i5 4430

follows:watermark/2/text/ahr0cdovl2jsb2cuy3nkbi5uzxqvag93yxjkz2u=/font/5a6l5l2t/fontsize/400/fill/i0jbqkfcma==/ Dissolve/70/gravity/center ">For example, we calculate the frequent itemsets {i1,i2,i5}. Be able to discover i1^i2=>i5 because {I1,I2,I5} has appeared 2 times. {I1,I2} appears 4 times, so the confidence level is 2/4=50%Similar to be able to figure out:

Functions in matlab are related to image convolution. For example, imfilter can implement convolution, or conv2 can also perform convolution. Their speed is quite fast, for example, 3000*3000 grayscale images, the convolution matrix size is 15*15, and the running time on the I5 CPU is about MS, which is quite powerful. In Celery's blog, we also mentioned that conv2 and matlab after optimization are much faster than matlab. For details, see http://blo

//mode 3//int--integer--stringintegeri=newinteger ( 100); Strings3=i.tostring (); System.out.println ("S3:" +S3);//s3:100//mode 4strings4=integer.tostring (number); System.out.println ("S4:" +S4);//s4:100//string--int//mode 1strings= "" "; integerii= newinteger (s); Intn=ii.intvalue (); System.out.println ("N:" +n);//n:100//mode 2intm=integer.parseint (s); System.out.println ("M:" +m);//m:100}} 5. Automatic box packing and unpackingJDK5 simplifies the way you define it.Integer x = new Integer (4

needed to achieve this goal.InputThe input consists of 4 lines with 4 characters "W" or "B" from each of the denote game field position.OutputWrite to the output file a single integer number-the minimum number of rounds needed to achieve the goal of the game fro M the given position. If The goal is initially achieved and then write 0. If it's impossible to achieve the goal and then write the word "impossible" (without quotes).Sample InputBwwbbbwbbwwbbwwwSample Output4The main topic: is to give

Title DescriptionEnter the names of 5 students in a class and their math and English scores to calculate the average score for each student, and then output the names of the students with the highest average score and the scores of maths and English.Input requirementsEnter the names of 5 students in a class and their math and English scores. The name is a string that is not more than 19 characters in length, and the result is represented by an integer. Output requirementsOutput the name and aver

]; for(inti =0; i5; ++i) {Tt[i]=Std::thread (thread_procedure); } for(inti =0; i5; ++i) {Tt[i].join (); } while(true) {Std::lock_guardLG (M); Resource.push_back (rand ()% -); Cv.notify_one (); }}This code uses a Std::mutex and a std::condition_variable to control the corresponding thread, attempting to implement a simple print function.But at run time the code will be stuck at the produce

Https://vjudge.net/contest/259447#problem/EBfs,k constraints are presented in an extra K-dimension of the array.1#include 2 using namespacestd;3 #definell Long Long4 #defineMINV 1e-65 #defineINF 1e96 #definePi 3.14159265367 #defineNL 2.71828182848 Constll mod=1e9+7;//9982443539 Const intmaxn=1e5+Ten;Ten One intqx[maxn* -],qy[maxn* -],num[maxn* -],step[maxn* -],ci[maxn],c[5]={1,Ten, -, +,10000},d[5]; A BOOLvis[maxn][4][3]; - - intMain () the { - intHead,tail,i,j,s,x,y,ss,bu; -Head=0, tail=1

solving problems is. Adding in 10 100 = points from hacks, he total, score becomes 3930 + + = 4930. 1#include 2#include 3#include 4#include 5#include 6#include string>7#include 8#include 9#include Ten using namespacestd; OnetypedefLong Longll; Atypedef unsignedLong Longull; - structSubmission - { the intT; - intwa; - intSC; -}p[5]; + intMain () - { + intShack,fhack; A for(intI=0;i5; i++) at { -scanf"%d",p[i].t); -P[i].sc= -*

Title Link: http://61.187.179.132/JudgeOnline/problem.php?id=1264Test instructions: Give two series, each of the length of the series is 5n, wherein 1-n each number appears 5 times. The longest common child of two columns.Idea: LCS turned into LIS, for each number that appears in the first array, turn it into the position in the second array, notice that the position is from the big to the small row, and then do the LIS for this array.#include #include#include#include#includeintq[1000005],a[1000

, there are several functions related to the image convolution, such as imfilter can achieve convolution, or conv2 also line, their speed is quite fast, such as 3000*3000 grayscale, convolution matrix size is 15* 15, on the I5 CPU running time as long as about 170ms, quite to force.In Celery's blog, also mentioned his optimized conv2 and MATLAB is quite even faster than MATLAB, see http://blog.csdn.net/celerychen2009/article/details/38852105.As the MA

