Cause of the error that form. submit () cannot be submitted: form. submit form
Source: http://www.ido321.com/948.html
Directly Add the following code:
1:
2: Member registration
3:
4:
5:
6: enter the
There are two (multiple) submit in a form in HTML. how to distinguish between the backend (pure HTML implementation without javascript) and formjavascript
A form may have multiple Submit elements. How can I identify which button is clicked in the
We should control the Submit button when the form is submitted, and cannot click repeatedly to submit the data. Otherwise there will be redundant duplication of data in the system, causing the system to appear data garbage. jquery is simple enough
Pre-used JS form to prevent duplicate submission method
The code is as follows
Copy Code
The following three methods are called separately
so if I make a form directly, and then submit it to/test, the above
ObjectiveUsing AJAX to request data, many people will, for example, say:$.post (Path,{data:data},function(data) { ...},"JSON");Or is this Ajax$.ajax ({ URL:"${pagecontext.request.contextpath}/public/testupload", Type:
ObjectiveUsing AJAX to request data, many people will, for example, say:$.post (Path,{data:data},function(data) { ...},"JSON");Or is this Ajax$.ajax ({ URL:"${pagecontext.request.contextpath}/public/testupload", Type:
use Ajax to submit form forms, including Ajax file uploadsHttp://www.cnblogs.com/zhuxiaojie/p/4783939.html
Preface
Using AJAX to request data, many people will, for example, say:
$.post (path,{data:data},function (data) {...
}, "json");
Or is
Originalhttps://www.jianshu.com/p/b427daa8663dOutline1. Understanding the form2. Understanding form Elements3. Classification of form elements4. Table element--text box5. Table Element button6, Table element--Single, multi-select7, table cell
Front-end technology-submit a form through javaScript, front-end javascript
window.location=pp+"?username="+getCookie("username")+"&userid="+getCookie("userid");
Replace
document.write("");document.write("");document.write("");document.write("");
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