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### Wuhan University of Science and Technology acm:1004: ChineseEdition C language Programming tutorial (second Edition) Exercise 5.6

Problem DescriptionThis day the teacher again to small Hao out a topic: give you three lengths, respectively, A,b,c match, let you calculate the three matches can make up of the Triangle area.InputEnter each row to include three number a,b,c.OutputThe area of the output triangle for each row (reserved three decimal places), cannot be composed of triangles told the small Hao output "no!".Sample Input1 2 33) 4 5Sample Outputno!6.000HINT1#include 2#include 3 intMain ()4 {5 Doubles,a,b,c,p;6

### Wuhan University of Science and Technology acm:1009: ChineseEdition C language Programming tutorial (second Edition) example 5.4

Problem DescriptionThe teacher gave a title to Xiao Hao: give you a value of n (within 32 bits) in seconds, let you convert to: minutes: seconds output. Now that little Howe is in a quandary, please help him solve the problem.InputEnter a positive integer of n seconds per line.Outputfor each set of test data, output a row of results: minutes: seconds. (24-hour system)Sample Input560Sample Output00:00:0500:01:00HINT#include intHh,mm,ss;voidConvertime (Longsec) {hh=sec/3600; MM= (sec-hh*3600L)/ -;

### Wuhan University of Science and Technology acm:1007: ChineseEdition C language Programming tutorial (second edition) Exercise 5.7

Problem DescriptionThis day the teacher gave small Hao a very simple topic relaxed: Enter a score, let you find their simplest score. InputThe first line includes a T, which represents the number of groups of test data.The next line of T lines includes a fraction. (The numerator denominator is within the int range)OutputFor each test sample, the output line has its simplest fraction.Sample Input32/63/111/36Sample Output1/33/111/36My Code:1#include 2ProcessintAintb/*greatest common divisor, so th

### Wuhan University of Science and Technology acm:1005: ChineseEdition C language Programming tutorial (second Edition) example 5.8

Problem DescriptionThe teacher gave a title to Xiao Hao: give you two integers x and n ( -10now that little Howe is in a quandary, please help him solve the problem. InputEnter two integers x and n per line.Outputfor each set of test data, the output line evaluates. Sample Input1 12 2Sample Output16HINT1#include 2 3 4 Long LongSumintXintN)5 {6 Long Longs=0;7 inti,j;8 Long LongS1;9 for(i=1; i)Ten { Ones1=1; A for(j=1; j) - { -s1*=x; the } -s+=S1; - } -

### Wuhan University of Science and Technology acm:1001: ChineseEdition C language Programming tutorial (second edition) Exercise 6.7

Problem DescriptionThe output Yang Hui the first n rows of the triangle.InputEnter a number n (n OutputThe output Yang Hui the first n rows of the triangle. (Note that there is no extra space at the end of the line, the number is output in%3d format)Sample Input34Sample Output 1 1 1 1 2 1 1 1 1 1 2 1 1 3 3 1HINTNote that there are multiple sets of inputs. Output a blank line after each set of test data.while (scanf ("%d", n)! = EOF){......}1#include 2 i

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### Wuhan University of Science and Technology acm:1009: ChineseEdition C language Programming tutorial (second edition) Exercise 6.11

Problem Descriptionn individuals in a circle, numbered from 1 to n sequentially. From the person numbered 1 starts 1 to K, where the number of people who count K out of the circle, the output of the last left a person's original numbers.InputFirst enter a T, which indicates that there is a T group of data (1Then there are t-lines, each with 2 positive integers n and K. (1OutputFor each set of test data, output a number that represents the number of the last person left.Sample Input310 37 15 4Sam

### Wuhan University of Science and Technology acm:1007: ChineseEdition C language Programming tutorial (second edition) Exercise 7.10

Problem DescriptionEnter n (nInputExample of multi-group test sample. The first row of each group has an integer n indicating that there are n strings. Next there are n rows, one string per line.OutputOutput a sequential string, with each line outputting a string.Sample Input3abaaabcabSample OutputAababacab1#include 2#include string.h>3 voidSortChar* str[],intsize)4 {5 inti,j;6 Char*tmp;7 for(i=0; i1; i++)8 {9 for(j=i+1; j)Ten { One if(strcmp (str[i]

### Wuhan University of Science and Technology acm:1001: ChineseEdition C language Programming tutorial (second Edition) after class exercise 3.12

Problem DescriptionEnter n, and the output corresponds to a hollow positive hexagon with a side length of N.For easy viewing, the sample midpoint '. ' Represents a space and prints a space instead of a small dot when plotting a drawing.InputEdge length N. (NOutputSide length is a positive hexagon of nSample Input5Sample Output.....*****....*.....*...*.......*.. *.........*.*...........*.. *.........*...*.......*....*.....*.....*****1#include 2#include 3 voidPrtCharCintcount)4 { 5 while(cou

### Wuhan University of Science and Technology acm:1006: ChineseEdition C language Programming tutorial (second edition) Exercise 7.15

Problem DescriptionEnter n strings (nInputMultiple sets of test data. The first row of each set of test data contains an integer n, representing a total of n strings. Next, each line contains a string that consists of printable characters.OutputEach set of test sample output one row. The output finds a string that satisfies the test instructions.Sample Input3djdlkfjsadfjwedlkfjdlkfjl;jf;sfjdsl;al/dljfd2dlkasfjmmlld;femflsad;fiwejdifSample OutputDlkfjdlkfjl;jf;sfjdsl;al/ld;femflsad;fiwejdif1#incl

### Wuhan University of Science and Technology acm:1009: ChineseEdition C language Programming tutorial (second Edition) example 4.18

