lps ooak

Topic Portal1 /*2 Test instructions: One rabbit jumps clockwise, the other jumps counterclockwise, and the weight of the stones is equal and cannot cross the starting point .3 LPs: This is the application of LPs, the ring multiplied into a chain, a set of LPS, but do not understand dp[i][i+n-2] + 1, see other people's problem-solving report, to later fill (play t

1. Non-retention Ram/register:If the use of Ram/register itself in the Power-down state can not save its own state, then make sure that they will be in the power-up when the reset.2. Output signal of Power-down part circuit in chip:Power-down some of the output signals of the circuit can be used by other power-on parts of the circuit, then these signals must be processed. Avoid the X-value transmission to the power-on part of the circuit.There are three kinds of processing methods: latch (the va

: Wed Jul 30 2014 22:00:22-22:27:47 8 CPUs in system; running 1 parallel copyof tests Dhrystone 2 using register variables 27570040.0 lps (10.0 s, 7 samples) Double-Precision Whetstone 3041.3 MWIPS (6.5 s, 7 samples) Execl Throughput 1855.2 lps (30.0 s, 2 samples) File Copy 1024 bufsize 2000 maxblocks 816467.6 KBps (30.0 s, 2 samples) File Copy 256 bufsize 500 maxblocks 218024.2 KBps (30.0 s, 2 samples) Fil

E5-2630 0 @ 2.30 GHz (4600.0 bogomips) Hyper-Threading, x86-64, MMX, Physical Address Ext, SYSENTER/SYSEXIT, SYSCALL/SYSRET CPU 2: Intel (R) Xeon (R) CPU E5-2630 0 @ 2.30 GHz (4600.0 bogomips) Hyper-Threading, x86-64, MMX, Physical Address Ext, SYSENTER/SYSEXIT, SYSCALL/SYSRET CPU 3: Intel (R) Xeon (R) CPU E5-2630 0 @ 2.30 GHz (4600.0 bogomips) Hyper-Threading, x86-64, MMX, Physical Address Ext, SYSENTER/SYSEXIT, SYSCALL/SYSRET 08:21:32 up, 1 user, load average: 0.01, 0.02, 0.00; runlevel 3 ---

, Physical address Ext, Sysenter/sysexit, Syscall/sysret, Intel Virtualization CPU 1:intel (R) Xeon (r) CPU L5520 @ 2.27GHz (4533.6 bogomips) hyper-threading, x86-64, MMX, Physical address Ext, Sysenter/sysexit, Syscall/sysret, Intel Virtualization 09:41:17 up days, 9:21, 1 user, load average:0.23, 0.05, 0.02; RunLevel 3 ------------------------------------------------------------------------Benchmark Run:mon June 29 2013 09:41:17-10:09:292 CPUs in System; Running 1 parallel copy of tes

Laszlo development is divided into two branches: Endotoxin 2.2It is the main branch, with priority to stability and bug fixing. This is the direction of commercial recommendation, and this version does not support 3.0 features. Endotoxin 3.0Is a branch of the development version. The main feature of LPS 3.0 is that it does not depend on the server deployment mode, supports Unicode, integrates browsers, and adjusts the application size and speed. A

Problem: The longest palindrome subsequence of the given input string (the subsequence does not require continuous). LPs (I,J) is used to denote the length of the longest palindrome sequence from the string I character to the J character, the length of the string is N, and LPs (1,n) is required: LPS (I,J) = 0; i>j;

Given a string S, find the longest palindromic substring in s. The maximum length of S is assume, and there exists one unique longest palindromic substring.The longest palindrome, for each character from the middle to the sides of the search, attention to the odd and even two kinds of cases. The total time complexity is O (n^2). In addition Manacher algorithm complexity is O (n), the manacher algorithm is very complex appearance, IQ catch urgent, have to digest a bit. Put on a simple one first.1

/**/classpublicstaticint Maxlengthpalindrome (int//}Solution One:Implemtation is recursive, and it ' s much worse than O (n^2). Should use recursive with memorization and then can improve to O (n^2).However, recursive memorization doesn ' t improve over bottom-up and it had costly overhead. Bottom-up is better in this problem. Public classSolution { Public Static voidMain (string[] args) {intArr[] =New int[] {4,1,2,3,4,5,6,5,4,3,4,4,4,4,4,4,4}; System.out.println (arr, maxlengthpalindrome0, Arr.

Dhrystone 2 using register variables 187347382.3 LPS (10.0 s, 7 samples) double-precision whetstone 23772.5 mwips (10.0 s, 7 samples) execl throughput 21570.5 LPS (29.9 S, 2 samples) file copy 1024 bufsize 2000 maxblocks 352958.1 kbps (30.0 S, 2 samples) file copy 256 bufsize 500 maxblocks 98319.9 kbps (30.0 S, 2 samples) file copy 4096 bufsize 8000 maxblocks 907132.3 kbps (30.0 S, 2 samples) pipe throughpu

throughput 1 2 3 4 5 6 7 8 9 101 X pipe-based Context Switching 1 2 3 4 5 6 7 8 9 101 x Process Creation 1 2 x System call Overhead 1 2 3 4 5 6 7 8 9 1 X Shell Scripts (1 concurrent) 1 2 x Shell Scripts (8 concurrent) 1 2 3=========================================== ============================= BYTE UNIX Benchmarks (Version 5.1.3) system:test-vm001:gnu/linux Os:gnu/linux--3. 10.0-514.el7.x86_64--#1 SMP Tue Nov 16:42:41 UTC machine:x86_64 (x86_64) Language:en_US.utf8 (charmap= "UTF -8 ", coll

