how to take character input in java using scanner class

Code:Import Java.util.Scanner;public class Scannerdemo {public static void Main (string[] args) {Scanner scan = new Scanner (system.in);receiving data from the keyboard // nextLine方式接收字符串 System.out.println("nextLine方式接收："); // 判断是否还有输入 if (scan.hasNextLine()) { String str2 = scan.nextLine(); System.out.println("输入的数据为：" + str2); }

() method and the Nextline () method, because Nextline () consumes the line feed. You can refer to the correct wording of this program (Http://code.geeksforgeeks.org/CErAhD). This problem and the scanf () in C + + (http://www.geeksforgeeks.org/problem-with-scanf-when-there-is-fgetsgetsscanf-after-it/) Method follows the same problem as the gets () method. Other points of difference: BufferedReader is supported for synchronization, and scanner is no

in the implementation of the character window input, many people prefer to use the scanner scanner, it is easier to operate. In the process of programming, I found that there are two ways to implement string input with scanner, one is next (), the other is nextline (), but what is the difference between the two methods

Code:Import Java.util.Scanner;public class Scannerdemo {public static void Main (string[] args) {Scanner scan = new Scanner (system.in);receiving data from the keyboard // nextLine方式接收字符串 System.out.println("nextLine方式接收："); // 判断是否还有输入 if (scan.hasNextLine()) { String str2 = scan.nextLine(); System.out.println("输入的数据为：" + str2); }

Let's look at the exact words in the Java API documentation:当扫描器抛出 InputMismatchException 时，该扫描器不会传递导致该异常的标记，因此可以通过其他某种方法来获取或跳它。 这是java API文档中的原话。In fact it means: "'If you enter the a character when the Nextint method executes, and you do not successfully parse an integer at this time, your input will not be ignored. Because it might be able t

Java Scanner ClassJava.util.Scanner is a new feature of JAVA5, and we can get the user's input through the Scanner class.Here is the basic syntax for creating a Scanner object:New Scanner (system.in);Next we demonstrate the simplest data input, and get the input string throu

First, we introduce, in the Java language, for string input, because the scanner.next () function can not enter the space and carriage return, at this time, we have to use scanner.nextline () to solve such problems ，In the process of use, we will find Nextint () and nextline used together, this problem occurs:After you enter an int data, it is output, and the string is not entered at all ...Then went online to check some information, read some of the

string first, get an int valueString s3 =Sc.nextline (); intB2 =Sc.nextint (); System.out.println ("S1:" + s3 + ", B:" +B2); System.out.println ("-------------------"); //get an int value first, get a string, get the data wrong intA2 =Sc.nextint (); String S4=Sc.nextline (); System.out.println ("A:" + a2 + ", S2:" +S4); System.out.println ("-------------------"); //Workaround: Define two scanner objects and get two data respectively int

the end of all line separator. The position is set to the beginning of the next line.The Nextint () method reads the token of the next int type flag. But the focus does not move to the next line, still on the line. When you use the Nextline () method, all the contents of the row remaining are read, including the newline character, and then the focus moves to the beginning of the next line. Therefore, you cannot receive a variable of type string that

First of all, scanner is a scanner that scans data to scan and read data in a buffer in memory, and the data we enter in the console is also stored in the buffer waiting for the scanner to read. This scanner in the scanning process to judge the basis of the stop is "blank character