jmp cycles

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How nt loads ntldr nt guidance (MBr-> DBR-> ntldr)

small hard disk): 0001.0048 7732 ja 007c; if the value is greater than 0: 0001.004a 668b461c mov eax, [bp + 1C]; eax = number of hidden sectors: 0001.004e 6683c00c add eax, 0000000c; number of hidden sectors + 0c: 0001.0052 bb0080 mov BX, 8000; BX = 8000: 0001.0055 b90100 mov CX, 0001; Cx = 1: 0001.0058 e82b00 call 0086: 0001.005b e94803 JMP 03a6; 03a6 ?????? * Referenced by a (u) nconditional or (c) onditional jump at address:|: 0001.0106 (c)|: 0001

Basic Techniques for writing viruses

main boot program moves itself from 0000: 7c00; 0000: 0600 place, for the DOS partition boot program Teng; Outbound Space0018 ea1d060000 JMP 0000: 061d; jump to 0000: 061d to continue execution, which is actually; Execute the following mov command (at the offset of 001d)001d bebe07 mov Si, 07be; 07be-0600 = 01be, 01be is the first address of the Partition Table0020 b304 mov BL, 04; up to four partition tables, that is, up to four partitions0022 803c8

Linux kernel preemption

enable_interrupts (Clbr_none) fixup_top_of_stack%r11,-argoffset//If there is a signal, unconditionally jumpJMP Int_check_syscall_exit_work/* ... Omit ... * /GLOBAL (Int_ret_from_sys_call) disable_interrupts (clbr_none) Trace_irqs_off MOVL$_tif_allwork_mask,%edi / * Edi:mask to check * /GLOBAL (Int_with_check) Lockdep_sys_exit_irq Get_thread_info (%RCX) Movl Ti_flags (%RCX),%edxAndl%edi,%edxJNZ int_careful Andl$~Ts_compat,ti_status (%RCX) JMP Retint_

Intel, AMD and via CPU micro-architectures (17)

enough to handle the instruction fetch around the jump without delay. If the Ifetch block that contains the jump crosses a 16-byte boundary, the double buffer needs to hold two contiguous 16-byte blocks of code before producing a valid Ifetch block. This means that, in the worst case scenario, the decoding of the first instruction after a jump delays 2 clock cycles. In the Ifetch block containing the jump instruction, the cost of a 16-byte boundary i

Overflow programming skills in WINDOWS

Once accused by cnns of being plagiarized, see blind tone for specific events. Overflow programming skills in WINDOWSAuthor: Yuan GeAfter reading some overflow programs in WINDOWS, I felt that they were not uniform and perfect. I decided to write a relatively unified method and tried to solve some problems.1. jmp esp problems.KERNERL32 is used to ensure consistency. DLL code, because at least the same system KERNEL32. The DLL module load address may

Protection Mode _ 1

determined that the content of the hidden part is consistent with the content of the segment descriptor (see the format of the segment description ), however, the format may be different. But the format is not important for us to understand this, because it is impossible for programmers to directly operate on it. We use the CS register as an example. The same is true for other registers: In real mode, when we execute a command to load the CS register (JMP

[Practice] SQL Server 2000 sp2 12 Command overflow attack implementation

], ECx. Text: 42cf7326 mov edX, [EBP + arg_0]. Text: 42cf7329 mov eax, [EBP + var_224]. Text: 42cf732f mov ECx, [eax] We can find that the above values mainly involveOverwrite address-8Overwrite address + 4Overwrite address + 8Overwrite address + cOverwrite address + 10Overwrite address + 14These addresses are mainly write operations.In addition, if you want to override address-4 and overwrite address + 4, you can perform an add operation. The address range of the operation should also be read/w

FASM DirectDraw Test

Ddraw_err; create the device environment handle on this page. The device environment is compatible with GDI, cominvk ddsprimary, getdc, HDC retjnz ddraw_err; output text invoke setbkcolor, [HDC], 0x000000ff invoke settextcolor, [HDC], 0x00ffff00 invoke textout, [HDC], [txtpoint. x], [txtpoint. y], stmsg, dwlenmsg invoke showwindow, [hwnd], sw_shownormal invoke updatewindow, [hwnd]; ========================================================== = msg_loop: invoke getmessage, MSG, null, 0, 0 retjz en

Differences between function calls: _ cdecl and _ stdcall

rep STOs dword ptr [EDI]41: int S, I;42:43: While (1)00401128 mov eax, 10040112d test eax, eax0040112f je input + 0c1h (004011d1)44 :{45: printf ("\ nplease input the first number M :");00401135 push offset string "\ nplease input the first number M"... (0020.b8)0040113a call printf (00401530)0040113f add ESP, 446: scanf ("% d", M );00401142 mov ECx, dword ptr [EBP + 8]00401145 push ECx00401146 push offset string "% d" (000000b4)0040114b call scanf (004015f0)00401150 add ESP, 847:48: If (M 004

Chapter 6: blasting Software

. Thank you for your support! "|: 004f4e2c b8004f4f00 mov eax, 004f4f00: 004f4e31 e8563df6ff call 00458b8c: 004f4e36 a16c305000 mov eax, dword ptr [0050306c]: 004f4e3b 8b00 mov eax, dword ptr [eax]* Possible stringdata ref from code obj-> "chinazip-registered version"|: 004f4e3d ba244f4f00 mov edX, 004f4f24: 004f4e42 e80de1f3ff call 00432f54: 004f4e47 33c0 XOR eax, eax: 004f4e49 5A pop edX: 004f4e4a 59 pop ECx: 004f4e4b 59 pop ECx: 004f4e4c 648910 mov dword ptr fs: [eax], EDX: 004f4e4f 686e4e4f0

