. Unique identification as our ID card number, we handle credit card when the identity card is required, the real name under the purchase number card, ID card is necessary. If we are the system administrator, then I can completely through your ID number to find your cell phone number, bank card number.
With the above thought, all we have to do is find a unique identifier to associate with. There is an important role for the micro-letter OpenID. It has the same effect as the ID number mentione
PC-side micro-scan code registration and login
First, the preface
First of all, the focus of this article is to implement ideas, code and database design mainly to show ideas, if the code efficiency has a harsh requirements of the project should not be copied.
I believe that people who have been in the micro-credit development licensing This is not less done, but generally speaking, we are more to the mo
. NET development-scan code registration and logon on the PC side,. netpc
I. Preface
The focus of this article is the implementation idea. The code and database design mainly aims to demonstrate the idea. If there are strict code efficiency requirements, do not copy them.
I believe that developers have never done this much, but we generally do more authorization for mobile websites. Specifically, it is an a
two-dimensional code picture, users use micro-letter client scan code after the launch of payment." Note: The Code_url is valid for 2 hours, and will not be able to initiate payment after the expiration of the scan code. See, that's it. We first want to call the micro-letter to provide a unified next single interface, get a key information Code_url (as for this code_url is what ghost, I do not know), and t
How does the api obtain the scope (snsapi_login) permission? the logon via scan code on the PC side is not found in the Developer Documentation. I have read the relevant articles and did not say how to obtain the permission. my public account is the service number, you have already handed in the 300 certification.
A friend who knows what to do
Reply to discussion (solution)
Don't sink!
On
This article is mainly for everyone in detail the scan code after the success of the automatic jump PHP version of the code, with a certain reference value, interested in small partners can refer to
This example for everyone to share the PHP scan code after the success of the automatic jump code, for your reference, the specific content as follows
Scenario: PC-side
Scenario: PC-side sweep code payment
Result: The payment succeeds automatically jump
This article mainly and everyone in detail introduced the scan code after the success of the automatic jump PHP version of code, with a certain reference value, interested in the small partners can refer to, hope to help everyone.
Implementation ideas:
Pay the QR code page, write the AJAX request payment status, request to
Recently did a scan code login function, briefly explain the idea:Web-side generated a two-dimensional code, two-dimensional code content is a string of random garbledThen take the scanning function in the app to sweep, read to garbled, and the app's current user's UID is bound together to submit to the serverWeb page in the generation of two-dimensional code in 30 seconds, constantly holding the garbled to
In short, the Dubbo timeout, because the Dubbo default time is 500ms, more than this time it will revisit the service layer, try up to three times.So when I was testing, the log showed an exception to ... timeout ....Start setting the start setting of the timeout=50000, small data volume can be, if the data volume is not large.Then set the timeout=1200000 on the service provider sideinterface= "com. Xxxx. Xxxxx. Cardservice " ref=" Cardservice " timeout=" 1200000 "/>About the Dubbo service gen
The main idea: to give n a convex polygon, to find the area of these polygons and.Idea: N is less than 10, can be messed up. There is also a better solution, which seems to require only O (N^2LOGN) time to solve. But I do not, want to understand the reference: http://wyfcyx.is-programmer.com/posts/80378.htmlHere's the idea of messing about. Since all are convex polygons, then any line perpendicular to the x-axis in the area of the polygon must be a line segment (or Nothing), then we will all the
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