Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float Totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100);

Turn from:Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*1

Method 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemNum=3;float totalPrice=price*itemNum;float num=(float)(Math.round(totalPrice*100)/100);//如果要求精确4位就*10000然后/10000Method 2: Return with

Float rounding Keep Two decimal places note the placeRecently in Codewars did a very simple topic, but it took me 20 minutes, although the final solution, but in the middle found that the foundation of Java is not really, go back to a good fixDo not

How to make float keep two decimal places or decimal placeshttp://meryvn.blog.163.com/blog/static/36962664201173010402629/Two methods:Import java.math.*;......Method 1:float F = 34.232323;BigDecimal B = new BigDecimal (f);Float F1 = B.setscale (2,

In javascript, regardless of Single-precision float and double-precision, all decimal variables are regarded as float. Therefore, to obtain the n digits after decimal places, use the toFixed (n) method to obtain
Convert js numbers to float and take

Example 1Float f = 34.237323f;BigDecimal B = new BigDecimal (f );Float f1 = B. setScale (2, BigDecimal. ROUND_HALF_UP). floatValue ();System. out. println (f1 );Method 2:Float f = 34.232323;BigDecimal B = new BigDecimal (f );Float f1 = B. setScale (2

Convert js numbers to float and take N decimal places:
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All variables in javascript are weak types, and all variables are declared as var, which is not as convenient as java during the

/*** Java two integers divide two decimal places and convert decimals to percentages* In Java, when two integers are divided, because the number after the decimal point is truncated, the result of the operation will be an integer, if you want to get

Java methods for preserving decimal problems:Method One: Rounding using Java. Math.bigdecimal class Double d = 12.345;BigDecimal bd = new BigDecimal (2,bigdecimal.round_half_up). Doublevalue ();Method Two: Use the Java.text.DecimalFormat

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