hh 360

Main topic:Sdoi the number of occurrences of only one occurrence within an interval. Multiple groups of queries.HeoiFind the number of at least two occurrences within an interval. Multiple groups of queries.Sdoi HH ' NeckplaceIf each inquiry is 1. R, then we just turn the first occurrence of each color into 1, and then maintain the interval and then we can. This is obvious.So now consider if the interval becomes 2. R, then it is clear that the first p

Namespace yyyy_mm_dd_hh_mm{Class Program{static void Main (string[] args){while (true){Try{Console.WriteLine ("Please enter your date of birth");DateTime dt = Convert.todatetime (Console.ReadLine ());String s= dt. ToString ("Then your birth time is yyyy mm month DD day");//YYYY-MM-DD-HH-MM-SS Note This format, the output is yyyy MM month DD Day, etc.Console.WriteLine (s);Console.ReadLine ();}catch (Exception){Console.WriteLine ("Please enter the corre

1189:hh character reversal time limit: 1 Sec memory limit: up to MB Submissions: 8 Resolution: 6 Submitted State [Discussion Version] Title Description HH began to learn C language, the teacher assigned a homework problem, Reverses the contents of a string str and outputs it. STR has a length of not more than 100 characters. input Input has multiple lines, the first line includes a number T, Next T lin

Accidentally saw this blog of hh daniel: http://www.cppblog.com/notonlysuccess/archive/2011/09/26/80162.html#156835 "In October 16 last year, a was the first A + B, and my AC career started.Today is July 22, April 16, just half a year. I submitted three questions... The amount of AC in HDU reaches 900 ..." How can this be done with crazy questions. Think about yourself and be complacent in order to be able to get a question of 1y! When I finish a qu

Rokua Topic LinksTest instructionsGiven a long 5w static sequence, ask for 20w times, each time ask to find the number of elements in a range Dyeing problem God, I've just been able to do it, and I feel like we can use a unified approach.The first is to figure out the position of the nearest previous element, which is the same as an element, so that only the last position within the interval is less than the lower bound is the number of elementsIt's a very reasonable look, but I can't see

A DPFast power acceleration with matrixAnd then this DP state is smart with the edge state.#include [DP Matrix Fast Power] Bzoj 1875 [sdoi2009]hh go for a walk

Test instructionsA sequence with a length of N and a M query;The number of different numbers in the interval to ask;nExercisesThe online algorithm is too advanced and will not, so this problem will be done offline;Analysis data range, m query can be stored completely, 1000000 of the number can also be hash barely discrete;Then consider the number of a range of numbers, probably 1-r minus 1-(L-1) ;But because there are duplicate numbers, for the number of repetitions, we should only calculate bet

// Compare the time format yyyy-mm-dd hh: MI: SS Function comptime (begintime, endtime ){ VaR begintimes = begintime. substring (0, 10). Split ('-');VaR endtimes = endtime. substring (0, 10). Split ('-'); Begintime = begintimes [1] + '-' + begintimes [2] + '-' + begintimes [0] + ''+ begintime. substring (10, 19 );Endtime = endtimes [1] + '-' + endtimes [2] + '-' + endtimes [0] + ''+ endtime. substring (10, 19 ); // Alert (begintime + endtime + b

) { intret=0; while(p) ret+=s[p],p-=lowbit (P); returnRet;}intMain () {scanf ("%d",N); for(intI=1; i) {scanf ("%d", A +i); if(!m[a[i]]) m[a[i]]=++CNT; A[i]=M[a[i]]; } scanf ("%d", m), cnt=0; for(intI=1, l,r;i) {scanf ("%d%d",l,R); MEM[CNT].U=L,MEM[CNT].T=I,MEM[CNT]. next=tab[r],tab[r]=mem[cnt],cnt++; } for(intI=1; i){ if(Pos[a[i]]) Update (pos[a[i]],-1); Pos[a[i]]=i,update (I,1); for(Hash *p=tab[i];p; p=p->next) Ans[p->t]=sum (N)-sum (p->u-1); } for(intI=1; i"%d\n", Ans[i])

Title effect: some beads necklace. Beads have different colors. We asked several times how many different colors had been in a certain range.Thinking: This problem has taught me to learn smart offline practices. Sort the problem by the left endpoint. The processed position is the first occurrence of each color. Where the next occurrence of each color is. Then, 1 to the CNT cycle, where there is a problem with the left endpoint is the current node, just deal with his answer. The method is a prefi

function Getnowdate () {var date = new Date ();var seperator1 = "-";var Seperator2 = ":";var month = Date.getmonth () + 1;var strdate = Date.getdate ();if (month >= 1 month month = "0" + month;}if (strdate >= 0 strdate Strdate = "0" + strdate;}var Hours = date.gethours ();var Minutes = Date.getminutes ();var Seconds = Date.getseconds ();if (Hours >= 0 Hours Hours = "0" + Hours;}if (Minutes >= 0 Minutes Minutes = "0" + Minutes;}if (Seconds >= 0 Seconds Seconds = "0" + Seconds;}var currentdat

Title Link hh NecklaceThis problem can be directly on the chairman of the tree template#include Of course, you can do it with the MO team algorithm.#include Bzoj 1878 [Sdoi2009]hh's Necklace (Chairman tree or MO team algorithm)

Recently in the writing of a HTML5 small game, the game will inevitably use the function of the timing. I am simply setting up a passedtime variable that does not have 60 frames + + once in the game Loop (fps=60). Then the time to convert the Passetime into 00:00 format is displayed. Although this method of computer time is not very accurate (because not every machine can be guaranteed to update 60 times in any second), but now the computer efficiency is very high, plus broswer progress, unless

the random number of HHTime limit:1 Sec Memory limit:128 MB submit:413 solved:60 [Submit] [Status] [Web Board] Description HH wants to ask some students to do a survey at school, for the objectivity of the experiment, he first generated N 1 to 1000 random integers (n≤100), for which the number of repetitions, only one, the rest of the same number to remove, different numbers correspond to the number of different students. Then the number of these num

360 offline where are the tickets for the robbery? 360 Secure browser can support 360 off-line grab ticket function, otherwise other browsers can not use this grab ticket plug-in. 360 Off-line robbery tickets are divided into two kinds Directly in the computer to open the 360