int min value

1 /*2 * question:3 * design a stack containing min4 * defines the stack data structure. A Min function must be added to obtain the minimum element of the stack.5 * the time complexity of the min, push, and pop functions is required to be O (1)6 */78

Min StackDesign a stack that supports push, pop, top, and retrieving the minimum element in constant time. Push (x)-push element x onto stack. Pop ()--Removes the element on top of the stack. Top ()--Get the top element. Getmin (

Original title: https://oj.leetcode.com/problems/min-stack/solution/Implements a minimum stack of push (int x), pop (), Top (), Min () methods, which require constant timeThis code has been Leetcode accepted, the following analysis results are given

Idea: 1: Add two fields to the data structure of the stack, such astypedef struct {int Data[max]; // all numbers in the storage stackint top; // the top element of the storage stackDatathe position in the arrayint min; // Minimum Valueint second;//

These days, in order to sort out the driver knowledge that ldd3 learned some time ago, I went to look at the USB driver. I don't know, but I was shocked. There are a lot of syntaxes in it, which I found to be great at using. It's not like writing

We recommend that you use the following min macro definition in the GCC document:Reference: # define min (x, y )/(_ Extension __/({/Typeof (x) _ x = (x), _ y = (y );/(_ X })/)This article discusses the significance of this practice.1. Side effects

The sword refers to the offer --- stack containing min, and the sword refers to the offer --- min Idea: This question is mainly used to supplement the stack's min method. For example, the stack has built-in methods such as pop, push, and peek. Each

The maximum and minimum values of the calculation do not need to be compared twice on the Forum. Some people gave the best answer during the first discussion. That person said that when performing image operations, comparison operations will have a

There are n coins with different denominations. The denominations of each coin are stored in the array T [1: N. Now we need to use coins with these denominations to find money. The number of coins with various denominations that can be used is

#include #define N 5/* by row pointer p and two-dimensional array subscript i,j; Gets a pointer to a two-dimensional array element */int *getelementpoint (int *p,int i,int j){Consider a two-dimensional array as a one-dimensional array, assuming a[i][