machine learning exercises

Analytical:Two categories: Each classifier can only divide the samples into two categories. The prison samples were warders, thieves, food-delivery officers, and others. Two classifications certainly won't work. Vapnik 95 proposed to the basis of the support vector machine is a two classification classifier, this classifier learning process is to solve a positive and negative two classification derived fro

how to properly deal with training data and problems. Remember in the last lecture we have introduced the definitions and differences between bias and variance, and here we look at their production environment: Bias:j (train) Large, J (CV) Large, J (train) ≈j (CV), bias produced in D small, underfit stage; Variance:j (train) Small, J (CV) Large, J (train) To ensure that the bias is small, it is necessary to ensure that there are enough feature, that is linear/logistics regression many paramet

Learning C language for exercises, learning C Language exercises Open two files and let the program print the first line of the first file, the first line of the second file, the second line of the first file, and the second line of the second file, so on, until the last line of the file with a large number of lines is

[Introduction to machine learning] Li Hongyi Machine Learning notes-9 ("Hello World" of deep learning; exploring deep learning) PDF Video Keras Example application-handwriting Digit recognition Step 1

IntroductionThe systematic learning machine learning course has benefited me a lot, and I think it is necessary to understand some basic problems, such as the category of machine learning algorithms.Why do you say that? I admit that, as a beginner, may not be in the early st

descriptions are not written in order except for the first goal definition in Makefile. Make just adds a table entry to the dependency table and does not delete it. In principle, it is not guaranteed to be built in the order of the dependent tables, and if you need a goal to be built before another goal, you need to explicitly describe the dependency. Http://blog.codingnow.com/2008/09/replacement_of_ide_3.html 　　"Part3" This should be a divine act (zuō) When I waited for MinGW to do

Python learning-stage Comprehensive Exercises 2. python Comprehensive Exercises Based on the previous class learning, do the following example exercises: (do not read the code first, and try to write the code first. The code is for reference only. There are multiple implemen

Python learning-stage comprehensive exercises 3. python Comprehensive ExercisesPython learning-comprehensive phase Exercise 3 Based on the previous class learning, do the following example exercises: operations that contain folders and files (do not read the code first, and

Objective:When looking for a job (IT industry), in addition to the common software development, machine learning positions can also be regarded as a choice, many computer graduate students will contact this, if your research direction is machine learning/data mining and so on, and it is very interested in, you can cons

Preface: "The foundation determines the height, not the height of the foundation!" The book mainly from the coding program, data structure, mathematical theory, data processing and visualization of several aspects of the theory of machine learning, and then extended to the probability theory, numerical analysis, matrix analysis and other knowledge to guide us into the world of

This column (Machine learning) includes single parameter linear regression, multiple parameter linear regression, Octave Tutorial, Logistic regression, regularization, neural network, machine learning system design, SVM (Support vector machines Support vector machine), clust

TopicDescribe:输入2个数字，最后输出2个数字的最大公约数Topic Category:Difficulty:Run time limit:无限制Memory Limit:无限制Stage:Input:2个整数Output:输出数字1和2的最大公约数Sample input:2 3Sample output:1Code/* ---------------------------------------* Date: 2015-07-05* sjf0115* title: Greatest Common Divisor * Source: Huawei Machine Test Exercises---------------------- -------------------*/#include #include using namespace STD;//Greatest common div

TopicDescribe:请一个在字符串中找出连续最长的数字串，并把这个串的长度返回；如果存在长度相同的连续数字串，返回最后一个连续数字串；注意：数字串只需要是数字组成的就可以，并不要求顺序，比如数字串“1234”的长度就小于数字串“1359055”，如果没有数字，则返回空字符串（“”）而不是NULL！Sample inputabcd12345ed125ss123058789abcd12345ss54761Sample output输出123058789，函数返回值9输出54761，函数返回值5Function Prototypes: unsignedint Continumax(char** pOutputstr, char* intputstr)Input parameters: char* intputstr 输入字符串；Output parameters: char** pOutputstr: 连续最长的数字串，如果连续最长的数字串的长度为0，应该返回空字符串；如果输入字符串是空，也应该返回空字符串； return value: 连续最长的数字串的长度Pr