},{0,1,1,1,1},{0,0,2,1,1},{0,0,0,0,1},{0,0,0,0,0}};intD,MAXDEP;BOOLfo;intnow[5][5];intx0,y0;intxs[]={1,1,-1,-1,2,2,-2,-2};intys[]={2,-2,2,-2,1,-1,1,-1};CharC;inlineBOOLeq () { for(intI=0;i5; i++) for(intj=0;j5; j + +)if(Ans[i][j]!=now[i][j])return 0; return 1;} InlinevoidSwapint*a,int*b) { intt=*A; *a=*b; *b=T;} Inlineintminsteps () {inta=-1; for(intI=0;i5; i++) for(intj=0;j5; j + +)if(Ans[i][j]

on others to give you the wrong, so that your level is not how much improvement. Okay, no more nonsense, put the code (the level is too low, can only write so long code to =)#include #includestring.h>intMain () {Charpuzzle[6][6],move[ +],temp; intI,j,k,si,sj,flag,count=0; while(Gets (puzzle[0])!=nullstrcmp (puzzle[0],"Z")!=0) {Count++; Flag=1; for(i=1; i5; i++) {gets (puzzle[i]); } for(i=0;i5; i+

Topic linksViolence DFS of course notSo iterate and deepen it. ida*1#include 2#include 3#include 4 using namespacestd;5 intTt,k,flag;6 intans[5][5]=7 {8{1,1,1,1,1},9{0,1,1,1,1},Ten{0,0,2,1,1}, One{0,0,0,0,1}, A{0,0,0,0,0} - }; - intxx[8]={1,1,-1,-1,2,2,-2,-2},yy[8]={2,-2,2,-2,1,-1,1,-1}; the intPD1 (inta[5][5]) - { - for(intI=0;i5; i++) - for(intj=0;j5; j + +) + if(Ans[i][j]!=a[i][j])return 0; - return 1; + } A intPD2 (int

) .... A5204205 Hardware Location Code ... U0.1-p1/e2 PLATFORM specific Name: Ethernet Node: [email protected] Device Type: Network Physical Location:u0.1-p1/e2 Physical Locationlocation to determine if the NIC is plugged into the PCI interface [[email protected]/] #lsslot-C PCI# Slot Description Device (s)U0.1-p2-i1 pci-x capable, + bit, 133MHz slot EmptyU0.1-p2-i2 pci-x capable, + bit, 133MHz slot EmptyU0.1-p2-i3 pci-x capable, 133MHz slot FCS0U0.1-p2-i4 pci-x capable,

1. There are 5 students, each of whom has a test score of 3 courses in Chinese, maths and foreign languages. Programming statistics The total score and average scores of each student and the average score of all students in each section. Requires that the results be initialized in the program, and the result is output in tabular form. #include #defineN 5#defineM 6#defineL 3intMain () {intI,j,sumi,sumii,flag; Doublescore[n][m]={{1, -, the, -},{2, the, the, the},{3, the, +, -},{4, the, the, the},

(1) Each conversion column can appear three times at most, because if it appears four times, it is equivalent to turning a circle, equal to 0. There are a total of 4 ^ 9 cases, which can be traversed. For example: Void DFS (INT clocks []) { For (INT I1 = 0; I1 For (INT I2 = 0; I2 For (INT I3 = 0; I3 For (INT I4 = 0; I4 For (INT I5 = 0; I5 For (INT I6 = 0; I6 For (INT i7 = 0; i7 For (INT i8

overclock, but servers can only reduce the frequency and not exceed. In addition, the CPU and Xeon series in the same period are much more expensive than the home-level I3 I5 I7, which is very cost-effective. Understanding servers is actually to learn about redundant memory, redundant hard disks, redundant CPUs, redundant power supplies, and BMC remote management. It can be said that the household machine is a high startup, but the base is thin and

Configuration: [root@aix211 /]#lscfg -vpl en0[root@aix211 /]#lscfg -vpl et0[root@aix211 /]#lscfg -vpl ent0 ent0 U0.1-P1/E2 10/100 Mbps Ethernet PCI Adapter II (1410ff01) 10/100 Mbps Ethernet PCI Adapter II: Network Address.............000255CF1406 ROM Level.(alterable).......SCU015 Product Specific.(Z0).......A5204205 Hardware Location Code......U0.1-P1/E2 PLATFORM SPECIFIC Name: ethernet Node: ethernet@1 Device Type: network Physical

The difference between static and non-static is only revealed if the value is initialized during runtime. Because the values during compilation are considered by the compiler to be phaseThe same. Packagethinking; Public classFinalData {//Can be Compile-time constants Final intI1 = 9; Static Final intI2 = 99; //Typical public constant: Public Static Final intI3 = 39; //cannot be Compile-time constants: Final intI4 = (int) (Math.random () *20); Static Final inti5 = (int) (Math.random ()

DEMO Program: Testsemaphore_demo.rarSource code: Testsemaphore_src.rar---Key code is as follows---voidCtestsemaphoredlg::onbnclickedbuttonthread1 () {//TODO: Add control notification handler code hereAfxBeginThread (Afx_threadproc) Thread1writea, This);}voidctestsemaphoredlg::onbnclickedbuttonthread2 () {//TODO: Add control notification handler code hereAfxBeginThread (Afx_threadproc) Thread2writeb, This);}voidctestsemaphoredlg::onbnclickedbuttonthread3 () {//TODO: Add control notification handl