2^X mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 13341 Accepted Submission (s): 4143Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exists, print a line with 2^x mod n = 1.Print 2
2^x mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others) total submission (s): 12605 Accepted Submission (s): 3926Problem DescriptionGive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.InputOne positive integer on each line, the value of N.OutputIf the minimum x exists, print a line with 2^x mod n = 1.Print 2^
Take the remainder function PHP to take the remainder function PHP two to take the remainder MOD (x, y) x%y
MOD
For example: 9/3,9 is the divisor, 3 is the divisor. The MoD function is a redundancy function in the form of:MoD (NEXP1,NEXP2), which is the remainder of two numeric expressions after the division operation. So: The two integers are the same as you kn
Time Limit: 2 seconds memory limit: 65536 KB
Give a number N, find the minimum X that satisfies 2 ^ x mod n = 1.
Input
One positive integer on each line, the value of N.
Output
If the minimum x exists, print a line with 2 ^ x mod n = 1.
Print 2 ^? MOD n = 1 otherwise.
You shoshould replace X and N with specific numbers.
Sample Input
25
S
1046 a^b mod C reference time limit: 1 seconds space limit: 131072 KB score: 0 Difficulty: Basic collection attention gives 3 positive integers a B C, for A^b Mod c. For example, 3 5 8,3^5 Mod 8 = 3. Input3 positive integers a B C, separated by a space in the middle. (1 OutputOutput calculation resultsInput example3 5 8Output example3Related questions x^a
Hello minecraft! How does launcher install mod? believe that the first time to use the Hello minecraft! starter friends have this question, the following three small series to bring Hello minecraft! The launcher installs the MoD the picture and text tutorial, hoped can help you!
The MoD installation tutorial
Step one: Click on the game settings to find
Hello minecraft! How does launcher install mod? believe that the first time to use the Hello minecraft! starter friends have this question, the following three small series to bring Hello minecraft! The launcher installs the MoD the picture and text tutorial, hoped can help you!
The MoD installation tutorial
Step one: Click on the game settings to find
Yesterday, when learning the mathematical functions of MATLAB, the tutorial mentions that modulo (MoD) and take-rest (REM) is different, today on the Web specifically checked:
Usually the modulo operation is called the rest operation, and they return the result as a remainder. The only difference between REM and mod is:When x and Y are the same sign, two function results are equal, and when the X and Y symb
Calculation Method of a * B mod C
Method 1:
Everyone can think of it. Calculate the value of a * B and then calculate the value of a * B mod C. This is the simplest, but there is a drawback: the value of a * B cannot be too large and may overflow.
Method 2:
Review the knowledge of hexadecimal conversion. Binary Conversion to hexadecimal can be added with the weight of 2 (which seems to be described in this
Recently, our new VPS customers have suddenly increased and we don't know where our friends are from. Maybe a forum mentioned our VPS, as long as you hear the cry of "tutorial", you can feel this eagerness from the other side of the earth. Installing Nginx on Linux, MySQL, PHP (also known as LNMP) is a line of command, and there is no need for any "tutorial". Even if you need a google/baidu tutorial, you can find the ghost, there is no need to "ask" again. For example, install Nginx, MySQL, and
2^X mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 14349 Accepted Submission (s): 4438Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exists, print a line with 2^x mod n = 1.Print 2
The program will not execute $ runnew $ mod (); it will not be executed! Why $ modisset ($ _ GET [m])? Ucfirst ($ _ GET [m]): Index; by default, the upper-case letter of the issetucfirst () of the Index function is loaded. $ mod. quot; Action quot; $ runnew $ mod (); $ ru program is not executed $ run = new $ mod ();
The program will not execute $ run = new $ mod (); it will not be executed! Why does $ mod = isset ($ _ GET ['M'])? Ucfirst ($ _ GET ['M']): 'index'; // by default, the Index function issetucfirst () is loaded with an upper-case letter $ mod. = quot; Action quot: The program is not executed $ run = new $ mod (); it i
/* (X * C + a) % (2 ^ K) = B → (x * C) % (2 ^ K) = B-A satisfies the theorem: inference 1: The equation Ax = B (mod n) has a solution for the unknown x. if and only when gcd (A, n) | B. Inference 2: The equation Ax = B (mod n) or there are d different solutions to the modulus n, where D = gcd (A, n), or no solution. Theorem 1: Set d = gcd (A, n). Assume that the integers x and y meet d = AX + by (for exampl
/*2 ^ x mod n = 1Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 11800 accepted submission (s): 3673Problem descriptionGive a number N, find the minimum x (x> 0) that satisfies 2 ^ x mod n = 1.
InputOne positive integer on each line, the value of N.
OutputIf the minimum x exists, print a line with 2 ^ x mod n
Finally, I got this question... I watched it for half a week. The number of questions accumulated in the competition is decreasing... Come on!
Digit DP. f [I] [Sum] [mod] [res] indicates the first I bit, sum, Mod, sum % mod, and Res. F [I + 1] [Sum + k] [mod] [(RES * 10 + k) % mod
1046 a^b mod C reference time limit: 1 seconds space limit: 131072 KB score: 0 Difficulty: Basic collection attention gives 3 positive integers a B C, for A^b Mod c. For example, 3 5 8,3^5 Mod 8 = 3. Input3 positive integers a B C, separated by a space in the middle. (1 OutputOutput calculation resultsInput example3 5 8Output example3Related issues x^a
This question requires the smallest positive integer x, N> 0 that satisfies 2 ^ x limit 1 (mod N.
First consider the Euler's Theorem 2 ^ Eular (n) limit 1 (mod N), which requires n> 1. So when n = 1, in fact, all K numbers have k limit 0 (mod N), which is a special decision.
In the Euler's theorem, Eular (n) must be cyclic, but not necessarily the smallest cy
2 ^ x mod n = 1
Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 11542 accepted submission (s): 3577
Problem descriptiongive a number N, find the minimum x (x> 0) that satisfies 2 ^ x mod n = 1.
Inputone positive integer on each line, the value of N.
Outputif the minimum x exists, print a line with 2 ^ x mod
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