merge two sorted linked list in c

Original title Link: http://oj.leetcode.com/problems/merge-two-sorted-lists/ This topic is relatively simple, classic linked list basic operation. Maintaining the two pointers corresponds to two linked lists, because it is generally based on a linked list, such as L1, then if the L1 of the element is relatively small

ListNode Class (Node Class)1 Packageleetcode.utilities;2 3 Public classListNode {4 Public intVal;5 PublicListNode Next;6 PublicListNode (intval) {7 //TODO auto-generated Constructor stub8 This. val =Val;9 This. Next =NULL ; Ten } One //Print linked list A Public Static voidprintlist (ListNode head) { -System.out.println ("Prinylist start"); -ListNode Pnode =head; theSystem.out.print ("{")

The title describes the input of two monotonically increasing lists, the output of the list of two linked lists, of course, we need to synthesize the linked list to meet monotonic rules. Using recursion: Find the smallest head node in 2 linked lists, and the combined list head node is the smallest head node. The merge

Title Description input Two monotonically increment list, output two list of linked lists, of course, we need to synthesize the list to meet the monotone non-reduction rule solution 1: non-recursive solution1 classSolution {2 Public:3listnode* Merge (listnode* pHead1, listnode*pHead2)4 {5 if(!phead1 !phead

Title Description: Combine the list of K-sorted lists into a sort of chain table Ideas: Use the heap sort, traverse the list, and place the value of the head pointer of the linked list and the head pointer itself as an element in the heap; After traversing the

Title: Enter two incrementally sorted lists, merge the two linked lists, and make the nodes in the new list continue to be sorted in ascending order. The linked list is defined as follows:struct listnode{int m_nvalue; Listnode* M_pnext;};Analysis: The problem is a lot of poi

title :Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.code : OJ online test via runtime:208 ms1 #Definition for singly-linked list.2 #class ListNode:3 #def __init__ (self, x):4 #self

Title Description:Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.Problem Solving Ideas:The title means to synthesize an ordered list of two ordered linked lists.Add to the new list b

The topics are as follows: Merge K sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Analysis: When you think about it for the first time, it's more natural. Intend to follow the idea of merging sort. Each time, select the smallest one in the K element. The minimum time complexi

ability to analyze the problem (whether the formation of a very clear thinking, pointer operation Proficiency) and the candidate can write strong code. Java code: Import Java.io.ioexception;import Java.io.StreamTokenizer; public class Main {public static void main (string[] args) throws IOException {//TODO auto-generated Method St UB Streamtokenizer stin = new Streamtokenizer (system.in); int m, n,value; while (Stin.nexttoken ()! = streamtokenizer.tt_eof) {m = (int) s

Title: Enter two incrementally sorted lists, merge the two linked lists, and make the nodes in the new list continue to be sorted in ascending order. For example, the list of links in the input graph 1 and linked List 2, the

1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 Ten structHelper { OneListNode *head; A intLen; -Helper (ListNode *h,intl): Head (h), Len (l) {} - }; the - classhelpercmp { - Public: - BOOL operator() (ConstHelper a,ConstHelper b) { + returnA.len >B.len; - } + }; A at classSolution { - Public: -Priority_queueHeap; - -I