050;6 7 intR[max],u[max],s[max];8 9 intMain () {Ten intn,m,t; One while(cin>>n>>m) { At=N; -Memset (R,0,sizeof(R)); -memset (U,0,s

#ifndef Mainwindow_h#defineMainwindow_h#include#include#includeclassMainWindow: Publicqmainwindow{Q_object Public: MainWindow (Qwidget*parent =0); ~MainWindow (); Qspinbox* spin[Ten]; Qdoublespinbox* doublespin[Ten];};#endif //Mainwindow_h#include"mainwindow.h"Mainwindow::mainwindow (Qwidget*parent): Qmainwindow (parent) { This->resize ( -, -); This-Centralwidget (); intXpos =Ten ; intYpos = - ; intVal[] = { -, -, $}; DoubleDouble_val[] = {50.5,127.32,171.342}; for(intI=0;i3; i++) {Spin[i]=New

);//4Math.Round (-0.64);//-1Math.Round (-5.5);//-6Math.Round (-4.5);//-4decimal Trade-offs: Math.Round (Double, Int32), where Int32 specifies the number of decimal places for the return value. Example: Math.Round (3.44,1);//Returns 3.4.Math.Round (3.45,1);//Returns 3.4.Math.Round (3.46,1);//Returns 3.5.Math.Round (4.34,1);//Returns 4.3Math.Round (4.35,1);//Returns 4.4Math.Round (4.36,1);//Returns 4.4pasted from//msdn.microsoft.com/zh-cn/library/zy06z30k.aspx>extension: The function by default is

http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=28517Idea: (1) First preprocessing, speaking of the input decimal at the end of the 0 minus, and record the position of the decimal point, and then flashback stored in the array,(2) A multiplication operation, two cycles.It is important to note that the length of the array after the operation needs to be accurately recorded.#include #includestring.h>#defineN 200voidAdd ();intreverse ();voidSumm ();intSum[n],b[n],n,time[n];CharA[n];intl,