how to splice telephone wire

optimization ... The optimal strategy for a position can be considered on both sides, then update the current optimal solution while updating the state. Poor monotony! #include #includeusing namespacestd;intn,c,h,le,f[2][101],i,j,xx;CharCS;intRead () {CS=getchar (); xx=0; while(cs'0'|| Cs>'9') cs=GetChar (); while(cs>='0'cs'9') xx=xx*Ten+cs- -, cs=GetChar (); returnxx;}intMain () {n=read (); C=read (); h=read (); for(i=1; i+h -; i++) f[0][i+h]=i*i; Le=h; intLa=1, now=0, mi,x; for(i=1; i) {s

Normal DP..F[I][J] Represents the first I-pole, the minimum total cost of changing the height of the I pole to J. Set the original pole height to h[]f[i][j]=min{f[i-1][k]+c*|j-k|+ (J-h[i]) ^2, (K>=h[i-1],j>=h[i])}Directly on the words of Complexity is O (n*100*100) = =You can use two arrays to save the K (two arrays with different values of J): One is K>=j, the other is K1#include 2#include 3#include 4 using namespacestd;5 Const intmaxn=100023;6 intf[2][101],gpre[101],gaft[101],H[MAXN];7 inti,j,

Telephone Wire Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 2662 Accepted: 970 DescriptionFarmer John ' s cows is getting restless about their poor telephone service; They want FJ to replace the old telephone

P2885 [usaco 07nov] Telephone Wire, p2885usaco 07novDescription Farmer John's cows are getting restless about their poor telephone service; they want FJ to replace the old telephone wire with new, more efficient wire. the new wiri

Serie A champions:Some trees are high given. One operation: Increase the height of a tree by H and spend it as h*h. After the operation is complete, the two trees spend a height difference * Fixed value C.Ask for a two-flower fee plus and a minimum value.ExercisesVery much like NOIP2014 d1t3.The violent movement is O (1*10^9) tSo a monotone queue, each tree sweep two times the end.Well, look at the water code.#include Copyright notice: This article blog original articles, blogs, without consent