HP HP CLJ2840, 2820 Replacement toner Cartridge method
1, push the scanner, release the button to open the scanner assembly.
2, open the top cover, lift the imaging drum vertically, and then remove the cartridge to replace the toner cartridge.
3. Ensure that the correct print cartridge slot is in the loading/unloading position, if the correct print cartridge slot is not in the loading/unloa
11g ASM dbca error prcr-1006 crs-0259 prcr-1071
When creating a single instance DB using ASM mode, it appears when running DBCA
PRCR-1006 : Failed to add resource ora.orcl.db for orcl
PRCR-1071 : Failed to register or update resource ora.orcl.db
PRCR-1001 : Resource ora.orcl.db does not exist
After viewing the DBCA log, I found the following error.
[oracle@dga01 orcl]$ tail -30000 trace.log | grep PRCR
classes.User Management class: Used to manage user data, verify user name and password through database after user login, and read user's details from database after authentication. While maintaining user data in the program, the user data is saved to the database when the user game ends and exits the game.Server Framework class: Used to manage the game hall data, including a list of some data.Database classes: Server-side for network games when processing large amounts of customer data, using
Physiological cycle POJ 1006, physiological cycle poj1006
Time Limit:1000 MS
Memory Limit:10000 K
Total Submissions:138101
Accepted:44225
DescriptionThere are three physiological cycles in life: physical strength, emotional strength, and mental strength. The cycle is 23 days, 28 days, and 33 days. One day in each cycle is the peak. On the peak day, people will do well in the corresponding aspects. For example, at
According to the statistics system of hacked sites in China, from September to 3rd, the total number of submitted illegal websites in China was 1006, up 68.79% from last week. The following is the specific situation:
650) this. width = 650; "src =" http://www.bkjia.com/uploads/allimg/131227/0941512264-0.jpg "alt =" 20130922053913832.jpg"/>Figure 1) submitted by the hacked website in week 5, 3rd from September)
As shown in figure 1, a total of 517 subm
Title Link: The Magical kingdomAn essay question ... Magic string diagram, Magical mcs ...Feel like I have nothing more to say, here's a brief introduction to MCS:We give each point a weighted value, from the back to the next step to determine the perfect elimination sequence of points, each time the choice of the maximum value of a point (the same words randomly selected) placed in the current perfect elimination sequence position, and then the adjacent to a bit of weight added \ (1\). A perfec
Topic linksDescriptionGiven two string a B, the longest common subsequence of A and B (the subsequence is not required to be contiguous).For example, two strings: ABCICBA Abdkscab AB is a sub-sequence of two strings, and ABC is also, ABCA, where ABCA is the longest subsequence of the two strings.InputLine 1th: String ALine 2nd: string b(A, B's length OutputOutput the longest sub-sequence, if there are multiple, randomly output 1.Input exampleAbcicbaAbdkscabOutput ExampleABCAThe code is as follow
back and forth on both paths.Input and Output Sample input example # #:3 30 3 92 8 55 7 0Sample # # of output:34DescriptionLimit30% of the data meet: 1100% of the data meet: 1NOIP 2008 Raising the third question of the groupDP Category: Checkerboard type DP#include #includeusing namespacestd;#defineN 51intN,m,s[n][n],f[n][n][n][n];intMain () {scanf ("%d%d",n,m); for(intI=1; i){ for(intj=1; j) {scanf ("%d",S[i][j]); } } for(intI=1; i){ for(intj=1; j){ for(intk
forth on both paths.Input and Output Sample input example # #:3 30 3 92 8 55 7 0Sample # # of output:34DescriptionLimit30% of the data meet: 1100% of the data meet: 1NOIP 2008 Raising the third question of the group/*two-way transmission of the note, can be seen from the starting point has two pieces of paper together F[i][j][k][l] said from the beginning to (I,J) and (K,l) the greatest affection of the note can be from the top, or the top and left, or left and top, or all from the left when al
#includestring.h>#include#include#include#includeusing namespacestd;Const intn=1e5+Ten;Const intinf=0x3f3f3f3f;Const intmod=1e9+7; typedefLong LongLL;intA[n], flag;voidIncrease (intN) { inti, NUM, idex; Num= Flag =0; for(i =2; I ) { if(A[i] 1]) {num++; Idex= i;///Mark subscript that does not satisfy an element } } if(num = =0) flag =1; if(num = =1) { if(Idex = = N | | idex = =2|| a[idex-2] 1] 1]) Flag=1;///If this does not satisfy the left and right side of
occurs in 1234 days.Use the plural form "days" even if the answer is 1.Sample Input0 0 0 00 0 0 1005 20 34 3254 5 6 7283 102 23 320203 301 203 40-1-1-1-1Sample OutputCase 1:the Next triple peak occurs in 21252 days. Case 2:the Next triple peak occurs in 21152 days. Case 3:the Next triple peak occurs in 19575 days. Case 4:the Next triple peak occurs in 16994 days. Case 5:the Next triple peak occurs in 8910 days. Case 6:the Next triple peak occurs in 10789 days.SourceEast Central North America 19
Test instructions: number n, is (n+d)%23==p, (N+d)%28==e, (n+d)%33=i;Reprint please indicate source: http://www.cnblogs.com/dashuzhilin/;Idea: Chinese remainder theorem. Using the additive of congruence, the (n+d) is split into three number a,b,c,Make a%23==p,a%28==0,a%33==0;Make b%23==0,b%28==e,b%33==0;Make c%23==0,c%28==0,c%33==i;Then (n+d) = = (A+b+c) +LCM (23,28,33) *t;So, we can do the optimization, initially, the p,e,i are 1, namely:Make the A%23==1,a%28==0,a%33==0;a a multiple of 28 and 3
Title Link: BZOJ-1006Problem analysisThis problem is a bare model of the minimum number of staining figures for a chord graph.The minimum coloring method of a string graph is to find out the perfect elimination sequence (MCS algorithm) of the chord graph, and then, in accordance with the perfect elimination sequence, backward forward from backward to the smallest color that each Dianran can dye.The number of colors found is the smallest stain, but also the largest group.Code#include [Bzoj
意很明确就是求三个峰值相同的日期是哪一天,不过开始没理解到题意被卡了1个小时,理解之后才发现这个题这么简单,按照题意模拟就好。// @zhangxiaoyu///2015/8/13#include #include #include using namespace STD;typedef Long LongLL;intMain () {intP,e,i,d,kcase=1; while(~scanf("%d%d%d%d", p,e,i,d)) {if(p==-1e==-1i==-1d==-1) Break;intAnsif(p at) p+= at;/// This place must have for(ans=d+1; ans21252; ans++)/// starting from d+1, first find the date that is a multiple of 23{if((ans-p)% at==0) Break; } for(ans=ans;ans21252; ans+= at)/// Find the first one is both a
:10sc3021234 08:00:00 11:25:25cs301133 21:45:00 21:58:40Sample Output:SC3021234 CS301133title requirements from some records to find the earliest entry and the latest departure, only for this purpose, do not need to store the data, but should be dynamic record minimum and maximum, the final output, the realization of the idea is to check each record, if found new records of sign The in time is earlier than the current stored sign in the earliest time, then the update MiniD and the earliest sign
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