java programming language 4th edition

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Wuhan University of Science and Technology acm:1005: Chinese Edition C language Programming tutorial (second Edition) example 5.8

Problem DescriptionThe teacher gave a title to Xiao Hao: give you two integers x and n ( -10now that little Howe is in a quandary, please help him solve the problem. InputEnter two integers x and n per line.Outputfor each set of test data, the output line evaluates. Sample Input1 12 2Sample Output16HINT1#include 2 3 4 Long LongSumintXintN)5 {6 Long Longs=0;7 inti,j;8 Long LongS1;9 for(i=1; i)Ten { Ones1=1; A for(j=1; j) - { -s1*=x; the } -s+=S1; - } -

Wuhan University of Science and Technology acm:1001: Chinese Edition C language Programming tutorial (second edition) Exercise 6.7

Problem DescriptionThe output Yang Hui the first n rows of the triangle.InputEnter a number n (n OutputThe output Yang Hui the first n rows of the triangle. (Note that there is no extra space at the end of the line, the number is output in%3d format)Sample Input34Sample Output 1 1 1 1 2 1 1 1 1 1 2 1 1 3 3 1HINTNote that there are multiple sets of inputs. Output a blank line after each set of test data.while (scanf ("%d", n)! = EOF){......}1#include 2 i

Wuhan University of Science and Technology acm:1007: Chinese Edition C language Programming tutorial (second edition) Exercise 7.10

Problem DescriptionEnter n (nInputExample of multi-group test sample. The first row of each group has an integer n indicating that there are n strings. Next there are n rows, one string per line.OutputOutput a sequential string, with each line outputting a string.Sample Input3abaaabcabSample OutputAababacab1#include 2#include string.h>3 voidSortChar* str[],intsize)4 {5 inti,j;6 Char*tmp;7 for(i=0; i1; i++)8 {9 for(j=i+1; j)Ten { One if(strcmp (str[i]

Wuhan University of Science and Technology acm:1001: Chinese Edition C language Programming tutorial (second Edition) after class exercise 3.12

Problem DescriptionEnter n, and the output corresponds to a hollow positive hexagon with a side length of N.For easy viewing, the sample midpoint '. ' Represents a space and prints a space instead of a small dot when plotting a drawing.InputEdge length N. (NOutputSide length is a positive hexagon of nSample Input5Sample Output.....*****....*.....*...*.......*.. *.........*.*...........*.. *.........*...*.......*....*.....*.....*****1#include 2#include 3 voidPrtCharCintcount)4 { 5 while(cou

Wuhan University of Science and Technology acm:1006: Chinese Edition C language Programming tutorial (second edition) Exercise 7.15

Problem DescriptionEnter n strings (nInputMultiple sets of test data. The first row of each set of test data contains an integer n, representing a total of n strings. Next, each line contains a string that consists of printable characters.OutputEach set of test sample output one row. The output finds a string that satisfies the test instructions.Sample Input3djdlkfjsadfjwedlkfjdlkfjl;jf;sfjdsl;al/dljfd2dlkasfjmmlld;femflsad;fiwejdifSample OutputDlkfjdlkfjl;jf;sfjdsl;al/ld;femflsad;fiwejdif1#incl

Wuhan University of Science and Technology acm:1009: Chinese Edition C language Programming tutorial (second Edition) example 4.18

Problem DescriptionVerify Goldbach conjecture that any even number of sufficiently large (>=4) can be represented by a sum of two primes.InputEnter an even n. (2OutputFind A, B make n=a+bWhere A and B are two primes, and aSample Input4100Sample Output2 23 971#include 2 3#include 4 5 using namespacestd;6 7 intPrimeintm)8 9 {Ten One intI,n; A - if(m==1)return 0; - theN= (int) sqrt (Double) m); - - for(i=2; i) - + if(m%i==0)return 0; - +

Wuhan University of Science and Technology acm:1007: Chinese Edition C language Programming tutorial (second Edition) example 4.13

+ if((m%i==0) (n%i==0)) - $ { $ -printf"%d%d\n", i,m*n/i); - the Break; - Wuyi } the - } Wu - } About $ } - -}Other code:1#include 2#include 3 intgcdintAintb)4 {5 if(a%b==0)6 returnb;7 Else8 returnGCD (b,a%b);9 }Ten intLcmintAintb) One { A returna

Wuhan University of Science and Technology acm:1004: Chinese Edition C language Programming tutorial (second Edition) Exercise 5.6

Problem DescriptionThis day the teacher again to small Hao out a topic: give you three lengths, respectively, A,b,c match, let you calculate the three matches can make up of the Triangle area.InputEnter each row to include three number a,b,c.OutputThe area of the output triangle for each row (reserved three decimal places), cannot be composed of triangles told the small Hao output "no!".Sample Input1 2 33) 4 5Sample Outputno!6.000HINT1#include 2#include 3 intMain ()4 {5 Doubles,a,b,c,p;6

Wuhan University of Science and Technology acm:1009: Chinese Edition C language Programming tutorial (second Edition) example 5.4

Problem DescriptionThe teacher gave a title to Xiao Hao: give you a value of n (within 32 bits) in seconds, let you convert to: minutes: seconds output. Now that little Howe is in a quandary, please help him solve the problem.InputEnter a positive integer of n seconds per line.Outputfor each set of test data, output a row of results: minutes: seconds. (24-hour system)Sample Input560Sample Output00:00:0500:01:00HINT#include intHh,mm,ss;voidConvertime (Longsec) {hh=sec/3600; MM= (sec-hh*3600L)/ -;

