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This error was reported when two linux Red Hat 4 hosts were used to build RAC (10 Gb). The problem was solved later.
I just set up RAC, can open Node 1, open Node 2, this error is reported, view the log of Node 1 as follows:
SQL>Select * from v $ Log;// Logs with only Node 1
permissioned setting, but his communication is at least squared, and obviously is hard to support large network nodes, even in permissioned setting. According to colleague Test, the Hyperledger 100 nodes are about to finish the egg ... PBFT is the abbreviation of practical Byzantine Fault tolerance, which means a practical Byzantine fault-tolerant algorithm. T
Apmserv1 and Apache startup failed. check related configurations. 2. MySQL5.1 failed to start. check the related configuration. 1. Apache startup failed. check the related configuration. 2. MySQL5.1 failed to start.
1, Apache failed to start, please check the relevant configuration. 2, MySQL5.1 start failure, please check the relevant configuration.
Apache Port is 800,mysql5.1 port is 3308
Reply to discussion (solution)
Add: My permissio
Category: Windows programming C + + 2012-10-27 19:56 3410 people read reviews (1) favorite reports There are four threads of 1, 2, 3, 4. The function of thread 1 is output 1, the function of thread
def groupBy (FN): def Go (LST): = {} for in lst: ifelse m.update ({fn (v): [v]}) #如果存在dict, append to the corresponding key, or none if it does not exist, then update a new key to return m return = GroupBy (lambdais 1) grpby ([1, 2, 3]) The Python implements the GroupBy function. Grpby = GroupBy (lambda x:x%
Work case 1 everything is caused by check, case check
In HTML, the input tag has two types: radio and checkbox. One single choice button and one check button. Jquery can select them through $ (": radio") and $ (": checkbox"). If you want to select the selected button, jquery
. Instead He gave you an array a1, A2, ..., Aksuch that
In other words, n was multiplication of all elements of the given array.
Because of precision difficulties, Barney asked you to tell him the answer as an irreducible fraction. In all words need to find it as a fraction p/q such that, where is the greatest common divisor. Since p and Q can be extremely large, you have need to find the remainders of dividing each of the them by 109 + 7.
Please note
/* Factorization is a very basic mathematical operation and is widely used. The followingProgramReturns the factorization of integer n (n> 1. For example, if n is 60, the output is 2 2
the data by opening the table. Find out after the management of this piece of relevant code there is a loophole, if not see first clear2. After clearing, open the log, watch to see if it is hung again, see the corresponding time log, see if you can find clues
I've had problems like this before. Do you write your program yourself or CMS? If it is a CMS I suggest
The following post discusses some conjecture assumptions in access.
Access or other database operation efficiency issues. Welcome to discuss
Http://topic.csdn.net/u/20090514/10/a93475bd-e67e-45c8-aa1e-87168ba36d02.html#replyachor
Reply to reference wwwwb on the 9th floor ::
You can test it by yourself, but based on experience,Delete, insert again (the data volume is larger than the number of records not inserted), and then index creation, the spee
Problem description:There are three kinds of coins: 1 $, 2 $, 3 $. given a chique of N $(0 Sample input: 1 2 3Sample outpt: 1 2 3
That is to say, I want to change the
Using O (1) Time to check whether an integer n is a power of 2.ExampleFor n=4, return TrueFor n=5, return falseChallengeO (1) TimeAnalysis:Use bit manipulation. Be carefull is about the 0 and negtive integer.Solution:
row within the result set partition. The rank of a row is a number of rows before the line involved.
--like here I sort by price, take out the most expensive items in each category from top to bottom
SELECT * from
(
SELECTI.price,i.commodityname,c.classname,rank () Over(Partition byC.classidOrder byI.priceDESC) Rank2 fromCommodityinfo iINNER JOINCommodityclass C onI.commodityclass=C.classid) RWHERERank22; Under SQL SERVER:
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