kilobyte megabyte

both 2, which indicates that the image operation is performed on two physical disks. 1. view the rootvg size. # Lsvg rootvgVolume group: rootvg IDENTIFIER: 00f9150300004c0000000145634ba48dVg state: active pp size: 1024 megabyte (s)Vg permission: read/write TOTAL PPs: 1116 (1142784 megabytes)MAX LVs: 256 FREE PPs: 199 (203776 megabytes)LVs: 13 USED PPs: 917 (939008 megabytes)OPEN LVs: 12 QUORUM: 1 (Disabled)TOTAL PVs: 2 vg descriptors: 3STALE PVs: 0

Run-Time System and Virtual Machine A run-time system consists of an execution engine, a machine-level debugger, A assembler, and related development tools). Standard Operation Procedure (SOP): declares a proposition for demonstration and provides examples. That is, proposition-proof-example. This topic is suitable for System Engineers. Virtual machines must meet the following three criteria:1) portabilityPortability is the most important feature. It allows applications to work on consis

of binary numbers, which is generally an 8-bit binary number as a numerical unit in a computer. For example, an ascii code is a byte. The conversion of such units is:1 gib (TB, terabyte) = 1024 gib (40 to the power of 2)(1 TB = 1024 GB)1 gib (GB, gigabyte) = 1024 MB (2 to the power of 30 bytes)(1 GB = 1024 MB)1 MB (megabyte) = 1024 kilobytes (20 to the power of 2)(1 MB = 1024kb)1024 bytes (kb, kilobyte) =

BYTE (byte) is B: A byte is made up of 8-bit binary digits (1 byte = 8 bit). Byte is the most common base unit in the information store. An English letter (case-insensitive) occupies a byte of space, a Chinese character occupies two bytes of space.Symbol: English punctuation 2 is a byte, Chinese punctuation is two bytes. A binary numeric sequence, as a digital unit in a computer, typically a 8-bit binary number,If an ASCII code is a byte, the conversion of such units is: 1000 gigabyte (tb,kil

Function Get folder Sizefunction Getdirsize ($dir){$handle = Opendir ($dir);while (false!== ($FolderOrFile = Readdir ($handle))){if ($FolderOrFile!= "." $FolderOrFile!= "..."){if (Is_dir ("$dir/$FolderOrFile")){$sizeResult + + getdirsize ("$dir/$FolderOrFile");}Else{$sizeResult + + filesize ("$dir/$FolderOrFile");}}}Closedir ($handle);return $sizeResult;} Unit Automatic conversion functionfunction Getrealsize ($size){$KB = 1024; Kilobyte$MB = 1024 *

1bit=1 bit 2 binary information 1B (byte byte)1KB (kilobyte KB) =2 (Ten) b=1024b=2 (ten) B;1MB (Megabyte MBytes) =2 (Ten) kb=1024kb=2 B; equivalent to the content of a short story.1GB (Gigabyte gigabytes) =2 (mb=1024mb=2) B; the equivalent of a short story.1TB (Trillionbyte) =2 (gb=1024gb=2) B; equivalent to the music content of Beethoven's fifth movement Symphony.1PB (Petabyte) =2 (tb=1024tb=2) B; the equi

equals 8 bits (1byte=8bit). Eight-bit binary number minimum is 00000000, the maximum is 11111111; usually 1 bytes can be stored in an ASCII code, 2 bytes can hold a Chinese character GB code.3, the wordWhen a computer is processing data, the length of time it accesses, processes, and transmits is called word. A word is usually made up of one or more bytes (usually the integer bits of bytes). For example, the word 286 microcomputer consists of 2 bytes, its word length is 16;486 microcomputer's w

Practice a bit,Take your time and watch it slowly.SHOW WARNINGS;SELECT from String_tbl;SELECT CONCAT ('Danke sch'CHAR(148'n');SELECT ASCII ('o');SELECT from String_tbl;SELECT POSITION ("is" in from String_tbl;SELECT (PNS* (8*6));SELECT MOD (10,4);　　 select POW (2 , 10 ) kilobyte, POW (2 , 20 ) megabyte, -> POW (2 , 30 ) gigabyte, POW (2 , 40 ) terabyte; SELECT ROUND (72.09091ROUND(72.09092ROUND(72.09

install dump-y # dump: Incremental backup and differential backup are supported, and only individual partitions can be backed up #0: Full backup # U: update/etc/dumpdates # F: backup name [root @ serv01 data] # cd/backup/[root @ serv01 backup] # lslost + found [root @ serv01 backup] # rm-RF lost + found /# first view, dumpdates has no content [root @ serv01 backup] # ls/etc/dumpdates # backup [root @ serv01 backup] # dump-0 UF data01.dump/data/dump: date of this level 0 dump: Fri Aug 2 18:57:53

You may rarely face this situation, but once so, you must know what is wrong: insufficient memory or out-of-memory (OOM ). The result is very typical: you cannot reallocate the memory, and the kernel will kill a task (usually the one running ). Generally, with a large amount of read/write switching, you can see the screen and disk movements. The following is an implicit question: How much memory do you need to allocate? How much does the operating system allocate to you? The basic reason for OOM

