microsoft ignite cost

every year, Microsoft will have a technology event, which will be held in many countries, his name is called " TechED", the most recent TechED I attended was the one in which I had previously published several conference records in 51CTO, such as http.// jiushu.blog.51cto.com/972756/1085347. However, I believe that the Chinese students will find thatTechED2014 disappeared, in fact, can not be said to disappear, but this time, the Chinese region Tech

10.26-10.28 was honored to attend the first Ignite China Technical Conference held by Microsoft in Beijing. The world is so big, so much technology, I want to see it.A three-day technical conference in the small Tangshan nine Huashan Zhuang held, spit trough a bit, tete is far away, every day to run more than 30 kilometers to the venue." technology innovation to help the Internet + times " as the theme, the

It is fortunate to have participated as MVP in this annual Microsoft China Technical Conference (Ignite). Jumping out of the technical field, this meeting gave me the greatest feeling is attitude. In recent years, whether it is open source technology, or the release of black technology, people feel that Microsoft is becoming cool, but cool is not necessarily popu

Article Title: Microsoft's Linux embedded development cost PK. Linux is a technology channel of the IT lab in China. Includes basic categories such as desktop applications, Linux system management, kernel research, embedded systems, and open source. With the increasing complexity of embedded system development, the development cost is also increasing. Therefore, it is of great significance for embedded vend

N*n Matrix Cost:m in a direction graph, the maximum number of nodes that can be traversed such as a can have 0->1->2->0->1 cost: 2+2+3+2=9#include using namespacestd;intMain () {intn=3;intm=Ten; inta[][3]={{0,2,3},{4,0,2},{3,4,0}}; intlast_step[3]; intdist[3][3]; for(intI=0; i) { for(intj=0; j) {Dist[i][j]=A[j][i]; } } for(intI=0; ii;} intmax=0; for(intstep=1; step-max1; step++){ for(intj=0; j){ intMin=int_max;i