magic square 4x4

JavaScript to solve the third-order magic square Puzzle: Third-order magic Square, try to fill in a 3x3 table with the 1~9 9 different integers, making the sum of the numbers on each row, each column, and each diagonal. Strategy: Exhaustive search. Lists all the integer fill schemes, and then filters them. The brigh

Time limit per test 2 secondsMemory limit per test 256 megabytesInput Standard InputOutput Standard output Little elephant loves magic squares very much. A magic square is a 3 hour x hour 3 table, each cell contains some positive integer. At thatThe sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the

#-*-Coding:utf-8-*-#利用numpy模块构造幻方Import NumPyAs NP#列表循环向左移offset位DefShift_left(LST, offset):return [lst[(I+offset)%len (LST)]For IIn range (len (LST))]#列表循环向右移offset位DefShift_right(LST, offset):return [Lst[i-offset]For IIn range (len (LST))]#构造奇数阶幻方函数DefMagic_of_odd_order(n):p = (int) (N-1)/2)#创建矩阵1Initial_lst1 = List (range (p+1,n)) +list (range (p+1))INITIAL_MAT1 = []For IIn range (n):Initial_mat1.append (Shift_left (Initial_lst1, i))MAT1 = Np.array (INITIAL_MAT1)#创建矩阵2Initial_lst2 = List (ran

This paper illustrates the method of realizing the odd-order magic square in C language. Share to everyone for your reference. The implementation methods are as follows: Copy Code code as follows: #include "stdio.h" #include "string.h" #include "Stdlib.h" #define N 5 void Main () {int a[n][n]={0};int i,j;int k; i = 0;j = N/2;A[0][j]=1;for (k = 2; k if (i = = 0 J = = N-1) {//First, deter

DescriptionIn a square consisting of several neatly arranged numbers, the sum of the numbers of any row, line, and diagonal in the graph is equal, and a chart of this nature is called the magic square. It has been determined that the N-Order magic Square (n>=3) can construct

Magical Magic SquareTitle DescriptionMagic Square is a very magical n*n matrix: It is composed of digital three-way,......, n*n, and the sum of the numbers on each row, column, and two diagonal lines are the same.When n is an odd number, we can construct a magic square by the following methods:First write 1 in the midd

Anti-Magic Square China's ancient books are very early records 2 9 4 7 5 3 6 1 8 This is a third-order magic square. Each row and the number on the diagonal are added equally. Consider one of the opposite questions below. You can not fill Hu Ci sudoku with 1~9 numbers. So that the numbers on each diagonal of ea

H-Fantastic phalanxTime Limit: 1000 msDescriptionThe magic is to place the number from 1 to N2 in a n * n matrix. Each number appears only once andFor each row, the sum of each column and its diagonal line is the same.The focus of this problem is the odd magic square, which means that N is an odd number. You will use the following method to constructThe most basi

Puzzles Third-order magic square. Try to fill in a 3x3 table with these 9 different integers, making the sum of the numbers on each row, each column, and each diagonal 1~9. Strategy Exhaustive search. Lists all the integer fill schemes, and then filters them. JavaScript solution Copy Code code as follows: /** * Created by Cshao on 12/28/14. */ function Getpermutation (arr) {

simulation has always been the NOIP must test a type of question is also the most simple type of questions generally speaking, this problem takes the least time and should try to take the most points, so as my "Noip real Problem" series of the first article on first say a simulation problem Topics① Toy Puzzle "Noip Improvement Group" 2016d1t1 [difficulty]0.8 [tag]② Magical Magic Square "Noip raise Group" 20

Magic Square is also known as Rubik's Cube, square squares or halls. In a square consisting of a number of neatly arranged numbers, the sum of the numbers of any one row, one longitudinal line, and the diagonal is equal, and a chart of this nature, called Magic