Problem DescriptionVerify Goldbach conjecture that any even number of sufficiently large (>=4) can be represented by a sum of two primes.InputEnter an even n. (2OutputFind A, B make n=a+bWhere A and B are two primes, and aSample Input4100Sample Output2 23 971#include 2 3#include 4 5 using namespacestd;6 7 intPrimeintm)8 9 {Ten One intI,n; A - if(m==1)return 0; - theN= (int) sqrt (Double) m); - - for(i=2; i) - + if(m%i==0)return 0; - +

### Wuhan University of Science and Technology acm:1007: ChineseEdition C language Programming tutorial (second Edition) example 4.13

+ if((m%i==0) (n%i==0)) - \$ { \$ -printf"%d%d\n", i,m*n/i); - the Break; - Wuyi } the - } Wu - } About \$ } - -}Other code:1#include 2#include 3 intgcdintAintb)4 {5 if(a%b==0)6 returnb;7 Else8 returnGCD (b,a%b);9 }Ten intLcmintAintb) One { A returna

### Introduction to dora core 8 Simplified Chineseedition + multi-languageedition

After learning about Fedora core 8, I will explain Fedora core 8 to help you understand the Fedora system. Simplified Chinese version + multi-language version 9DVD + 3CD attached user manual product No.: PHA1A0010170049DVD-ROM + 3CD-ROM + 1 84 pages of this installation manual) + + 1 Registration Card + 90 days of technical support! This product has a serial number, fedora core 8 provides users with an unpr

### Java Core Technology Volume 1 basic Knowledge (original book 9th edition) (completeChinese version). Pdf__java

Download address: Network disk download Introduction to the content One of the most influential and valuable works in the Java field, with more than 20 years of experience in teaching and research of senior Java technology experts to write (won the Jolt Award), and "Java Programming ideas," the same as the more than 10-year global best-selling not decline, popular acclaim. The 9th edition is completely updated according to JavaSE7, at the same time c

### Java Help documentation full range JDK1.5 JDK1.6 JDK1.7 official Chinese-English completeedition _java

The JDK (Java Development Kit,java Development Kit, Java Development tool) is a program development environment that writes Java applets and applications. It consists of a running environment on the operating system level, as well as a developer compiling, debugging, and running the tools required for applets and applications written in the Java language.The JDK (Java Development Kit) is a product of the Sun Microsystems for Java developers. Since the launch of Java, JDK has become the most wide

### Wuhan University of Science and Technology acm:1003: ChineseEdition C language Programming tutorial (second Edition) example 6.6. Adaptation

Problem DescriptionWowapps most like to learn English, English class never skip class, but English has not been learned, because the class has been sleeping. Why do you sleep, because he thinks the English word is too long. Now Wowapps has a long, long, long word and wants to compress it. Can you help him?Compression: Replaces consecutive repeating letters with one, see sample for details.InputEnter an n first to indicate the number of words Wowapps give (1Next n lines, each behavior of a string

### Wuhan University of Science and Technology acm:1002: ChineseEdition C language Programming tutorial (second Edition) example 6.6

Problem DescriptionTomorrow will be the English exam, Wowapps is Midnight Oil recite the words. Wowapps found the word difficult to recite, the back one forget. After careful study, Wowapps found that the reason why the word is difficult to recite is because of the appearance of a character, destroying the beauty of the whole word, resulting in poor memory. Wowapps decided to destroy these discordant characters on behalf of the Moon!! (Applause!!) But the exam has entered the countdown, and Wowa

### Wuhan University of Science and Technology acm:1004: ChineseEdition C language Programming tutorial (second Edition) after class exercise 3.7

Problem DescriptionEnter an unsigned short integer k[hex.] and P[oct.], the high byte of K as the low byte of the result, and the high byte of p as the result of the high byte to form a new integer.InputK[hex.] and P[oct.]OutputThe operation gets the new integer n.Sample Input0XD9 01117Sample Output200HINTOutput is 16 binary1#include 2 intMain ()3 {4 5 intk,p;6 while(SCANF ("%x%o", k,p)! =EOF)7 {8 intNewint = (p0xff00)| (k0xff00) >>8;9printf"%x\n", newint);Ten }

### Wuhan University of Science and Technology acm:1009: ChineseEdition C language Programming tutorial (second edition) Exercise 5.12

Problem Descriptionthis day the teacher as a routine to small Hao out a topic: The teacher to small Hao a string, let small Hao will the string in reverse order output. InputThe first line includes a T, which indicates how many sets of test data are:Next T line, each line includes a string (length not exceeding 65535).OutputFor each test data output it's reverse string.Sample Input1oaHoaiX EvoL ISample OutputI Love Xiaohao1#include 2#include string.h>3 intMain ()4 {5 intL,i,n;6 Chara[655

### Wuhan University of Science and Technology acm:1008: ChineseEdition C language Programming tutorial (second edition) Exercise 6.14

Problem DescriptionEnter an octal string, convert it to an equivalent decimal string, and output it in the PRINGF%s format.InputFirst, a positive integer t is entered, indicating that there is a T set of test data (1Next T line, one string per line, representing an octal integer (this integer is no more than 20 bits).OutputFor each test data, output the corresponding decimal string. One line per string.Sample Input11732Sample Output986HINTNote: The given octal number may be large, with a long lo

### Perl Language Primer (Chinese Version) (6th edition) Southeast University Press

-programreturn valueParametersPrivate variables in sub-programsVariable-length parameter listImproved max sub-programEmpty argument listAbout lexical (my) variablesUse strict compilation instructionsreturn operatorEllipsis and numberNon-scalar return valuePersisting private variablesExercisesFifth chapter input and outputReading standard inputInput from the diamond operatorCalling parametersOutput to standard outputjnprintf formatted outputArrays and printfFile handleOpen File HandleRead and wri

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