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C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100

C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100Calculate

Implemented in C: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value.

To get this topic, we will first think of using loops to complete.But not every operator is a "+" sign.Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.The loop variable i is then treated as the denominator.Here we have the idea of the loop body is basically OK.It is important to note that the calculation results here are expressed in decimals, so it is not possible to define variables with int integers.The code is as foll

The "C language" calculates the value of 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100.

Note: When calculating 1 to use a double type that is 1.0 . Odd even numbers are calculated separately and then merged. #include Label control +1,-1 with flag. #include Use the Function Pow Pow ( -1,i+1) equivalent ( -

Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... + 1/n!], While

Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... +

Algorithm: 1! + (1!) +3! ) + (1!) +3! +5! + (1! + 3! + 5! + 7! + 9!) + .... + (1!) +3! +5! + ... + m!)

-(void) Touchesbegan: (nonnull nssetAlgorithmic entry[Self func2:9];}Calculate factorial factor (m) = m!-(int) factor: (int) m{int factornum=0;if (m==0|m==1)return 1;else{Factornum=m*[self Factor:m-1];NSLog (@ "%d", factornum);return factornum;}}Calculate Func1 (m) = 1! +3!

C language: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Be careful to define its type, divide it into two parts, and define it as "I" to see if the denominator is an odd or even number, and the sum is summed. C language: Calculate 1/1-1/2+1/3-1/4+

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... + 1/n ., Even number

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... +

Minecraft Source code Analysis (1)-Spawn logic

counted only once, so the more dispersed the player, the more chunks will be overwritten and will have higher biomass capacity.The capacity is checked at the beginning of each build cycle. If the number of surviving organisms exceeds its capacity, the entire generation cycle is skipped.In each build cycle, an attempt is made to generate a set of mobs in each of the appropriate chunks. Select a random location within the block as the central point of this set of mobs. To generate this set of mob

Find out e=1+1/1!+1/2!+1/3!+......+1/n!+ ... The approximate value of Java applet program

Program//Find out e=1+1/1!+1/2!+1/3!+......+1/n!+ ... The approximate value, the request error is less than 0.0001import java.applet.*;import java.awt.*;import java.awt.event.*;p ublic

C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation

C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation Method 1: for Loop Im

1/1! + 1/2! + 1/3! +... + 1/N !...... Deep feelings

This is an interesting one. I just learned it when I went to school.C LanguageWhen I started my first lesson on data structure, the teacher gave me the following question:Use programming: 1/1! + 1/2! + 1/3! +... + 1/n!Then I thoug

Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1/n! (N is a large number. If n is too large, it will overflow)

/*************************************** ************************Accumulated (C language)AUTHOR: liuyongshuiDATE :************************************************ ***********************//*Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1

Computing 1 + 1/3 + 1/5 +... + 1/(2n + 1) Value

The while loop is required and must be calculated to 1/(2n + 1) Public class dowhiledemo{Public static void main (string ARGs []){Int n = 1;Double dsum= 1.0, dtemp;Do{N = 2 * n + 1;Dtemp = 1.0/N; // is critical. If 1.0 is written as an integer 1, the calculation result is

Formula for calculating pi pai: Pai = 4* (1-1/3+1/5-1/7 ...)

There are many formulas for calculating pi pai in history, in which Gregory and Leibniz found the following formula: Pai = 4* (1-1/3+1/5-1/7 ...) The formula is simple and graceful, but in a bad way, it converges too slowly. If we rounded to keep its two decimal digits,

Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30

Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30 public class Mainthread {private static int num;//current record number private static final int threadnum

Java uses the while loop to calculate 1 + 1/2! + 1/3 !...... + 1/20!

Write a program and use the while statement to calculate 1 + 1/2! + 1/3 !...... + 1/20 !, And output the computing results in the control of Taishan. Requirement 1 + 1/2! +

Java uses while loop to calculate 1+1/2!+1/3!...... +1/20!

1 Public Static voidMain (string[] args) {2 Doublen = 1, sum = 0;3 while(N ) {4sum + = 1/factorial (n);5n++;6 }7 System.out.println (sum);8 9 }Ten One Static DoubleFactorial (Doublem) { A if(m = = 1 | | m = = 0) { - return1; -}Else { the return(M * Fact

Using a while loop to compute 1+1/2!+1/3!+...+1/20!

Package practice; /* Use while loop to compute 1+1/2!+1/3!+...+1/20! A is used to store one of the first n factorial points sum is used to accumulate and/or public class Whiledemo {The public static void main (string[] args) {/*i=i+1

Use the do-while statement to calculate 1 + 1/2 + 1/3 +... + 1/20 results (tasks on the computer in week 10)

/** Copyright (c) 2011, School of Computer Science, Yantai University * All Rights Reserved. * file name: test. CPP * Author: Fan Lulu * Completion Date: July 15, October 29, 2012 * version number: V1.0 ** input Description: none * Problem description: computing and output 1 + 1/2 + 1/3 +... +

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