-ROM). Though a CD-RW disc can be erased and written again, character CD players and other equipment generally perform better with CD-R media ( Always check if a CD player supports CD-RW before you buy it ). A standard CD-RW is 120 in diameter and usually comes with a capacity of either 640 MB or 700 mb. A CD-RW will store 74 or 80 minutes of CD audio, but as mentioned, is much less compatible with CD players than CD-R. Using software solutions suchNero burning Rom, At-home users can create au

completed. -U: record this backup to the/etc/dumpdates file. -V: displays the dump file process. -J: added support for bzip2 to compress data. The default compression level is 2. -Level: Backup grade 0 ~ 9 -F: Backup File -W: List whether the partitions with dump settings have been backed up in/etc/fstab. Example 1: Mount backup to/boot file system level-0 [Root @ localhost ~] # Dump-S/boot16752640 [root @ localhost ~] # Dump-u-0-f/root/boot. dump.0/boot DUMP: Date of this level 0 dump: Fri F

View existing VG # lsvgrootvgoravgdatavg view the usage status of each VG # lsvgoravg focuses on several values PPSIZE: 512 megabyte (s) View existing VG # lsvg rootvg oravg datavg view the status of each VG # lsvg oravg focuses on several values pp size: 512 megabyte (s) View existing VG # Lsvg Rootvg Oravg Datavg View the usage status of each VG # Lsvg oravg Focus on several values Pp size: 512

23G 92M 23G 1%/home/dev/sda5 497M 213M 284M 43%/BOOTTMPFS 37 3M 28K 373M 1%/run/user/0/dev/sda3 976M 2.6M 907M 1%/run/media/root/myfileView the space required for backup/DEV/SDA3 [[email protected] tartest]# dump-s/dev/sda353248For backup, back up to/root/boot.dump file,/run/media/root/myfile can also be written/dev/sda3[[email protected] tartest]# dump-0u-f/root/ Boot.dump/run/media/root/myfile Dump:date of this level 0 Dump:thu June 15:42:53 Dump:dumping/dev/sda3 (/run /media/root/myfile) To/

command on the existing system dump, the dump is not considered to be the latest one. Errpt error E87EF1BE Solution E87EF1BE 0926082807 p o dumpcheck The largest dump device is too small.Information. It is determined that the lg_dumplv capacity for storing dump files is insufficient. Generally, the recommended dump device value is 1.5 times the sysdumpdev-e value.The steps for resizing are as follows:1. view the estimated lg_dumplv size.# Sysdumpdev-e0453-041 Estimated dump size in bytes:

[Android Notes] Android calculates the folder size, deletes all files in the folder, and android notes 1. Get the folder size: 1/** 2 * Get the folder size 3 * @ param file File instance 4 * @ return long 5 */6 public static long getFolderSize (java. io. file file) {7 8 long size = 0; 9 try {10 java. io. file [] fileList = file. listFiles (); 11 for (int I = 0; I 2. Delete all files in the folder: 1/** 2 * Delete files and directories in the specified directory 3 * @ param deleteThisPath 4 * @

information Example : Full backup/ boot directory. [[Email protected]~]# dump-0uf/root/boot0.dump/bootDump:date of this level 0 Dump:mon 1901:02:33 2013DUMP:DUMPING/DEV/SDA1 (/boot) to/root/boot0.dumpDUMP:Label:noneDump:writing Kilobyte RecordsDump:mapping (Pass I) [Regular files]Dump:mapping (Pass II) [directories]dump:estimated 23349 blocks.Dump:volume 1 started with block 1 At:monaug 19 01:02:33 2013Dump:dumping (Pass III) [directories]Du

The JS code is as follows:var size = ' 8164674 '; function bytestosize (bytes) { ifreturn ' 0 B '; var // or 1024x768 sizes = [' B ', ' KB ', ' MB ', ' GB ', ' TB ', ' PB ', ' EB ', ' ZB ', ' YB '], = Math.floor (Math.log (bytes)/ Math.lo G (k)); return (Bytes/math.pow (k, i)). Toprecision (3) + "+ Sizes[i];} Console.log (Bytestosize (parseint (size)));SummarizeThe next two storage units are described: Bits, bytesBit: "Bit" is the smallest unit of data in an electronic c

. Job:counters:49file System Countersfile:number of bytes Read=162file:number of bytes Written=497579file:number of Rea D Operations=0file:number of large read operations=0file:number of write operations=0hdfs:number of bytes Read=233hdfs: Number of bytes Written=62hdfs:number of read Operations=12hdfs:number of large read Operations=0hdfs:number of write Operations=6job counterslaunched map tasks=1launched reduce tasks=3data-local map tasks=1total time spent by all maps in O Ccupied Slots (ms)

Hard disk is one of the important parts of the computer, not only expensive, stored information is priceless, therefore, each purchase of computer users want to choose a cost-effective, stable performance of a good hard drive, and in a period of time to meet their own storage needs. Speed, capacity and security are the three major factors that weigh hard drives. Bigger, faster, safer, cheaper is always the direction of hard disk development. The purchase of hard disk should first be considered f