SelectQ1.productname, (Q2.m1 Power (2, orderdate) * salevolume as M1, (Q2.m2 Power (2, orderdate) * salevolume as m2, (Q2.m3 Power (2, orderdate) * salevolume as m3, (Q2.m4 Power (2, orderdate) * salevolume as M4, (Q2.m5 Power (2, orderdate) * salevolume as M5, (Q2.m6 Power (2, orderdate) * salevolume as M6, (Q2.m7 Power (2, orderdate) * salevolume as M7, (Q2.m8 Power (2, orderdate) * salevolume as
Declare
@ D
Smalldatetime
Set
@ D
=
'
2004-7-1
'
Select
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Int
,
0
,
1
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As
I
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# T
From
Sysobjects
Select
Max
(M1)
As
M1,
Max
(M2)
As
M2,
Max
(M3)
As
M3,
Max
(M4)
As
M4,
Max
(M5)
As
M5,
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(M6)
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Simple Guide for porting Android kernel Author: Liu Xuhui colorant@163.com reprint please indicate the source http://blog.csdn.net/colorant/ transplanted Android kernel to the actual hardware platform, many people have done this for a long time, however, there are not many relevant documents and experience. Let me write one. I want to record the general process for myself and continue later.
1. background knowledge about Android kernel porting
1.1 operating platformGoogle Android platform until
;
typedef pair
Map
Map
M1[1] = 10;
M1[2] = 20;
M1[3] = 30;
Output 10 20 30, with line wrapping
for (itr1 = M1.begin (); itr1!= m1.end (); ++itr1)
{
cout
}
Map
Map
M2[1] = 10; Inserts an element with a key value of 1,value 10, Multimap does not support operator[]
M2.insert (Int_pair (2,20)); The valuetype of map is pair (T1,T2);
M2[3] = 30;
Output 30,20,10
for (ITR2 = M2.begin (); itr2!= m2.end (); ++itr2)
{
cout
}
Constructs a M3 using the M1 memory allocator
Map
Map
Copy a M4 according to M1
Tags: blog http using io strong data ar ArtSkilled use of various usage methods in SQL Server can bring a lot of convenience to queries. Let's introduce except and intersect today. Note This syntax is supported only for SQL Server 2005 and later version numbers.Except refers to the data that exists in the first collection, but does not exist in the second collection.Intersect refers to data that exists in two collections.Tests such as the following:CREATE TABLE t1 (ID int,mark char (2)) gocreate
affect system performance by reducing the number of available random access memory (RAM. You need to grant this permission to the user in the Local Security Policy Management Program, as shown in: ! F) S5 W' ^) W: t' G0 S X After assigning the preceding permissions to the user, you must use the code to enable the permissions in the program, as shown below: 7 K. F, P! M5 W $ H: W $]: T % Z: N "N) K6 J $ D6 K7 E: Y // Set the permission to lock the p
one time.
The next step is to find the longest ordered substring. Because the correct sequence is from small to large, the examples are started from the last one. Find the longest ordered sub-String Length MI after each number (including itself), and then find the maximum value in the most Mi, that is, the solution. View the following sequence:
No.
1 2 3 4 5 6 7 8 9 10
Sequence
5 8 3 7 6 1 9 2 10 4
AlgorithmThe procedure is as follows:
Durable is designed to prevent messages from being received in time due to exceptions such as downtime.
This has no significant impact on queue, but has a great impact on topics.
Reference
Http://activemq.apache.org/how-do-durable-queues-and-topics-work.html
Influence on queue
Durable queuesKeep messages around und persistently for any suitable consumer to consumeThem. Durable queues do not need to concern themselves with whichConsumer is going to consume the messages at some point in the futur
namespace STD;
Typedef pair
Map
Map
M1 [1] = 10;
M1 [2] = 20;
M1 [3] = 30;
// Output result 10 20 30 with line breaks
For (itr1 = m1.begin (); itr1! = M1.end (); ++ itr1)
{
Cout
}
Map
Map
M2 [1] = 10; // insert an element with a key value of 1 and a value of 10. multimap does not support operator []
M2.insert (int_pair (); // map valuetype is pair (T1, T2 );
M2 [3] = 30;
// Outputs 30, 20, 10
For (itr2 = m2.begin (); itr2! = M2.end (); ++ itr2)
{
Cout
}
// Use the memory distributor of M
. Net reflection (reflection) is very comprehensive and powerful, such as famous. net decompilation tool red gate's. net reflector is used. net reflection mechanism. Here is a simple instance (using the ConsoleProgram) To see how reflection is used in. net.
Using system;
Using system. reflection;
Namespace mengliao. CSHARP. c13.s02
{
Class myclass
{
Private int count;
Public myclass (INT value)
{
Count = value;
}
Public void M1 ()
nondurabilityTwo, persistent subscribers and non-persistent subscribers①durable subscribers and Nondurable subscribersFirst, the domain that persistent and non-persistent subscribers target is pub/sub, not peerWhen the broker sends a message to the subscriber, if the Subscriber is in the inactive state : The durable subscriber can receive the message, but not the persistent Subscriber.Similar to the QQ message, someone sent you offline messages, if the non-persistent subscribers will receive no
. CASE_INSENSITIVE); // after adding the attribute, Patter. CASE_INSENSITIVE indicates case-insensitive regardless of Matcher m4 = p4.matcher ("java_java_java_ilovejava fdasfas"); StringBuffer sb = new StringBuffer (); int I = 0; while (m4.find () {I ++; if (I % 2 = 0) {m4.appendReplacement (sb, "java");} else {m4.appendReplacement (sb, "JAVA");} m4.appendTail (sb ); // adding the tail to the buf is a combination of the following parameters: Word Group "); Pattern p5 = Pattern. compile ("(\ d {3
------------------------------ // static method f is not available for subclass of the parent class. m6 (); // output the static method of the parent class // some subclasses of the parent class also have static method f. m3 (); // outputs the static method of the parent class. // The member method f is not included in the subclass of the parent class. m2 (); // outputs the member methods of the parent class // some subclasses of the parent class also have member Methods f. m1 (); // output the
address of the double is divisible by 8, so C is padded with 8 bytesDouble D; 8} m2; 24struct MYSTRUCT3//start address can be divisible by 8{Short A; 2Char b; 6//By the same token, the starting address of the subsequent element must be divisible by 8, so B takes 6Double C; 8int D; 8//You need to populate some bytes afterwards to ensure that each array element satisfies the start address constraint after the array is allocated} m3; 24struct MYSTRUCT4{Char A; 2//Can be divisible by 4 after addres
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