C ++ programming ideology (second edition) Chapter 2nd object creation and use (exercises and answers), java programming ideology (second edition)

C ++ programming ideology (second edition) Chapter 2nd object creation and use (exercises and answers), java programming ideology (second edition) Exercise-related code Hello. cpp Stream2.cpp Nomconv.cpp Fillvector.cpp 2-1 modify Hello. cpp so that he can print your name

Thinking in Java,fourth Edition (Java programming Idea, Fourth edition) study notes (eight) polymorphism

to call inside a constructor is those that is final in the base class. (This also applies to private methods, which is automatically final.)Convariant return typesJava SE5 adds convariant return types, which means, a overridden method in a derived class can return a type derived From the type returned by the Base-class methodDesigning with InheritanceIf you choose inheritance First when you ' re using a existing class to make a new class, things can become needlessly comp Licated.A better appro

Thinking in Java,fourth Edition (Java programming Idea, Fourth edition) Learning notes (11) Holding Your Objects

objects of a known type,can is multidimensional, can hold primitived. However, its size cannot is changed once you create it.2. Collection:hold single elements, automatically resize, won ' t hold Primitives3. Map:holds associated pairs, automatically resize, won ' t hold Primitives4. Like an array, a List of also associated numerical indexes to Objects--thus,arrays and Lists is ordered containers.5. The behavior of Queues and stacks is provided via the LinkedList6. A Map is a-to-associate not i

Wuhan University of Science and Technology acm:1003: Chinese Edition C language Programming tutorial (second Edition) example 6.6. Adaptation

Problem DescriptionWowapps most like to learn English, English class never skip class, but English has not been learned, because the class has been sleeping. Why do you sleep, because he thinks the English word is too long. Now Wowapps has a long, long, long word and wants to compress it. Can you help him?Compression: Replaces consecutive repeating letters with one, see sample for details.InputEnter an n first to indicate the number of words Wowapps give (1Next n lines, each behavior of a string

Wuhan University of Science and Technology acm:1002: Chinese Edition C language Programming tutorial (second Edition) example 6.6

Problem DescriptionTomorrow will be the English exam, Wowapps is Midnight Oil recite the words. Wowapps found the word difficult to recite, the back one forget. After careful study, Wowapps found that the reason why the word is difficult to recite is because of the appearance of a character, destroying the beauty of the whole word, resulting in poor memory. Wowapps decided to destroy these discordant characters on behalf of the Moon!! (Applause!!) But the exam has entered the countdown, and Wowa

Wuhan University of Science and Technology acm:1004: Chinese Edition C language Programming tutorial (second Edition) after class exercise 3.7

Problem DescriptionEnter an unsigned short integer k[hex.] and P[oct.], the high byte of K as the low byte of the result, and the high byte of p as the result of the high byte to form a new integer.InputK[hex.] and P[oct.]OutputThe operation gets the new integer n.Sample Input0XD9 01117Sample Output200HINTOutput is 16 binary1#include 2 intMain ()3 {4 5 intk,p;6 while(SCANF ("%x%o", k,p)! =EOF)7 {8 intNewint = (p0xff00)| (k0xff00) >>8;9printf"%x\n", newint);Ten }

Wuhan University of Science and Technology acm:1009: Chinese Edition C language Programming tutorial (second edition) Exercise 5.12

Problem Descriptionthis day the teacher as a routine to small Hao out a topic: The teacher to small Hao a string, let small Hao will the string in reverse order output. InputThe first line includes a T, which indicates how many sets of test data are:Next T line, each line includes a string (length not exceeding 65535).OutputFor each test data output it's reverse string.Sample Input1oaHoaiX EvoL ISample OutputI Love Xiaohao1#include 2#include string.h>3 intMain ()4 {5 intL,i,n;6 Chara[655

Wuhan University of Science and Technology acm:1008: Chinese Edition C language Programming tutorial (second edition) Exercise 6.14

Problem DescriptionEnter an octal string, convert it to an equivalent decimal string, and output it in the PRINGF%s format.InputFirst, a positive integer t is entered, indicating that there is a T set of test data (1Next T line, one string per line, representing an octal integer (this integer is no more than 20 bits).OutputFor each test data, output the corresponding decimal string. One line per string.Sample Input11732Sample Output986HINTNote: The given octal number may be large, with a long lo

Java language guidance (fifth edition of the original book), fifth edition of guidance

Java language guidance (fifth edition of the original book), fifth edition of guidance Chapter 1 Quick Start Chapter 2 Object-Oriented Programming Concepts Chapter 3 language basics 1. Usage of continue Chapter 4 class and obj

Buy myeclipse Send book Activities | Effective Java Chinese version (2nd edition) "Java Programming Idea (section

Buy Classic Java IDE myeclipse send Java Classic best-selling book: Basic version of the book Yas Block masterpiece "Effective Java Chinese version (2nd edition)", buy advanced version of the programmer must book "Java Programming

"Network programming Notes" Simple TCP protocol Socket programming (C language Edition Server and client)

(addrserver,0,sizeof(Addrserver));//Initialize Amemcpy ( (ADDRSERVER.SIN_ADDR), host->h_addr, host->h_length);//Set IP -addrserver.sin_family = af_inet;//Set the version number -Addrserver.sin_port = htons ((unsigned Short) server_port);//set the port number the - //connect .... Initiating a link to the server - if(Connect (SOCKFD,structSOCKADDR *) addrserver,sizeof(structsockaddr ))) - { +printf"Connect error!\n"); -Exit1); + } Aprintf"Connection Server succeeded Connec success...\n\n");Next

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