identifying polygons

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QT Graphics (Qpainterpath)

this path. This function is much faster than the exact boundingrect () that returns the bounding rectangle of this painter's path using floating-point precision. Finally, Qpainterpath provides a contains () function that determines whether the given point or rectangle is within the path. and the intersects () function, which determines whether any point within a given rectangle is also within that path. Qpainterpath Conversion For compatibility reasons, you may want to simplify the representati

python-Obtaining operating System Information

() Platform.python_compiler () Platform.python_branch () platform.python_implementation () Platform.python_revision () platform.python_version () platform.python_version_tuple () " "#Global Var#whether to display log informationShow_log =Truedefget_platform ():" "get the operating system name and version number" " returnPlatform.platform ()defget_version ():" "get the operating system version number" " returnplatform.version ()defget_architecture ():" "get the number of bits in the operat

Odoo 8.0 New API Overview

decoration traditional style decoration class, while realizing the inheritance of returns decorationGuess: This decorating method can be called either by the traditional style or by the record style.Noguess: Stop all guess functionsModel: Decorate the Record-style method with self as the recordsetMulti: The same model, the difference is that the model in the equivalent of Traditional-style in the Model.method (Cr,uid,args,context=context), and Multi for Model.method (CR , Uid,ids,args,context=c

Python daily Class (2): Platform

() Platform.python_compiler () Platform.python_branch () Platform.python_implementation () platform.python_revision () platform.python_version () Platform.pyth On_version_tuple ()" "#Global Var#whether to display log informationShow_log =Truedefget_platform ():" "get the operating system name and version number" " returnPlatform.platform ()defget_version ():" "get the operating system version number" " returnplatform.version ()defget_architecture ():" "get the number of bits in the operat

H5 Game Development Polygon Collision Detection (Java code)

Reprint to: http://www.cnblogs.com/Kurodo/archive/2012/08/08/2628688.html for a rectangular collision, many people know.But in the face of Polygon graphics, most of the way to use multi-rectangle overlay. But I don't really like this way, I'm using a classic algorithm: SAT a fast detection of irregular convex polygon collision of the algorithm to give two convex polygons, if we can find an axis, so that the two objects on this axis projection does not

A detailed approach to drawing using Java graphics Classes _java

The Graphics class provides basic drawing methods, and GRAPHICS2D classes provide more powerful drawing capabilities. This section explains the graphics class, the next section explains Graphics2D. The Graphics class provides basic geometry rendering methods, which include: drawing segments, drawing rectangles, drawing circles, drawing with color graphics, drawing ellipses, drawing arcs, drawing polygons and so on. 1. Draw LineTo draw a line segment

bzoj2618cqoi2006 Convex polygon __bzoj

2618: [Cqoi2006] Convex polygon Time Limit:5 Sec Memory limit:128 MBsubmit:878 solved:450[Submit] [Status] [Discuss] The vertex coordinates of n convex polygons are given by Description , and the area of their intersection is obtained. For example, when n=2, two convex polygons are shown below: The area of the intersecting part is 5.233. Input The first line has an integer n, which indicates the number of

Drawing method of Java Graphics class __java

Graphics class provides basic drawing methods, graphics classes provide basic geometry rendering methods, mainly include: Draw line segments, draw a rectangle, draw a circle, draw the color of the graphic, draw the ellipse, draw arcs, draw polygons, draw strings and so on. Draw Segment To draw a line segment in a window, you can use the DrawLine () method of the Graphics class: /** * Draw a line between the dots (x1, y1) and (x2, y2) in the coordinat

10 design trends to focus on in the 2018

position at the bottom not enter the user's view for the first time, but it is the main area of vision and is not visually aggressive and more acceptable. The content suspended at the bottom of the screen is more natural than the pop-up ads and the top ads, and will not obscure the main content and be more effective. 4, voice interaction and semantic search It is conceivable that the future of web design will not be 100% pure vision, which will be more or less designed to audio. From the inte

The first experience of Fireworks MX2004 's shapes (two

in the edge direction? Inside also appeared a polygon, and added a reset Inner Polygon (restore original) control point, the specific operation and the above described the operation of the ring is basically similar! Please feel it yourself. Change effect please look at the following figure: Number 4th: Select the point, the Prompt box appears: sides:7; Alt/opt-drag to split (number of edges: 7; With alt/opt drag to split) This control point is also more interesting, select the point and then d