TopicDescribe:输入一个整形数组。数组中连续的一个或多个整数组成一个子数组，每个子数组都有一个和。求所有子数组的和的最大值。InterfaceInt GetSubArraySum（Int* pIntArray，Int nCount）；Specifications要求时间复杂度为O(n)Example例如输入的数组为1, -2, 3, 10, -4, 7, 2, -5，和最大的子数组为3, 10, -4, 7, 2，因此输出为该子数组的和18Practice Stage:Code/* ---------------------------------------* Date: 2015-07-05* sjf0115* title: The maximum and * source of the Subarray: Huawei Machine Test Exercises--------------

TopicCode/* ---------------------------------------* Date: 2015-07-05* sjf0115* Title: Object Manager * Source: Huawei Machine Test Exercises----------------------- ------------------*/#include #include "ObjMgt.h"#include using namespace STD;structobject{unsigned intKey1;unsigned intKey2;unsigned intKey3; Object (unsigned intAunsigned intBunsigned intc) {key1 = A; Key2 = b; Key3 = C; } Object () {

TopicDescribe:找出1至n之间同构数的个数。同构数是这样一组数：它出现在平方数的右边。例如：5是25右边的数，25是625右边的数，5和25都是同构数。Detailed Description:Interface descriptionPrototype:intSearchSameConstructNum(int n);Input parameters:int n：查找1至n之间的全部同构数return value:int：1至n之间同构数的个数Practice Stage:Code/* ---------------------------------------* Date: 2015-07-05* sjf0115* title: Find the number of isomorphic numbers * Source: Huawei Machine Test Exercises-----

TopicDescription: Topic title:求某二进制数中1的个数。给定一个unsigned int型的正整数，求其二进制表示中“1”的个数，要求算法的执行效率尽可能地高。Detailed Description:Prototype:int GetCount(unsigned int num)Input parameters: num 给定的正整数Output parameters (the memory area pointed to by the pointer is guaranteed to be valid):无return value:返回1的个数举例：输入13，则对应的二进制是1101，那么1的个数为3个。则：返回3。Practice Stage:初级 Code/* ---------------------------------------* Date: 2015-07-03* sjf0115* title: Number of 1 in a binary number * Source: Huawei

Topic描述: 详细描述：N个人围坐在一个圆桌上，顺时针报数，报数的初始值为第一个人设置。当有成员报出的数字为7的倍数或数字中包含7，则该人退出圆桌，而后由下一个人开始重新继续该游戏。实现以下接口： 1、设定输入原始的圆桌游戏的人数。以最先开始报数的人编号为1，顺时针排序。 2、设定第一个人的初始值，获取按照规则退出圆桌的人的编号。 3、结束游戏。样例:比如初始化为4人的游戏：第1轮初始值为1，退出为3；第2轮初始值为4，退出为4号；第三轮初始值为16，退出为2号；第四轮初始值为6，退出为1号；练习阶段: 中级 Code/* ---------------------------------------* Date: 2015-06-31* sjf0115* title: Roundtable game * Source: Huawei Machine Test Exercises-----

//while return 0;}Code twoTimeout/* ---------------------------------------* Date: 2015-06-30* sjf0115* title: Integer delimited * Source: Huawei on-Machine--------------------------- --------------*/#include #include #include #include using namespace STD;#define MAX 1000000intSplit (intN) {if(n = =1){return 1; }//if if(n = =2){return 2; }//if //Odd if(n%2){returnSplit (n1) %1000000000; }//if Else{returnSplit (n2) %1000000000+ Split (n/

[Huawei machine trial exercise questions] 14. Separated by integers, Huawei exercises Question Description: an integer can be divided into the sum of the power of 2. For example: 7 = 1 + 2 + 47 = 1 + 2 + 2 + 27 = 1 + 1 + 1 + 47 = 1 + 1 + 1 + 2 + 27 = 1 + 1 + 1 + 1 + 1 + 1 + 27 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 there are six different splitting methods. For example, 4 can be split into 4 = 1 + 1 + 1 + = 2 + =