ihome melody

DescriptionSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length.Little hi has practiced a lot of music and found that many of the works themselves contain the same melody. Melody is a continuous sequence of numbers, similar melodies can overlap in the original sequence. In

)? L: ++l;if(l >= N) Break; m = l; } for(RGinti =1, j =0; I 0, J-1); while(A[j + i] = = A[sa[rk[i]-1] + j]) ++j; Height[rk[i]] = j; }}ilintLCP (RGintXX, RGintYY) {xx = rk[xx]; yy = Rk[yy];if(xx > yy) swap (xx, yy); ++xx; RgintL = lg[yy-xx +1];returnMin (st[l][xx], St[l][yy-(11]);} ILintCalc () {RGintAns =0; for(RGintL =1; L for(RGinti =1; i + L intLen = LCP (i, i + L); ans = max (ans, len/l +1);if(I >= l-len% l) ans = max (ans, LCP (i-l + len% l, i + len% l)/L +1); }returnAns;}intMain

Difficult Melody (ing), difficultmelody Question Link Http://vjudge.net/contest/137242#problem/D DescriptionYou're addicted to a little game called 'Remember the melody ': you hear some notes, and then you repeat it. in most cases, the longer the melody, the harder to repeat, but it isn' t always true. also, melodies of the same length are usually not equally ea

Suffix array two • Repeat Melody 2 time limit: 10000ms single point time limit: 1000ms memory limit: 256MB descriptionSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length. Little hi has practiced a lot of music and found that many of the works themselves contain the same melody.Melody can be expressed as a continuous

Konjac Konjac know today only to play suffix array, and still nlogn^2 ... But it's basically a run-through;Repeat Melody 1:Two-point answer, the height of the collection, HeightMade by qt666#includeRepeat Melody 2:Similar to the above question, the two answers, the height of the set, maintain the most left and right side of the set, to judge the end of the subtraction >=mid;Made by qt666#includeRepeat

[NQ]=Fa[q]; memcpy (Ch[nq],ch[q],sizeof(Ch[nq])); FA[Q]=fa[np]=NQ; LEN[NQ]=len[p]+1; DEP[NQ]=dep[p]+1; for(; ch[p][c]==q;p=fa[p]) ch[p][c]=NQ; }} last=NP;}voidADD (intx,inty) {x+=y; X-=x>=mod? MoD:0;} intMain () {intN; scanf ("%d",N); intL; while(n--) {scanf ("%s", s+1); L=strlen (s+1); for(intI=1; i'0'); if(n) Extend (Ten); } for(intI=1; i; for(intI=1; i1]; for(intI=1; ii; sum[1]=1; intx; for(intI=1; ii) {x=Sa[i]; for(intj=0;jTen;++j)if(Ch[x][j]) {ADD (sum[ch[x][j]],sum[x]); ADD (Val

Suffix array one • Repeat Melody time limit:5000msSingle Point time limit:1000msMemory Limit:256MBDescribeSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length.Little hi has practiced a lot of music and found that many of the works themselves contain the same melody.

. Assuming that we have selected a bunch of points, then for unselected points, there must be an inverse pair with one of the points. Use the mathematical formula to show that this is the case:$\forall a_i \notin v_1$, must $\exists a_j \in v_2$ make $a_i>a_j$ and $iSo next consider a fragment on the sequence $ (l,r) $, where $l,r$ are already the points that have been king-James. Then for all points in $ (l,r) $ $a_i$, must not meet $a_l \leq a_i \leq a_r$.But there can be no one point satisfyi

1, we click on the phone "cool music" open into. 2, and then we click on "More Buttons." 3, and then we click to listen to music. 4, click the Start Identification button, and then try to hum the melody or play music. 5, waiting for the system to identify the song. 6, the song recognition completes, at this time, we can find the song name which oneself wants! What do you say, fun? Don't hurry up and try!

Suffix array four • Repeat melody 4 time limit:5000msSingle Point time limit:1000msMemory Limit:256MBDescribeSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length. Little hi has practiced a lot of music and found that many of the melodies in the works have duplicate parts.We call a

#1415: suffix array three • Repeat Melody 3Time limit:5000mscase time limit:1000msmemory limit:256mb descriptionSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length. Little hi has practiced a lot of music and found that many of the melodies in the works have a common part.Melody is a continuous series, if the same

Suffix array two • Repeat Melody 2 time limit:5000msSingle Point time limit:1000msMemory Limit:256MBDescribeSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length. Little hi has practiced a lot of music and found that many of the works themselves contain the same melody.Melody can be expressed as a continuous sequence

Suffix Automaton three • Repeat melody 6 time limit:15000msSingle Point time limit:3000msMemory Limit:512MBDescribeSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers.Now little hi wants to know the number of occurrences of the most frequently occurring melody in any

#1407: suffix array two • Repeat Melody 2Time limit:5000mscase time limit:1000msmemory limit:256mb descriptionSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers consisting of N in length. Little hi has practiced a lot of music and found that many of the works themselves contain the same melody.Melody can be expressed as a continuous sequenc

#1445: suffix automaton two • Repeat Melody 5 time limit:10000msSingle Point time limit:2000msMemory Limit:512MBDescribeSmall hi usually a big hobby is playing the piano. We know that a musical melody is represented as a series of numbers.Now little hi wants to know how many different melodies there are in a work?Tips on how to solve problemsInputA common row that contains a string of lowercase letters. The

HihoCoder_1445 _ suffix 2. Repeated melody 5,#1445: suffix 2. Repeated melody 5 time limit: Ms single point time limit: Ms memory limit: MB description Xiao Hi's usual hobby is playing the piano. We know that a Music Melody is represented as a series of numbers. Now, Xiao Hi wants to know how many different melodies appear in a piece of work? Solution tipsInput C

At the beginning of the submission, I was surprised to find out.Checked n times finally found strlen written in the For loop, so that the calculation of time complexity is n^2Problem Solving Ideas:Find the B string in the position where a string appears.Then we calculate the height array separately for a string, and then enumerate each position to find the substring that can be generated, and then the height can be reduced.#include Lightoj 1428 Melody

Topic: Given an undirected graph, find out how many strong connected graphs are in the generated sub-graph of this undirected graphWe think about the principle of repulsion.If a graph is not connected, then this image will be indented to form a dag with a >=2 point.There must be some 0 points in a DAG, and we enumerate the point sets of these points for the repulsionSpecific DP equations and details see code comments written or more detailed I won't say more = =#include Principle of Bzoj 3812

same peak. In addition to the British rock invasion boom brought by their headers, their records were considered "Too American" and were left cold by consumers. Despite their continued efforts, however, the fate cannot be changed. The members of the Communist Youth League had a strong fight, and even John ganmo, who was responsible for creating most of the songs, had exited. In 1969, only the sakex operator was the original member, of course, there is no chance to make a comeback. However, alth

ho: So the key is |valid-substrings (ST) | How did you find out?Little hi: Yes. |valid-substrings (ST) | Represents the number of substrings in the St without a colon, which is exactly the amount of all paths from the initial state s to the state St for all "sides without a colon".Little ho: It seems a bit around.Small hi: For example, for state 6, if we do not go through a transfer labeled ': ', then there are 2 paths from S to 61, which are s->6 and s->5->6, respectively, corresponding to sub