how computers work pdf

Analyze assembly code to understand how computers work, assembly code to understand computers For reprinted original works of Zhou yuyong, please indicate the sourceLinux Kernel Analysis MOOC course http://mooc.study.163.com/course/USTC-1000029000 Decompiling C code into assembly code to analyze how the computer works.Below is the simplified assembly code for c

Adobe's official security warning says new security vulnerabilities (cve-2011-2462) have been found in Adobe Reader and Acrobat 9.4.6. Adobe will release the update next week due to higher vulnerability levels. December 8, Jinshan poison PA Security Center reported that the attack code has been disclosed, verified that the installation of Jinshan poison PA computer can successfully defend against this vulnerability attack. PDF is the most common form

How computers work ——— the process of turning high-level language into machine language 20135304 Liu Xipeng"Linux kernel Analysis" MOOC course http://mooc.study.163.com/course/USTC-1000029000 "Experimental processWrite C language codeGet assembly code after executing gcc-s-o main.s main.c-m32 instructionDelete with "." Get clean assembly code after opening additional itemsAnalysis processAnalysis of t

The first week of Linux kernel analysis-how computers workLi Sheli + Original works reproduced please specify the source + "Linux kernel analysis" MOOC course http://mooc.study.163.com/course/USTC-1000029000The von Neumann architecture is the storage program computer.1. The digital computer system uses binary;2. The computer usually executes one of the instructions sequentially, if necessary, to jump to a specific address through the register, then ex

value of EBP to ESP, that is, both ESP and EBP point to position 4, then pops the top element of the stack into EBP, and assigns the value "position 1" of position 4 in the stack to EBP, while the ESP points to position 3;RetPop the stack top data into the EIP, the value "line 23" of position 3 in the stack is assigned to the EIP, while ESP points to position 2, the next instruction becomes the instruction at line 23rd;Addl $,%eaxThe value in the register EAX is added to 1, which becomes 19;Lea

Beijing Institute of Electronic Technology 20135310 Chen ChaojanFirst, video notesSecond, experiment: Compile a simple C program, analyze its assembly instruction execution process Using experimental environment of laboratory building 2. Source Code MAIN.C3. Generated assembly code MAIN.SThree, the assembly instruction execution Process analysisIv. summing up and understandingThis part is a basic part of computer working principle, which has been studied repeatedly in the basic course of

PIRATEZGW Original works reproduced please specify the source "Linux kernel Analysis" MOOC course http://mooc.study.163.com/course/USTC-1000029000 In fact, this is to deal with the work of the MOOC course, where the environment can not contact the Internet at any time, so submitted are relatively late, nonsense not much to say, into the topic. First, the operation of the experiment This is mainly in the Linux environment using VI + GCC to write C prog

position 5, respectively.Eight:Executes the statement, the leave statement is equivalent toMOVL%ebp,%espPOPL%EBPEquivalent to the stack used by the Undo function f(9) as shown,Perform MOVL%ebp,%esp ebp,esp all point to position 4.The execution popl%ebp ebp,esp points to position 1 and position 3 respectively.Nine:Execute Statement-RET(10) shown, the EBP,ESP points to position 1 and position 2 respectively. The next instruction executed by the program is statement 23.Ten:Execute statement 23,24A

subl $4, %esp movl 8(%ebp), %eax movl %eax, (%esp) call g leave ret main: pushl %ebp movl %esp, %ebp subl $4, %esp movl $18, (%esp) call f addl $11, %eax leave retStack change process1.main function--PUSHL%EBP + MOVL%ESP,%EBP2.main function--subl $4,%esp + movl $18, (%ESP)3.main function--call F4.f function--PUSHL%EBP + MOVL%ESP,%EBP5.f function--subl $4,%esp + movl 8 (%EBP),%eax + movl%eax, (%ESP)6.f function--call g7.G

Analysis:G:PUSHL%p; stack bottom entry stackMovl%esp,%p; empty stationMOVL 8 (%p),%x, two bits above the bottom of the stack, then pass the value of the indicated position to the EAXAddl $7,%x; plus 7POPL%p; stack bottom out stackRET; returnF:PUSHL%p; stack bottom entry stackMovl%esp,%p; empty stationSubl $4,%esp; Move down one of the top stacksMOVL 8 (%p),%x, two bits above the bottom of the stack, then pass the value of the indicated position to the EAXMOVL%x, (%ESP); to pass the value of EAX

How does a mini PDF reader work? at present, many documents are in PDF format, so many netizens will download a PDF reader in the computer, then, which PDF reader better use it? Small series to recommend a software, that is, mini PDF