Determine if the point is in the polygon

One, determine if the point is in the polygon (theory) To determine whether point P is a very basic but very important algorithm in the computation geometry in the polygon. With point P as the endpoint, to the left as the Ray L, because the polygon is bounded, so the left side of the Ray L must be outside the polygon, considering moving from left to right along L from Infinity, to the first intersection of the polygon, to the interior of the polygon, to the second intersection, to the polygon,

Java and MATLAB drawing polygon closed Line diagram example explanation _java

front of the nPoint-1 is when 1≤i≤npoints, from (Xpoints[i-1], ypoints[i-1]) to (Xpoints[i], ypoints[i]). If the last point is different from the first, the graph is automatically closed by drawing a line segment between the two points. The code example is as follows: Copy Code code as follows: Import java.applet.*; Import java.awt.*; public class Drawpicture extends Applet {public void Paint (Graphics g) { int px[]={20,70,130,240}; int py[]={20,150,100,130}; G.d

A ramble on the R language map

Original address: Click to open the link The R language has a commendable ability to visualize, and in this article, we try to use the R language to show map data, which is to draw a map and show the distribution of the data on the map. Because the Chinese map of the R language is too old, we are looking for an external map data file and loading and displaying the map in R. The map data file we use is a shapefile-formatted file that stores the geometric location and attribute information of geog

"Pick Up the Flowers" Memory (ii) Java memory Recycling

algorithm The algorithm is also known as the mark-and-organize (mark-and-compact) algorithm, as the name implies, is to mark the surviving objects, organize the reclaimed space . As shown above, the algorithm and the tag-purge algorithm first tag the surviving object, and then clear the unmarked object, the object that is not alive. But unlike the tag-purge algorithm, the algorithm has a finishing process, after reclaiming the space of the objects that are not surviving, will move all the surv

Windows GDI Drawing Basics

corners.ARC draws an oval line. ARC (hdc, Xleft, Ytop, Xright, Ybottom, Xstart, Ystart, Xend,yend)Chord Bow Chord (Hdc,xleft, Ytop, Xright, Ybottom, Xstart, Ystart, XEnd, Yend)Pie appeased Chart Pie (hdc, Xleft, Ytop, Xright, Ybottom, Xstart, Ystart, XEnd, yend);ArcTo and Anglearc draw oval lines.PolygonPolygon (Hdc,apt,icount);//Draw a polygon, and the last point is connected to the 1th.Polypolygon (Hdc,apt,aicount,ipolycount); Draw multiple polygons

Definition and illumination of WPF 3d:meshgeometry3d

Definition and illumination of the original WPF 3d:meshgeometry3dBecause WPF calculates the illumination based on the direction vectors of the entire plane, it may achieve different lighting effects if the same point is used on different faces. Let's illustrate this problem with a different way of defining mesh.To define two simple intersecting polygons, the main view of the entire graph can be referenced as a convenience:The first method is to use th

OpenCV growth Path: Extraction and description of lines and contours

parameters in the program outline includes all points, you can also use other parameters to let a bit of straight place, only the line start and end point of the location, the specific parameters can be used to refer to the description of the function in the manual.The second function drawcontours is a contour function, its 3rd parameter program set 1 means that all the contours are drawn, you can also specify the outline to be drawn the ordinal number.After extracting to the contour, in fact,

"Bzoj 2618" 2618: [Cqoi2006] convex polygon (semi-planar intersection)

2618: [Cqoi2006] Convex polygon Description counter-clockwise gives the vertex coordinates of n convex polygons, and asks them to cross the area. For example, when n=2, two convex polygons such as: The area of the intersecting portion is 5.233.Input The first line has an integer n, which represents the number of convex polygons, and the following describ

POJ 1389 (discretization + computational geometry)

Area of simple polygons Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3412 Accepted: 1763 DescriptionThere is n, 1 Assume that the contour of their union was defi Ned by a set S of segments. We can use a subset of S to construct simple polygon (s). Please report the total area of the polygon (s) constructed by the subset of S. The area should is as large as possible. In a 2-d

Euler's formula in geometry: V-e+f = 2

Euler formula in geometry: v-e+f = 2,v, E, F represents the number of vertices, sides, and polygons of simple geometry.Prove:There are many proofs of it, and a recursive method is presented here.For any simple geometry (the boundary of the geometry is not a curve), we look at each face of the geometry, set the edge into an N-shaped shape, we connect the other vertices from a fixed vertex, we are going to triangulate the N-shape from a vertex, we assum

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