how to find average of 2 numbers

Topic: Given a group of numbers, only two numbers appear once, and all the other numbers are paired. How to find these two numbers. Write a function implementation.Topic Analysis:last time, for a group of numbers only one number a

Requirement: A set of data that is graded by a group of judges. Find their maximum and minimum values. The corner label of the maximum minimum value To remove the average after the maximum and minimum values Code:1PHP2 $arr=Array(1,2,3,4);3 //Minimum Value4 //idea: 44,5,3,333,445,99,54,332,-65 //1. Define variables, one record subscript $index, one record minimum value $minvalu

//Gets the maximum and minimum values in the array@min. SelfNsarray*array =@[@4,@84,@2;NSLog(@ "max =%@", [arrayValueforkeypath:@ "@max. Self"]);//Average and sum nslog (@ "%@" , [array valueforkeypath:@ "@sum. Self" // average and averaging NSLog(@ "%@", [array valueforkeypath:@ "@avg. Self"]); 　　 // Find th

Without any comparison, find out the larger number of two numbers public class twonumwithoutjudge{//Judge a number of symbols (return 0 negative, 1 positive) public static int getsign (int x) {return ((x>>31) ^1) 1; }//Method 1 (limited premise A is not equal to B, may overflow) public static int GetMax01 (int a,int b) {int c=a-b; int d=b-a; int c=getsign (C);

static void Main (string[] args){Double[] A = new double[10];Double sum = 0;for (int i = 0; i {A[i] = Convert.ToInt32 (Console.ReadLine ());Sum=sum+a[i];Console.WriteLine ("First" + (i+1) + "Judges ' score is" +a[i ");}Console.WriteLine ("Total score is" +sum);Double temp;for (int i = 0; I {for (int j = i; J {if (a[i]{temp = A[i];A[i] = a[j + 1];A[j + 1] = temp;}}}for (int i = 0; i {Console.Write ("Score from large to small for:" +a[i]+ "\ n");}Console.WriteLine ("Highest score" + a[0]);Console.

First, let's start with a simple question: In an array, all the numbers except one appear twice. How can we find the different number, Simply put, all numbers are different or the final result is the number to be searched, because the same number is different or the result is 0. Now let's think about this question: The book "The beauty of programming" provides

>>> and >> are bitwise operators, only valid for integral types (not for floating-point types).When the integer type (low+high) >>1 can replace (Low+high)/2.>>> is the unsigned right-shift operator. If Low+high is a positive integer, these three operations are equivalent.Because of compiler optimizations, their efficiency should be the same (if there is no compiler optimization, the shift operation is faster).Use >>> generally have a special purposeAs

Analysis, two-digit and N. So are the two numbers unique? is the output subscript the first pair to appear?1, we assume that these two numbers are unique.And is unique, the larger the number, the smaller the other number. Thinking of the size relationship, we thought of the sort. So first sort:int array[]={1, 2, 7, 9, 13, 57, 36, 26, 55, 11, 9, 6, 3, 89, 36, 75,

bubbling Algorithm > [0] is the minimum value - for(intj=0;j//number of rows to compare to for(inti=0;i//Number of comparisons (number of columns) + //the more rows you compare, the fewer times you need to compare the number of accompanying numbers, and the less you need to-j the last number so you don't have to compare so-1 - if(t[i]>t[i+1]){ the

I think the writing is very clear, I hope there is no infringement of the author's copyright, the original address http://blog.csdn.net/hackbuteer1/article/details/6699642To quickly find the two numbers in an array so that the sum of the two numbers equals a given value, for the sake of simplification, we assume that there must be at least one set of conforming s

Transferred from: http://zhedahht.blog.163.com/Title: Three digits A, B, c appear only once in an array, and the other numbers appear two times. Please find three numbers that appear only once.Analysis: In the blog http://zhedahht.blog.163.com/blog/static/2541117420071128950682/we discussed how to find two occurrences

The two-fork search tree is described earlier, and he has no problem with the efficiency of finding and inserting in most cases, but he is less efficient in the worst case. The data structure of the balanced lookup tree introduced in this article and later in this article ensures that the LGN efficiency can be achieved in the worst case, and we need to make sure that the tree remains in equilibrium after the insert is complete, which is the Balanced search tree. In a tree with n nodes, we want t