merge two sorted linked list in c

Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.To facilitate header processing, add the dummy head node to the L1 and insert the nodes on the L2 into the L1.1ListNode *mergetwolists (ListNode *l1, ListNode *L2)2 {3ListNode

Title Description:Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.Problem Solving Ideas:and autonomous methods. The K list is continuously decomposed into the first and second halves. Merging of two lists is performed separately. Finally, the merged results are merged t

Topic:Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.Translation:Connect 2 ordered linked lists and return a new linked listIdeas:It is simple to iterate over each node, and the small words are added behind the new list. If one

Merges a K-linked list.Idea: Merge the list 22 first until you merge it into only one linked list1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 classSolution {Ten Public: Onelistnode* mergeklists (vectorlists) {

Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.This problem is similar to the add two numbers, noting that there are unequal lengths, and considering the use of dummy node as the result of the head element, the time complexity

TopicMerge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.AnalysisDon't forget to first determine whether the list of two lists is empty. The rest can be implemented using both recursive and non-recursive methods.CodeRecursive mode:C

Merge k sorted linked lists and return it as one sorted list. analyze and describe its complexity. the solution to merging k sorting lists is to extract k elements for heap sorting. Each time the smallest elements are extracted, you can insert them into the linked list to no

Problem Description: Given a two-linked list of head pointers, and both linked lists are already in order, the two linked lists are merged into a list, and the merged list is still orderly.Analysis: This problem is somewhat similar to the merge step in merge sort. Specific i

;next=p; P=p->Next; R=r->Next; } Else{R->next=Q; Q=q->Next; R=r->Next; } } if(p!=NULL) R->next=p; if(q!=NULL) R->next=Q; returnhead;}"Other Code"ListNode *mergetwolists (ListNode *l1, ListNode *L2) {ListNode*helper=NewListNode (0);// pay attention here! Switching to ListNode *helper=null is not feasible ListNode*head=Helper; while(L1 L2) { if(L1->valNext; ElseHelper->next=l2,l2=l2->Next; Helper=helper->Next; } if(L1) helper->next=L1; if(L2) helper->next=L2; retur

Problem descriptionMerge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.AlgorithmCode One1 PublicListNode mergetwolists (listnode l1,listnode L2) {2 if(l1==NULL)3 returnL2;4 if(l2==NULL)5 returnL1;6 ListNode l3,p;7 if(l1.vall2.va

MergeKSorted linked lists and return it as one sorted list. analyze and describe its complexity. Answer /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */public class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode

List of classes:class ListNode{ int key; ListNodenext; }Ideas: This and the array are different, do not need to use a double pointer, from the back to come Code: Recursivepublicmerge(ListNode head1,ListNode head2){ ifnull){ return head2; }elseifnull){ return head1; } null; if(head1.key else{ node = head2; node.next =

God and everyone make different jokes. [Problem description] Merge two sorted linked lists and return it as a new list. The new list shoshould be made by splicing together the nodes of the first two lists. [Solutions] You can add a new header pointer. It is relatively simple to