how to round double

C # math. Round () Achieves Chinese rounding   Math. Round () in C # does not use the "Rounding" method. In fact, in VB, VBScript, C #, J #, T-SQL in the round function are using banker's rounding (Banker algorithm), namely:Four Homes, six in five

Knights of the Round Table Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 10908 Accepted: 3585 DescriptionBeing A knight is a very attractive career:searching for the Holy

1 PackageMath;2 3 Public classTestmath_round {4 Public Static voidMain (string[] args) {5SYSTEM.OUT.PRINTLN (Math.Round (0.5));//16System.out.println (Math.Round (-0.5));//07System.out.println (Math.Round (-0.501));//-18 //the Math

In math. when performing data processing, round often encounters a situation where 81.25 retains a decimal number, and the value is 81.2. It is searched by material and math. the round rounding algorithm adopts the banker's rounding algorithm, which

Round () Rounding out the js Banker algorithm, round banker First, let's guess the result returned by round (0.825, 2, First, SQL server Returns 0.83 The returned result of js is 0.83. The code is as follows: Var B = 0.825; alert (Math. round (B * 1

Strange things about adding Java double Question:Compile and run the following program to see what?Public class test {Public static void main (string ARGs []) {System. Out. println (0.05 + 0.01 );System. Out. println (1.0-0.42 );System. Out. println

I. Loss of precision in floating-point calculationsProbably a lot of friends with programming experience are not familiar with this problem: no matter what programming language you use, when you use floating-point data for accurate calculations, you

Msdn does not provide a detailed description. An example is provided; Math. Round (3.44, 1); // returns 3.4.math.round (3.45, 1); // returns 3.4.math.round (3.46, 1); // returns 3.5. According to his example, the result is "five homes and six

Title in Java accurate calculation of floating-point number Ayellow (original) modificationKeyword Java floating-point number accurate calculationThe question is raised:What will we see if we compile and run the following program?public class

Let's take a look at an example: 1: DECLARE @Value float 2: SET @Value = 12.1785 3: SELECT '12.1785' as ValueToRound, ROUND(@Value,3) as RoundedValue 4: SET @Value = 12.1745 5: SELECT '12.1745' as ValueToRound,ROUND(@Value,3) as