This section describes how to use Google map on Android phones. We generally use Google map API + location API, that is, map API + status API, if we add some server and network knowledge, we can create very creative applications, and these are the popular lbs, the main technologies involved include map API + status API
technical. You just need to look at the examples. pay more attention to your ideas.
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1 // Initialize Map 2 Function Initmap (){ 3 VaR Lng = 1, 126.657717 ; 4 VaR Lat =
Assuming that Python does not provide a map () function, the My_map () function is programmed to implement the same functions as map (). The following code is implemented in Python 2.7.8. Implementation code: def my_map (Fun,num):i = 0x = list (len (num)) #创建一个list, length is the length of the input listFor n in Num: #对输入list中每个变量进行遍历X[i] = Fun (n) #调取fun函数, and returns the result in Xi = i+1Return x# retur
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I'm sure you will ask why this is the case or what is the difference with Android 2.2. here we need to explain that the Google API type will contain maps. jar is a jar package related to Google Maps. This function is supported in the project or in AVD. Otherwise, an error is returned.
[Problem 1] I tried it myself and found maps. jar in my local installation directory: D: \ Android-SDK-Windows \ add-ons \ addon_google_apis_google_inc_8 \ libs.
Th
setautolocateviewport () interface. This is the most important interface in this example and is used for actual locating. Here, you only need to obtain the longitude and latitude information and mark the geographical location of the visitor on the Google map. The Code is as follows:
// The following code implements the setautolocateviewport () Interface
// Set the map center to the Current Visitor Location
is as follows:
-(Insert point)-1;
Insert pointIndicates the position of the first element greater than the search object in the array. If all the elements in the array are smaller than the objects to be searched, the "insert point" is equal to the size () of the queried array ().
If the array contains repeated elementsWhich one cannot be found?. This algorithm is indeed not designed for arrays containing duplicate elements, but is still available.
If
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