Copy_from & to_user

); break ;\ Case 2: _ get_user_asm (x, PTR, retval, "W", "W", "= r", errret); break ;\ Case 4: _ get_user_asm (x, PTR, retval, "L", "", "= r", errret); break ;\ Default: (x) = _ get_user_bad ();\ }\ } While (0) # DEFINE _ get_user_asm (x, ADDR, err, itype, Rtype, ltype, errret )\ _ ASM _ volatile __(\ "1: mov" itype "% 2, %" Rtype "1 \ n "\ "2: \ n "\ ". Section. fixup, \" ax \ "\ n "\ "3: movl % 3, % 0 \ n "\ "XOR" itype "%" Rtype "1, %" Rtype "1 \ n "\ "JM

Use assembly to develop small file copy programs

CLD; fill 0, clear the last input file name MoV CX, 128; the maximum file name is 128 characters, including carriage return characters MoV Al, 0 Lea Di, fname Rep stosb ;------------- Lea dx, fbuffer; input file name MoV ah, 0ah Int 21 h ;------------------ MoV BL, [fbuffer + 1]; Replace the last carriage return of the input file name with 0, because the created file name cannot contain invisible characters Xor bh, BH MoV Si, offset fname Add Si, BX MoV byte PTR [Si], 0 ;--------------------- L

Analysis of bigfoot1 sample of Warcraft account theft

= 000E9FD5C 72B03E16 |ThreadFunction = PERrGx5D.72B03E1600E9FD60 00394700 |pThreadParm = 0039470000E9FD64 00000000 |CreationFlags = 000E9FD68 00394758 \pThreadId = 00394758 72B05D86 FF15 0C71B072 call dword ptr ds: [72B0710C]; kernel32.CreateThread 00E9FD54 00000000 |pSecurity = NULL00E9FD58 00000000 |StackSize = 000E9FD5C 72B03E42 |ThreadFunction = PERrGx5D.72B03E4200E9FD60 00394700 |pThreadParm = 0039470000E9FD64 00000000 |CreationFlags = 000E9FD68 0039474C \pThreadId = 0039474C Handler of t

PL/0 language compiler Analysis

return address Ra at runtime. Then, use tx0 to record the position of the current symbol table and generate a JMP command to jump to the starting position of the main program. As we do not know where the main program is started, therefore, the JMP target is set to 0 for the time being and will be changed later. At the same time, the position of the JMP command i

_ Stdcall and _ cdecl

intermediate code before and after it is irrelevant to this example)39: void winapi input (Int M, Int N)40 :{00401110 push EBP00401111 mov EBP, ESP00401113 sub ESP, 48 h00401116 push EBX00401117 push ESI00401118 push EDI00401119 Lea EDI, [ebp-48h]0040111c mov ECx, 12 h00401121 mov eax, 0 cccccccch00401126 rep STOs dword ptr [EDI]41: int S, I;42:43: While (1)00401128 mov eax, 10040112d test eax, eax0040112f je input + 0c1h (004011d1)44 :{45: printf ("" nplease input the first number M :");0040

Linux switch_to () In-depth Analysis

, % eax12. mov % ax, % FS13. incl jiffies14. movb $0x20, % Al15. outb % Al, $0x2016. movl CS (% ESP), % eax17. Andl $3, % eax18. pushl % eax19. Call do_timer20. Andl $4, % ESP21. JMP ret_from_sys_call From 1 to 7 behavior-based stack operation, this is what we care about! 16-18 is to apply CPL (CPL = cs 3) to the stack for the do_tiemr (long CPL) function. So what about the stack when it is executed into do_timer? Let's see: | Return address |-------

Cainiao compilation 003 code segment register CS and instruction pointer register IP

8086cpu starts from memory m x 16 + N Units, reads and executes a command. 10. Modify the commands for CS and IP addresses. Most 8086cpu registers can be changed using mov commands. mov commands are calledTransfer command The mov command cannot modify the Cs or IP value because 8086cpu does not provide such a function. Commands that can change the content of CS and IP registers are calledTransfer Instruction. A simplest command that can modify the value of CS and IP registers:

Search for OEP for cracking [manual shelling] (2)

1. Use the ESP Law After the OD is loaded, right-click the ESP content in the register window (for example, 0012ffa4) at F8 once, and choose "follow in the data window" to go to the memory data window, display the memory data window in the form of Hex data. Right-click the address starting position (for example, 0012ffa4) and choose "breakpoint"> "Hardware access"> "word ", f9 runs directly. If it is F8 again or twice, the code push EBP is usually used. The address of this Code is OEP. 2. Secon

Program Cracking Practice

instruction and corresponding machine code:NOP : The NOP instruction is the "null instruction". When executing to the NOP instruction, the CPU does nothing, just as an instruction to execute the past and continue executing a command behind NOP. (Machine code: 90)JNE : Conditional transfer directives, if not equal, jumps. (Machine code: 75)JE : The conditional transfer instruction, if equal, jumps. (Machine code: 74)JMP : Unconditional transfer instruc

Program Cracking Practice

instruction and corresponding machine code:NOP : The NOP instruction is the "null instruction". When executing to the NOP instruction, the CPU does nothing, just as an instruction to execute the past and continue executing a command behind NOP. (Machine code: 90)JNE : Conditional transfer directives, if not equal, jumps. (Machine code: 75)JE : The conditional transfer instruction, if equal, jumps. (Machine code: 74)JMP : Unconditional transfer instruc

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