.x86 _ 64 -- #1 SMP Mon Sep 22 19:06:58 UTC 2014Machine: x86_64 (x86_64)Language: en_US.utf8 (charmap = "UTF-8", collate = "UTF-8 ")CPU 0: Intel (R) Xeon (R) CPU X5650 @ 2.67 GHz (5331.8 bogomips)X86-64, MMX, Physical Address Ext, SYSENTER/SYSEXIT, SYSCALL/SYSRET, Intel virtualization alization08:24:54 up 1 day, 1 user, load average: 0.00, 0.01, 0.05; runlevel 3------------------------------------------------------------------------Benchmark Run: Wed Nov 12 2014 08:24:54-08:52:531 CPU in system;

8 9 10 1 x Shell Scripts (1 concurrent) 1 2 3 1 x Shell Scripts (8 concurrent) 1 2 3 ======================================================================== BYTE UNIX Benchmarks (Version 5.1.2) System:localhost.localdomain:gnu/linux Os:gnu/linux--3.10.0-123.8.1.el7.x86_64--#1 SMP Mon Sep 19:06:58 UTC 2014 Machine:x86_64 (x86_64) Language:en_US.utf8 (charmap= "UTF-8", collate= "UTF-8") CPU 0:intel (R) Xeon (r) CPU X5650 @ 2.67GHz (5331.8 bogomips) x86-64, MMX, Physical address Ext, Sy

available volume groups Datavg03 Datavg02 Datavg01 Datavg00 Rootvg 2. perform the following operations on the volume group used for database preparation: # Lsvg-l datavg03 Datavg09: Lv name type LPs PPs PVs LV STATE MOUNT POINT Lvdata0316 raw 64 64 1 open/syncd N/ Lvdata0317 raw 64 64 1 open/syncd N/ Lvdata0318 raw 64 64 1 closed/syncd N/ Lvdata0319 raw 64 64 1 closed/syncd N/ Lvdata0320 raw 64 64 1 closed/syncd N/ Lvdata0321 raw 64 64 1 closed/syncd

] >= dp[i][j-1]) {Dp[i][j] = dp[i-1][J]; PRE[I][J] =1; }Else{Dp[i][j] = dp[i][j-1]; PRE[I][J] =2; } } }}voidPrint (intIintJ//Backtracking output a new string sequence{if(i = =0 J = =0)return;if(Pre[i][j] = =0) {Print (I-1, J-1);printf("%c", s1[i-1]); }Else if(Pre[i][j] = =1) {Print (I-1, j);printf("%c", s1[i-1]); }Else{Print (i,j-1);printf("%c", s2[j-1]); }}voidSolveChar*S1,Char*S2) {len1 =strlen(S1); Len2 =strlen(S2); LCS (S1,S2); Print (LEN1,LEN2);printf("\ n");}Longest palindrome

if(!source | |!target)return-1; A intm = strlen (source), n =strlen (target); - if(!n)return 0; -vectorint> lps =kmpprocess (target, n); the for(inti =0, j =0; I m;) { - if(Source[i] = =Target[j]) { -i++; -J + +; + } - if(j = = N)returnIJ; + if(I Target[j]) { A if(j) J = lps[j-1]; at Elsei++; -

, # mklv-y wolflv-t jsf rootvg 10 wolflv # lsvg-l rootvgrootvg: lv name type LPs PPs P. Vs lv state mount POINThd5 boot 1 2 2 closed/syncd N/Ahd6 paging 12 24 2 open/syncd N/Ahd8 jfs2log 1 2 2 open/syncd N/Ahd4 jfs2 45 90 2 open /syncd/hd2 jfs2 7 14 2 open/syncd/usrhd9var jfs2 1 2 2 open/syncd/varhd3 jfs2 20 40 2 open/syncd/tmphd1 jfs2 1 2 open/syncd/homehd10opt jfs2 1 2 open/syncd/opthd11admin jfs2 1 2 2 open/syncd/admindzytest jfs 2 4 2 open/syncd/d

:00c164fe00004c0000000110a1021713.66 Permission:read/write VG State:active/complete LV STATE:OPENED/SYNCD TYPE:JFS WRITE Verify:off MAX lps:512 PP size:256 megabyte (s) Copies:1 SCHED Policy:parallel Lps:10 pps:10 Stale pps:0 BB policy:relocatable Inter-policy:minimum Relocatable:yes Intra-policy:middle UPPER bound:16 MOUNT point:n/a Label:none MIRROR WRITE consistency:on/active Each LP COPY on A

pp belonging to lv01 from hdisk0 to hdisk1 to create VG and create VG using PV. Use hdisk2 # mkvg-y mqvg- d 6-s 8 hdisk2mqvg is VG name, -d 6 indicates a maximum of six physical volumes. The-s 8 pp value is 8 MB, and the physical volume value is hdisk2. # Lspvhdisk0 kernel rootvg activehdisk1 00cb45e500864dcc None hdisk2 kernel mqvg active other related commands # lsvg-l vgname view lv contained in vg # lsvg-p vgname view pv contained in vg # chvg-ay vgname automatically activates vg when the s

Hardware environment: minicomputer IBM p670, storage: IBM shark F-20 Software environment: Operating System aix5.1 database Oracle9i Theme: physical volume PV-> volume group VG-> logical Volume LV (type: Raw)-> Add tablespace Procedure: I. First, # lsvg-O // view all available volume groups Datavg03 Datavg02 Datavg01 Datavg00 Rootvg 2. perform the following operations on the volume group used for database preparation: # Lsvg-l datavg03 Datavg09: LV name type